1 / 9

Distance formula

gent
Download Presentation

Distance formula

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Lesson PlanFrom 1st dec. to 15th dec. 2013 Class 10 – A Subject: MathematicsNo. of periods in a week: 7Topics: Coordinate geometry Aim: To create interest in the subjectSpecific Aim:To make the students understand the need of coordinate geometryTomake the students understand the concept of distance formula and section formula and to apply the same in finding the distance between two points in a plane.

  2. Distance formula Suppose we want to find the distance between two cities without actually measuring them, we can graphically represent it as shown in the figure, We can use Pythagoras theorem to find the distance Y 15km X 36 km

  3. Now suppose we have two points on the x axis and y axis as shown in the figure The distance from B to A =6-4=2 The distance from D to C = 6-3 = 3 D 6 5 4 3 2 1 Here also we can apply the Pythagoras theorem to find the distance AC and BD C A B 0 1 2 3 4 5 6 7 8 9 10

  4. Q (8,6) 8 7 6 5 4 3 2 1 PQ2 = PT2 +QT2 (x2 – x 1)2 + (y2 - y 1)2 P (4,6 This is known as distance formula 1 2 3 4 5 6 7 8 9 10 11 12

  5. Q (x2,y2 8 7 6 5 4 3 2 1 Suppose we have a situation In which line AQ is divided in the ratio of m1 and m2 P (x,y) C x1, y1 B A R 1 2 3 4 5 6 7 8 9 10 11 12

  6. In ∆PAB~ PQC PA = AB = PB QP PC QC x -x1= y –y1 = m1 x2 –x y2 –y m2 Hence we can find the value of x and y x= m 1x 2+m 2x1 m 1+m2 y= m 1 y2 + m 2y1 m 1+m2

  7. A • Similarly the area of the triangle can be found by using distance formula C B Q P R Area of a triangle ABC = Area of trapezium ABQP + Area of trapezium APRC- Area of trapezium BQRC

  8. Summary In this chapter we have dealt with the following • The distance formula • The section formula • Area of triangle using distance formula.

  9. Assignment Exercise 7.1 and 7.2 will be given and some extra questions will be given as worksheet.

More Related