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CSC 3315 Programming Paradigms Prolog Language

CSC 3315 Programming Paradigms Prolog Language. Hamid Harroud School of Science and Engineering, Akhawayn University http://www.aui.ma/~H.Harroud/csc3315/. Logic Programming Languages. Introduction A Brief Introduction to Predicate Calculus Predicate Calculus and Proving Theorems

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CSC 3315 Programming Paradigms Prolog Language

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  1. CSC 3315Programming ParadigmsProlog Language HamidHarroud School of Science and Engineering, Akhawayn University http://www.aui.ma/~H.Harroud/csc3315/

  2. Logic Programming Languages • Introduction • A Brief Introduction to Predicate Calculus • Predicate Calculus and Proving Theorems • An Overview of Logic Programming • The Origins of Prolog • The Basic Elements of Prolog • Deficiencies of Prolog • Applications of Logic Programming

  3. Introduction • Logic programming language or declarativeprogramming language • Express programs in a form of symbolic logic • Use a logical inferencing process to produce results • Declarative rather that procedural: • Only specification of results are stated (not detailed procedures for producing them)

  4. Proposition • A logical statement that may or may not be true • Consists of objects and relationships of objects to each other

  5. Symbolic Logic • Logic which can be used for the basic needs of formal logic: • Express propositions • Express relationships between propositions • Describe how new propositions can be inferred from other propositions • Particular form of symbolic logic used for logic programming called predicatecalculus

  6. Object Representation • Objects in propositions are represented by simple terms: either constants or variables • Constant: a symbol that represents an object • Variable: a symbol that can represent different objects at different times • Different from variables in imperative languages

  7. Compound Terms • Atomic propositions consist of compound terms • Compound term: one element of a mathematical relation, written like a mathematical function • Mathematical function is a mapping • Can be written as a table

  8. Parts of a Compound Term • Compound term composed of two parts • Functor: function symbol that names the relationship • Ordered list of parameters (tuple) • Examples: student(john) like(nick, windows) like(jim, linux)

  9. Forms of a Proposition • Propositions can be stated in two forms: • Fact: proposition is assumed to be true • Query: truth of proposition is to be determined • Compound proposition: • Have two or more atomic propositions • Propositions are connected by operators

  10. Logical Operators

  11. Quantifiers

  12. Clausal Form • Too many ways to state the same thing • Use a standard form for propositions • Clausal form: • B1  B2  …  Bn A1  A2  …  Am • means if all the As are true, then at least one B is true • Antecedent: right side • Consequent: left side

  13. Predicate Calculus and Proving Theorems • A use of propositions is to discover new theorems that can be inferred from known axioms and theorems • Resolution: an inference principle that allows inferred propositions to be computed from given propositions

  14. Resolution • Unification: finding values for variables in propositions that allows matching process to succeed • Instantiation: assigning temporary values to variables to allow unification to succeed • After instantiating a variable with a value, if matching fails, may need to backtrack and instantiate with a different value

  15. Proof by Contradiction • Hypotheses: a set of pertinent propositions • Goal: negation of theorem stated as a proposition • Theorem is proved by finding an inconsistency

  16. Theorem Proving • Basis for logic programming • When propositions used for resolution, only restricted form can be used • Horn clause - can have only two forms • Headed: single atomic proposition on left side • Headless: empty left side (used to state facts) • Most propositions can be stated as Horn clauses

  17. Overview of Logic Programming • Declarative semantics • There is a simple way to determine the meaning of each statement • Simpler than the semantics of imperative languages • Programming is nonprocedural • Programs do not state now a result is to be computed, but rather the form of the result

  18. Example: Sorting a List • Describe the characteristics of a sorted list, not the process of rearranging a list sort(old_list, new_list)  permute (old_list, new_list)  sorted (new_list) sorted (list) j such that 1 j < n, list(j)  list (j+1)

  19. The Origins of Prolog • University of Aix-Marseille • Natural language processing • University of Edinburgh • Automated theorem proving

  20. Terms • Edinburgh Syntax • Term: a constant, variable, or structure • Constant: an atom or an integer • Atom: symbolic value of Prolog • Atom consists of either: • a string of letters, digits, and underscores beginning with a lowercase letter • a string of printable ASCII characters delimited by apostrophes

