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Other Effects of Interference

Other Effects of Interference We have considered interference between waves of the same frequency. But of course, that’s not always the situation…. Beats

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Other Effects of Interference

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  1. Other Effects of Interference We have considered interference between waves of the same frequency. But of course, that’s not always the situation…. Beats The phenomenon of sound beats is a simple, common example. This is an alternating rise and fall in the observed amplitude (which we hear as loudness) of the combined (superimposed) sound of two sources that are close, but not identical, in frequency. The lows and highs of the two functions occur together only periodically—just a few cycles per second—so that we can hear distinctly each combined high (constructive interference) or low (destructive interference). OSU PH 212, Before Class #25

  2. As it turns out: fpitch = ( f1 + f2 )/2 fbeats = |f1 – f2 | Musicians use this phenomenon regularly to tune their instruments: When trying to match a given pitch, they try to eliminate the beats; so long as they can still hear beats, they’re not yet in tune. Example: The lead oboe sounds an “A” note of exactly 440 Hz. When the second oboe then joins in with her “A,” it produces beats that pulse with a frequency of 1 Hz. If the second oboe could correct this by lengthening her instrument slightly (lowering her pitch), what frequency (pitch) was your ear hearing while you heard the 1 Hz beats? (see After class 25 for the solution) OSU PH 212, Before Class #25

  3. Standing Waves • Standing waves correspond to another simple kind of wave interference. • A standing wave is the combination of two identical traveling waves that are moving in opposite directions along the same portion of the same medium—usually as a result of reflection (or “echo.” • The two waves are identical except for the direction in which they are traveling. They have the same amplitude, wavelength, frequency and speed. OSU PH 212, Before Class #25

  4. Standing Waves Musical instruments use standing waves in solid materials or in air to generate musical tones of very reliable frequency (pitch). How? A standing wave occurs when many waves overlap due to reflections of the same disturbance in the same available space. The interference of all these reflected waves tend to cancel each other out except for waves that “fit the available space.” The reflections that don’t cancel each other out are those that would be completing a cycle or half-cycle (thus zero variation) anyway as they encounter the end of the available space. These reflect back in a “harmonized” way, reinforcing each other (i.e. forming constructive interference), increasing the amplitude of their sum at each point consistently. We hear this as resonance. OSU PH 212, Before Class #25

  5. How does the end of the available space govern the standing wave? It fixes the value of the wave function. For example, a guitar string is fixed at both ends. Its function (a transverse displacement) is thus forced to be zero at each end. We call such zero displacement a node in the standing wave. The guitar string is a good example of a transverse standing wave. What about a longitudinal standing wave—such as sound? OSU PH 212, Before Class #25

  6. In a longitudinal pressure wave (sound), the air particles are being displaced back and forth (along the axis of the wave travel)—and they are undergoing pressure variations, too. Both of these—displacement and pressure—vary sinusoidally, but it turns out that they “peak” and “dip” at different times. So when we analyze how the “end of the space” affects a longitudinal wave, we have to be careful about what wave we’re talking about—either the pressure (what we hear and measure as sound) or the displacement of the particles back and forth. Here’s how it works.… OSU PH 212, Before Class #25

  7. A pipe open at both ends fixes the air pressure at each end to be atmospheric pressure. This means that it can have no standing pressure variation at those ends. A pipe closed at one end fixes the air displacement to be zero at the closed end (and the standing pressure variation must still be zero at the open end). Now let’s summarize the requirements for resonance—for strings and for two kinds of pipes.… OSU PH 212, Before Class #25

  8. With two fixed ends, a string will have standing waves of displacement at certain frequencies, according to this formula: L = m(/2) or fn = mv/2L where m = 1, 2, 3 ... Each such resonant frequency is called a harmonic. The first harmonic (the fundamental frequency) is when m = 1; the second harmonic is when m = 2; etc. Nodes (points of zero displacement) will, of course, appear at the fixed ends. They will also appear at spaced intervals of /2 from those ends. Antinodes (points of maximum displacement) appear halfway between the nodes. OSU PH 212, Before Class #25

  9. With both ends open, a cylindrical pipe will have standing longitudinal waves of pressure and displacement at certain frequencies, according to the same formula: L = m(/2) or fm = mv/2L where m = 1, 2, 3 ... The nodes and antinodes? It depends which disturbance you’re looking at; displacement and pressure peak at different points. Displacementantinodes (points of maximum displacement) appear at the open ends and at spaced intervals of /2 from those ends. Displacement nodes (points of zero displacement) appear halfway between those antinodes. Pressure nodes (points of no pressure variation) appear at the open ends and at spaced intervals of /2 from those ends. Pressure antinodes (points of maximum pressure variation) appear halfway between those nodes. OSU PH 212, Before Class #25

