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Extra Practice for Sem 2, Quiz 5. Use special right ∆ rules to solve the triangle. Answers in simplified radical form. I have the short leg, so to get long leg, multiply by √3 hyp , multiply by 2. 30 . 42. 21√3. 60 . 21.
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Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the short leg, so to get long leg, multiply by √3 hyp, multiply by 2 30 42 21√3 60 21
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have a leg, so the other leg is congruent, and to get the hyp, multiply by √2 45 21√2 21 45 21
Use special right ∆ rules to solve the triangle. Answers in simplified radical form 9√3 30 I have the hyp, so get short leg first by dividing by 2 9 18 60 Then, from the short leg to get the long leg, multiply by √3
Use special right ∆ rules to solve the triangle. Answers in simplified radical form 17√3 2 I have the hyp, so get short leg first by dividing by 2 30 17 2 17 60 Then, from the short leg to get the long leg, multiply by √3
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the hyp, so get short leg first by dividing by 2 7√2 60 Then, from the short leg to get the long leg, multiply by √3 7√6 14√2 30
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the hyp, so get short leg first by dividing by 2 12√3 60 Then, from the short leg to get the long leg, multiply by √3 36 24√3 30 12√3•√3 = 12•3 = 36
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the long leg, so get short leg first by dividing by √3 24 60 Then, from the short leg to get the hyp, multiply by 2 24√3 48 30
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the long leg, so get short leg first by dividing by √3 10√2 60 Then, from the short leg to get the hyp, multiply by 2 10√6 20√2 30 √2 10√6 √3 = 10√2
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the long leg, so get short leg first by dividing by √3 6√3 60 Then, from the short leg to get the hyp, multiply by 2 18 12√3 30 18 √3 • √3 • √3 = 18√3 3 = 6√3
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the long leg, so get short leg first by dividing by √3 40√3 3 30 20 Then, from the short leg to get the hyp, multiply by 2 20 √3 • √3 • √3 = 20√3 3 60 20√3 3
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the hyp, so to get the legs, divide by √2 45 12√10 12√5 √5 12√10 √2 = 12√5 45 12√5
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the hyp, so to get the legs, divide by √2 21√2 21√2 42 √2 • √2 • √2 = 42√2 2 45 45 42 = 21√2
Use special right ∆ rules to solve the triangle. Answers in simplified radical form I have the hyp, so to get the legs, divide by √2 45 5√7 5√14 2 5√7 √2 • √2 • √2 = 5√14 2 45 5√14 2
Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth. I have the hyp and the side adjto A, so I will use the cos. B 23 cosA = 16/23 A = cos-1 (16/23) A = 45.9 45.9 C A 16
Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth. I have the hyp and the side oppto B, so I will use the sin. B 23 44.1 sinA = 16/23 A = sin-1 (16/23) A = 44.1 45.9 C A 16 Check: 44.1 + 45.9 = 90 yes!
Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth. I have several choices for finding the missing side. I am using the sin of A; I’m looking for adjside, and I have the hyp. B 23 44.1 sin (45.9) = x 1 23 x = 23sin(45.9) x = 16.5 16.5 45.9 C A 16 Check: 16.52 + 162 = 232 528.25 ≈ 529
Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth. I have the side oppof A, so I will use the sinto find the hyp. B 139.5 50 sin (21) = 50 1 x x sin (21) = 50 x = 50 sin (21) x = 139.5 21 A C
Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth. I have the side oppof A, so I will use the tan to find the adjside. B 139.5 50 tan (21) = 50 1 x x tan (21) = 50 x = 50 tan (21) x = 130.3 21 A 130.3 C Check: 502 + 130.32 = 139.52 19452.04 ≈ 19460.25
Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth. B B = 90 – 21 = 69 139.5 69 50 21 A 130.3 C Check: sin(69) = 130.3 / 139.5 .9336 ≈ .9341