  21. Terms: Variables and Structures • Variable: any string of letters, digits, and underscores beginning with an uppercase letter • Instantiation: binding of a variable to a value • Lasts only as long as it takes to satisfy one complete goal • Structure: represents atomic proposition functor(parameter list)

  22. Fact Statements • Used for the hypotheses • Headless Horn clauses female(shelley). male(bill). father(bill, jake).

  23. Rule Statements • Used for the hypotheses • Headed Horn clause • Right side: antecedent (if part) • May be single term or conjunction • Left side: consequent(then part) • Must be single term • Conjunction: multiple terms separated by logical AND operations (implied)

  24. Example Rules ancestor(mary,shelley):- mother(mary,shelley). • Can use variables (universalobjects) to generalize meaning: parent(X,Y):- mother(X,Y). parent(X,Y):- father(X,Y). grandparent(X,Z):- parent(X,Y), parent(Y,Z). sibling(X,Y):- mother(M,X), mother(M,Y), father(F,X), father(F,Y).

  25. Goal Statements • For theorem proving, theorem is in form of proposition that we want system to prove or disprove – goal statement • Same format as headless Horn man(fred) • Conjunctive propositions and propositions with variables also legal goals father(X,mike)

  26. Inferencing Process of Prolog • Queries are called goals • If a goal is a compound proposition, each of the facts is a subgoal • To prove a goal is true, must find a chain of inference rules and/or facts. For goal Q: B :- A C :- B … Q :- P • Process of proving a subgoal called matching, satisfying, or resolution

  27. Approaches • Bottom-up resolution, forward chaining • Begin with facts and rules of database and attempt to find sequence that leads to goal • Works well with a large set of possibly correct answers • Top-down resolution, backward chaining • Begin with goal and attempt to find sequence that leads to set of facts in database • Works well with a small set of possibly correct answers • Prolog implementations use backward chaining

  28. Subgoal Strategies • When goal has more than one subgoal, can use either • Depth-first search: find a complete proof for the first subgoal before working on others • Breadth-first search: work on all subgoals in parallel • Prolog uses depth-first search • Can be done with fewer computer resources

  29. Backtracking • With a goal with multiple subgoals, if fail to show truth of one of subgoals, reconsider previous subgoal to find an alternative solution: backtracking • Begin search where previous search left off • Can take lots of time and space because may find all possible proofs to every subgoal

  30. Simple Arithmetic • Prolog supports integer variables and integer arithmetic • is operator: takes an arithmetic expression as right operand and variable as left operand A is B / 17 + C • Not the same as an assignment statement!

  31. Example speed(ford,100). speed(chevy,105). speed(dodge,95). speed(volvo,80). time(ford,20). time(chevy,21). time(dodge,24). time(volvo,24). distance(X,Y) :- speed(X,Speed), time(X,Time), Y is Speed * Time.

  32. List Structures • Other basic data structure (besides atomic propositions we have already seen): list • Listis a sequence of any number of elements • Elements can be atoms, atomic propositions, or other terms (including other lists) [apple, prune, grape, kiwi] [](empty list) [X | Y](head X and tail Y)

  33. Append Example append([], List, List). append([Head | List_1], List_2, [Head | List_3]) :- append (List_1, List_2, List_3).

  34. Reverse Example reverse([], []). reverse([Head | Tail], List) :- reverse (Tail, Result), append (Result, [Head], List).

  35. Example: mylength mylength([],0).mylength([_|Tail], Len) :- mylength(Tail, TailLen), Len is TailLen + 1. ?- mylength([a,b,c],X).X = 3 Yes?- mylength(X,3).X = [_G266, _G269, _G272] Yes

  36. Counterexample: mylength mylength([],0).mylength([_|Tail], Len) :- mylength(Tail, TailLen), Len = TailLen + 1. ?- mylength([1,2,3,4,5],X).X = 0+1+1+1+1+1 Yes

  37. Example: sum sum([],0).sum([Head|Tail],X) :- sum(Tail,TailSum), X is Head + TailSum. ?- sum([1,2,3],X).X = 6 Yes?- sum([1,2.5,3],X).X = 6.5Yes