  10. With just one end open, a cylindrical pipe will have standing waves of pressure and displacement at certain frequencies, with a different constraint: L = m(/4) or fm = mv/4L where m = 1, 3, 5 ... A pressure node (point of minimum pressure variation) will appear at the open end and at spaced intervals of /2 from that end. Pressure antinodes (points of maximum pressure variation) appear at the closed end and at spaced intervals of /2 from that end. A displacement antinode (point of maximum displacement) appears at the open end and at spaced intervals of /2 from that end. Displacement nodes (points of minimum displacement) appear at the closed end and at spaced intervals of /2 from that end. OSU PH 212, Before Class #25

  11. A string is clamped at both ends and plucked so it vibrates in a standing mode between two extreme positions a and b. Let upward motion correspond to positive velocities. When the string is in position c, the instantaneous velocities of points along the string… • A. …are zero everywhere. • B. …are positive everywhere. • C. …are negative everywhere. • D. …depend on location. OSU PH 212, Before Class #25

  12. A string is clamped at both ends and plucked so it vibrates in a standing mode between two extreme positions a and b. Let upward motion correspond to positive velocities. When the string is in position c, the instantaneous velocities of points along the string… • A. …are zero everywhere. • B. …are positive everywhere. • C. …are negative everywhere. • D.…depend on location. • The points everywhere within each loop (i.e. between each pair of nodes) are all moving in the same direction, but all points in the neighboring loop are moving the other way. OSU PH 212, Before Class #25

  13. Consider the possible standing waves that could exist on a6.00-m long stretched rope (fixed at both ends).a. What is the wavelength of the fourth harmonic frequency?b. If the fundamental frequency is 4.00 Hz., what is the speed of waves that travel along this string? • a. 2.00 m b. 72.0 m/s • a. 3.00 m b. 48.0 m/s • a. 4.00 m b. 36.0 m/s • a. 6.00 m b. 24.0 m/s • None of the above. OSU PH 212, Before Class #25

  14. Consider the possible standing waves that could exist on a6.00-m long stretched rope (fixed at both ends).a. What is the wavelength of the fourth harmonic frequency?b. If the fundamental frequency is 4.00 Hz., what is the speed of waves that travel along this string? • a. 2.00 m b. 72.0 m/s • a. 3.00 mb. 48.0 m/s • a. 4.00 m b. 36.0 m/s • a. 6.00 m b. 24.0 m/s • None of the above. Solutions: 4(l4/2) = L and 4 = (1)v/(2L) OSU PH 212, Before Class #25

  15. What is the wavelength of the second lowest frequency standing sound wave in a tube of length L that has one end open and the other closed? • 4L • 2L • L • 4L/3 • 2L/3 OSU PH 212, Before Class #25

  16. What is the wavelength of the second lowest frequency standing sound wave in a tube of length L that has one end open and the other closed? • 4L • 2L • L • 4L/3 • 2L/3 Solution: 3(l2/4) = L (m-values must be odd only.) OSU PH 212, Before Class #25

  17. The wavelength of the third harmonic on a stretched string is 10.0 cm while the frequency of the fourth harmonic is 480 Hz. What is the speed of the waves on this string? • 12.0 m/s • 36.0 m/s • 48.0 m/s • 60.0 m/s • 120 m/s OSU PH 212, Before Class #25

  18. The wavelength of the third harmonic on a stretched string is 10.0 cm while the frequency of the fourth harmonic is 480 Hz. What is the speed of the waves on this string? • 12.0 m/s • 36.0 m/s • 48.0 m/s • 60.0 m/s • 120 m/s Solution: 3(0.10/2) = L and 480 = 4v/(2L) OSU PH 212, Before Class #25

  19. Example: A standing wave of the 4th harmonic is set up on a guitar string. The frequency is 440 Hz. • (a) How many loops are in this standing wave? • (b) How many nodes does this wave have? • (c) Is the string’s midpoint a node or antinode? • Find the frequency of the string’s 1st harmonic. • Example: The “G” string on a guitar has a fundamental frequency of 196 Hz and a length of 0.62 m. When you press this string against the proper fret, you can produce a “C” note (262 Hz). What is the new, shortened length of the vibrating string? (In other words, what is the distance from that fret to the bridge of the instrument?) • (see After class 25 for the solutions) OSU PH 212, Before Class #25

  20. Example: When you blow across the top of a partially-filled bottle of water, you are setting up a standing wave in a chamber that is open only at one end. Is there an air pressure node or antinode at the top of the bottle? How about at the water level? Is there an air displacement node or antinode at the top of the bottle? How about at the water? If the standing wave is vibrating at its fundamental frequency, how far is it from the top to the water level? If you pour out some water, then blow again, will the fundamental frequency then be higher or lower? (see After class 25 for the solutions) OSU PH 212, Before Class #25

  21. Example: The auditory canal in the human ear has an average length of about 2.9 cm, and it functions approximately as a tube with one open end. For a speed of sound of 343 m/s, what is the fundamental frequency of the auditory canal? Example: For each of the following systems, the fundamental frequency is 400 Hz. Find the three lowest frequencies at which other standing waves will occur: (a) a string fixed at both ends; (b) a cylindrical pipe with both ends open; (c) a cylindrical pipe with only one end open. (see After class 25 for the solutions) OSU PH 212, Before Class #25

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