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Chapter 6 TEST!. Wednesday, February 22, 2012. Review. Solve: |4x – 3| = 22. Review. If y = x 2 + x – 6 has solutions x = 2 and x = -3, then what are the solutions to y = (x + 4) 2 + (x + 4) – 6? . Review. Solve (x + 3) 2 = 25. Review.
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Chapter 6 TEST! Wednesday, February 22, 2012
Review • Solve: |4x – 3| = 22
Review • If y = x2 + x – 6 has solutions x = 2 and x = -3, then what are the solutions to y = (x + 4)2 + (x + 4) – 6?
Review • Solve (x + 3)2 = 25
Review • Complete the square to turn the equation into vertex form: y = x2 + 7x - 12
Review • Use quadratic formula to solve the following quadratic equation: 3x2 – 5x = x2 + 2
Review • Write the equation of the parabola congruent to y = 3x2 under the translation T 5, -3
Review • Put into a + bi form:
Review • Determine the nature of the solutions for the equation y = -2x2 + 5x + 7
Review • Simplify:
Review • Complete the Square: y = x2 – 9x + 2