  38. Example: gcd gcd(X,Y,Z) :- X =:= Y, Z is X.gcd(X,Y,Denom) :- X < Y, NewY is Y - X, gcd(X,NewY,Denom).gcd(X,Y,Denom) :- X > Y, NewX is X - Y, gcd(NewX,Y,Denom). Note: not just gcd(X,X,X)

  39. The gcd Predicate At Work ?- gcd(5,5,X).X = 5 Yes?- gcd(12,21,X).X = 3 Yes?- gcd(91,105,X).X = 7 Yes?- gcd(91,X,7).ERROR: Arguments are not sufficiently instantiated

  40. Example: factorial factorial(X,1) :- X =:= 1.factorial(X,Fact) :- X > 1, NewX is X - 1, factorial(NewX,NF), Fact is X * NF. ?- factorial(5,X).X = 120 Yes?- factorial(20,X).X = 2.4329e+018 Yes?- factorial(-2,X).No

  41. Problem Space Search • Prolog’s strength is (obviously) not numeric computation • The kinds of problems it does best on are those that involve problem space search • You give a logical definition of the solution • Then let Prolog find it

  42. Item Weight in kilograms Calories bread 4 9200 pasta 2 4600 peanut butter 1 6700 baby food 3 6900 The Knapsack Problem • You are packing for a camping trip • Your pantry contains these items: • Your knapsack holds 4 kg. • What choice <= 4 kg. maximizes calories?

  43. Item Weight in kilograms Calories bread 4 9200 pasta 2 4600 peanut butter 1 6700 baby food 3 6900 Greedy Methods Do Not Work • Most calories first: bread only, 9200 • Lightest first: peanut butter + pasta, 11300 • (Best choice: peanut butter + baby food, 13600)

  44. Search • No algorithm for this problem is known that • Always gives the best answer, and • Takes less than exponential time • So brute-force search is used here • That’s good, since search is something Prolog does really well

  45. Representation • We will represent each food item as a term food(N,W,C) • Pantry in our example is[food(bread,4,9200), food(pasta,2,4500), food(peanutButter,1,6700), food(babyFood,3,6900)] • Same representation for knapsack contents

  46. The Knapsack Problem /*weight(L,N) takes a list L of food terms, N is the sum of all the Weights. */ weight([],0).weight([food(_,W,_) | Rest], X) :- weight(Rest,RestW), X is W + RestW./*calories(L,N) takes a list L of food terms, N is the sum of all the Calories. */ calories([],0).calories([food(_,_,C) | Rest], X) :- calories(Rest,RestC), X is C + RestC.

  47. The Knapsack Problem /* subseq(X,Y) succeeds when list X is the same as list Y, but with zero or more elements omitted.*/ subseq([],[]).subseq([Item | RestX], [Item | RestY]) :- subseq(RestX,RestY).subseq(X, [_ | RestY]) :- subseq(X,RestY). • A subsequence of a list is a copy of the list with any number of elements omitted • (Knapsacks are subsequences of the pantry)

  48. The Knapsack Problem ?- subseq([1,3],[1,2,3,4]).Yes ?- subseq(X,[1,2,3]).X = [1, 2, 3] ;X = [1, 2] ;X = [1, 3] ;X = [1] ;X = [2, 3] ;X = [2] ;X = [3] ;X = [] ;No Note that subseq can do more than just test whether one list is a subsequence of another; it can generate subsequences, which is how we will use it for the knapsack problem.

  49. The Knapsack Problem /* knapsackDec(Pantry,Capacity,Goal,Knapsack) takes a list Pantry of food terms, a positive number Capacity, and a positive number Goal. We unify Knapsack with a subsequence of Pantry representing a knapsack with total calories >= goal, subject to the constraint that the total weight is =< Capacity.*/knapsackDec(Pantry,Capacity,Goal,Knapsack) :- subseq(Knapsack,Pantry), weight(Knapsack,Weight), Weight =< Capacity, calories(Knapsack,Calories), Calories >= Goal.

  50. The Knapsack Problem ?- knapsackDec(| [food(bread,4,9200),| food(pasta,2,4500),| food(peanutButter,1,6700),| food(babyFood,3,6900)],| 4,| 10000,| X).X = [food(pasta, 2, 4500), food(peanutButter, 1, 6700)] Yes • This decides whether there is a solution that meets the given calorie goal

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