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Randomized Algorithms. William Cohen. Outline. SGD with the hash trick (review) Background on o ther randomized algorithms Bloom filters Locality sensitive hashing. Learning as optimization for regularized logistic regression. Algorithm:
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Randomized Algorithms William Cohen
Outline • SGD with the hash trick (review) • Background on other randomized algorithms • Bloom filters • Locality sensitive hashing
Learning as optimization for regularized logistic regression • Algorithm: • Initialize arrays W, A of size R andset k=0 • For each iteration t=1,…T • For each example (xi,yi) • Let Vbe hash table so that • pi = … ; k++ • For each hash value h: V[h]>0: • W[h] *= (1 - λ2μ)k-A[j] • W[h] =W[h] + λ(yi- pi)V[h] • A[j] = k
Learning as optimization for regularized logistic regression • Initialize arrays W, A of size R andset k=0 • For each iteration t=1,…T • For each example (xi,yi) • k++; let V be a new hash table; let tmp=0 • For each j: xi j >0: V[hash(j)%R] += xi j • Let ip=0 • For each h: V[h]>0: • W[h] *= (1 - λ2μ)k-A[j] • ip+= V[h]*W[h] • A[h] = k • p = 1/(1+exp(-ip)) • For each h: V[h]>0: • W[h] =W[h] + λ(yi- pi)V[h] regularize W[h]’s
An example 2^26 entries = 1 Gb @ 8bytes/weight
A variant of feature hashing • Hash each feature multiple times with different hash functions • Now, each w has k chances to not collide with another useful w’ • An easy way to get multiple hash functions • Generate some random strings s1,…,sL • Let the k-th hash function for w be the ordinary hash of concatenation wsk
A variant of feature hashing • Why would this work? • Claim: with 100,000 features and 100,000,000 buckets: • k=1 Pr(any duplication) ≈1 • k=2 Pr(any duplication)≈0.4 • k=3 Pr(any duplication)≈0.01
Hash Trick - Insights • Save memory: don’t store hash keys • Allow collisions • even though it distorts your data some • Let the learner (downstream) take up the slack • Here’s another famous trick that exploits these insights….
Bloom filter interface • Interface to a Bloom filter • BloomFilter(intmaxSize, double p); • void bf.add(Strings); // insert s • boolbd.contains(Strings); • // If s was added return true; • // else with probability at least 1-p return false; • // else with probability at most p return true; • I.e., a noisy “set” where you can test membership (and that’s it)
Bloom filters • Another implementation • Allocate M bits, bit[0]…,bit[1-M] • Pick K hash functions hash(1,s),hash(2,s),…. • E.g: hash(s,i) = hash(s+ randomString[i]) • To add string s: • For i=1 to k, set bit[hash(i,s)] = 1 • To check contains(s): • For i=1 to k, test bit[hash(i,s)] • Return “true” if they’re all set; otherwise, return “false” • We’ll discuss how to set M and K soon, but for now: • Let M = 1.5*maxSize// less than two bits per item! • Let K = 2*log(1/p) // about right with this M
Bloom filters • Analysis: • Assume hash(i,s) is a random function • Look at Pr(bit j is unset after n add’s): • … and Pr(collision): • …. fix m and n and minimize k: k =
Bloom filters • Analysis: • Plug optimal k=m/n*ln(2) back into Pr(collision): • Now we can fix any two of p, n, m and solve for the 3rd: • E.g., the value for m in terms of n and p: p =
Bloom filters • An example application • Finding items in “sharded” data • Easy if you know the sharding rule • Harder if you don’t (like Google n-grams) • Simple idea: • Build a BF of the contents of each shard • To look for key, load in the BF’s one by one, and search only the shards that probably contain key • Analysis: you won’t miss anything…but, you might look in some extra shards • You’ll hit O(1) extra shards if you set p=1/#shards
Bloom filters • An example application • discarding singleton features from a classifier • Scan through data once and check each w: • if bf1.contains(w): bf2.add(w) • else bf1.add(w) • Now: • bf1.contains(w) w appears >= once • bf2.contains(w) w appears >= 2x • Then train, ignoring words not in bf2
Bloom filters • An example application • discarding rare features from a classifier • seldom hurts much, can speed up experiments • Scan through data once and check each w: • if bf1.contains(w): • if bf2.contains(w): bf3.add(w) • else bf2.add(w) • else bf1.add(w) • Now: • bf2.contains(w) w appears >= 2x • bf3.contains(w) w appears >= 3x • Then train, ignoring words not in bf3
Bloom filters • More on Thursday….
LSH: key ideas • Bloom filter: • Set represented by a small bit vector • Can answer containment queries fairly accurately • Locality sensitive hashing: • map feature vector xto bit vectorbx • ensure that bxpreserves “similarity” of the original vectors
Random projections u - + + - - + + - - + - + + - + - - + -u 2γ
Random projections Any other direction will keep the distant points distant. u - + - + - + + - - + + - - + + - - + So if I pick a random r and r.xand r.x’ are closer than γ then probably x and x’ were close to start with. -u 2γ
Random projections To make those points “close” we need to project to a direction orthogonal to the line between them u + - + - + - + - - + - + + - + - - + -u 2γ
Random projections Put this another way: when is r.x>0 and r.x’<0 ? u + - + - + - - + + - - + + - + - - + -u
Random projections some where in here is ok r.x’ < 0 u + - - + + - + - - + r.x > 0 + - + - + - - + -u
Random projections r.x’ < 0 u + - + - - + - + + - r.x > 0 + - + - + - + - -u some where in here is ok
Random projections Claim: r.x’ < 0 u + - - + + - - + + - r.x > 0 + - - + + - + - -u some where in here is ok
Some math Pick random vector r, define Claim: So: And:
LSH: key ideas • Goal: • map feature vector xto bit vectorbx • ensure that bxpreserves “similarity” • Basic idea: use random projections of x • Repeat many times: • Pick a random hyperplaner • Compute the inner product or r with x • Record if x is “close to” r (r.x>=0) • the next bit in bx • Theory says that is x’ and x have small cosine distance then bxand bx’ will have small Hamming distance • Famous use: near-duplicate web page detection in AltaVista (Broder, 97)
LSH: key ideas • Naïve algorithm: • Initialization: • For i=1 to outputBits: • For each feature f: • Draw r(f,i) ~ Normal(0,1) • Given an instance x • For i=1 to outputBits: LSH[i] = sum(x[f]*r[i,f] for f with non-zero weight in x) > 0 ? 1 : 0 • Return the bit-vector LSH • Problem: • you need many r’s to be accurate • storing these is expensive • Ben will give us more ideas Thursday
Finding neighbors of LSH vectors • After hashing x1,…,xnwe have bx1, … bxn • How do I find closest neighbors of bxi? • One approach (Indyk & Motwana): • Pick random permutation p of bits • Permute to bx1, … bxnget bx1p, … bxnp • Sort them • Check B closest neighbors of bxipin that sorted list, and keep the k closest • Repeat many times • Each pass finds some close neighbors of every element • So, can do single-link-clustering with sequential scans