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2 x > - 8 and 2 x 5. Compound Linear Inequalities: Solving Algebraically . Example: Algebraically solve, - 5 < 2 x + 3 8. First break the compound inequality into two simple inequalities by writing it as: 2 x + 3 > - 5 and 2 x + 3 8.
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2x > - 8 and 2x 5 Compound Linear Inequalities: Solving Algebraically Example: Algebraically solve, - 5 < 2x + 3 8. First break the compound inequality into two simple inequalities by writing it as: 2x + 3 > - 5 and 2x + 3 8 The "and" means that only those numbers that satisfy both of the inequalities will be solutions of the original compound inequality. Next solve each simple inequality. x > - 4 and x 5/2
Try: Algebraically solve, Write the solution set in interval notation. Compound Linear Inequalities: Solving Algebraically x > - 4 and x 5/2 Numbers that satisfy both inequalities above are between -4 and 5/2 (including 5/2). The solution set can be written as a compound inequality, - 4 < x 5/2 or in interval notation as ( - 4, 5/2 ]. The solution set is [ - 7/4, 1/4]. Slide 2
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