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Explore ionization constant Kb for weak bases, calculate Kb from pH values, determine [OH-], pH, pOH from Kb in Chemistry.
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Chemistry 1011 TOPIC Acids and Bases TEXT REFERENCE Masterton and Hurley Chapter 4.2 (Review), 13, 14.1, 15.1 (page 427), 21.2 (page589) Chemistry 1011 Slot 5
Note on Topic Sequence • Section 13.4 in the Text includes some Cations as weak acids • Section 13.5 in the Text includes some Anions as weak bases • Section 13.5 also includes material concerning the relation between Ka and Kb • These topics will all be included when we cover Section 13.6 – “Acid-Base Properties of Salt Solutions” Chemistry 1011 Slot 5
13.5 Weak Bases and Their Ionization Constants YOU ARE EXPECTED TO BE ABLE TO: • Write an expression for the ionization constant, Kb, for a weak base • Place a list of weak bases in order of strength given values for Kb or pKb • Calculate Kb, given the pOH of a solution of a weak base • Given Kb, calculate the percent ionization of a weak base • Given Kb, calculate the [OH-], [H+] pOH and pH of a solution of a weak base of known concentration Chemistry 1011 Slot 5
Ionization Constants of Weak Bases • Weak bases produce hydroxide ions by reacting with water molecules • Ammonia, NH3, is a weak base NH3(aq) + H2O(aq)NH4+(aq) + OH-(aq) cb ca ca cb • In this process, • the NH3 accepts a proton and is a Bronsted-Lowry base • the H2O donates a proton and is a Bronsted-Lowry acid • NH4+ is the conjugate acid of NH3 • OH- is the conjugate base of H2O • Organic amines, R-NH2, are also weak bases Chemistry 1011 Slot 5
Ionization Constants of Weak Bases • NH3(aq) + H2O(aq)NH4+(aq) + OH-(aq) Kb = [NH4+] x[OH-] [NH3] • It is possible to determine • Kb, knowing the pOH and molar concentration of a weak base • pOH and PH, knowing the value of Kb and the molar concentration of a weak base Chemistry 1011 Slot 5
Calculating Kb from the pH or pOH Value • Calculate the value of Kb for methylamine, CH3NH2 given that the pH of a 0.10mol/L solution is 11.8 CH3NH2(aq) + H2O(aq)CH3NH3+(aq) + OH-(aq) Kb = [CH3NH3+] x[OH-] [CH3NH2] • If pH = 11.8, then pOH = 2.2 and [OH-] = 6.3 x 10-3 Kb = (6.3 x 10-3)2 = (6.3 x 10-3)2 = 4.0 x 10-4 (1.0 x 10-1- 6.3 x 10-3) (1.0 x 10-1) Chemistry 1011 Slot 5
Calculating [OH-], pH and pOH from Kb • Calculate the pH of a 5.0 x 10-2 mol/L solution of ammonia, given that Kb = 1.8 x 10-5. NH3(aq) + H2O(aq) NH4+(aq) + OH-(aq) Kb = [NH4+] x[OH-] = 1.8 x 10-5 [NH3] [original] 5.0 x 10-2 0.0 0.0 D[ ] -x +x +x [equilibrium] (5.0 x 10-2 - x) x x Chemistry 1011 Slot 5
Solving for x (Approximate Method) • Assume that x << (5.0 x 10-2) • Then: Ka = 1.8 x 10-5 = x2 (5.0 x 10-2) x2 = (1.8 x 10-5)(5.0 x 10-2) = 9.0 x 10-7 x = 9.5 x 10-4mol/L pOH = 3.0 pH = 11.0 (Check that [OH-] is << [NH3] ) 9.5 x 10-4mol/L<< 5.0 x 10-2 mol/L Chemistry 1011 Slot 5