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Warm-up. Sketch the graph of the function. Label the endpoints !. Answers. Use Calculator to check!. Precalculus L esson 1.8. Check: p. A36 #120, 122, 124, 134,140, 152, 156,160, 174, 184. 1.8. Objective: Combine functions arithmetically and graphically. What You Should Learn.
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Warm-up Sketch the graph of the function. Label the endpoints!
Answers Use Calculator to check!
PrecalculusLesson 1.8 Check: p. A36 #120, 122, 124, 134,140, 152, 156,160, 174, 184
1.8 Objective: Combine functions arithmetically and graphically.
What You Should Learn • Add, subtract, multiply, and divide functions. • Find the composition of one function with another function. • Use combinations and compositions of functions to model and solve real-life problems.
Example 1 Given f (x)= 2x – 3 and g(x) = x2 – 1 find the sum, difference, product, and quotient of f and g. f(x) + g(x) = (2x – 3) + (x2 – 1) = x2 + 2x – 4 f(x) – g(x) = (2x – 3) – (x2 – 1) = –x2 + 2x – 2 f(x)g(x) = (2x – 3)(x2 – 1) = 2x3 – 3x2– 2x + 3 Sum Difference Product Quotient
Arithmetic Combinations of Functions • The domain of an arithmetic combination of functions f and g consists of all real numbers that are common to the domains of f and g. • In the case of the quotient f(x)/g(x), there is the further restriction that g(x) 0.
Example 2 – Finding the Sum of Two Functions & evaluating. Given f(x) = 2x + 1 and g(x) = x2 + 2x – 1 find (f + g)(x). Then evaluate the sum when x = 3. Solution: (f + g)(x) = f(x) + g(x) = (2x + 1) + (x2 + 2x – 1) When x = 3, the value of this sum is (f + g)(3) = 32 + 4(3) = x2 + 4x = 21. Do Example 1 on notes 1.8
Composition of Functions Figure 1.90
Example 3 – Composition of Functions Given f(x) = x + 2 and g(x) = 4 – x2, find the following. a. (f g)(x) b. (g f)(x) c. (g f)(–2) Solution: a. The composition of f with g is as follows. (f g)(x) = f(g(x)) = f(4– x2) = (4– x2) + 2 = –x2 + 6 Definition of f g Definition of g(x) Definition of f(x) Simplify.
Example 3 – Solution cont’d b. The composition of g with f is as follows. (g f)(x) = g(f(x)) = g(x + 2) = 4 – (x + 2)2 = 4 – (x2 + 4x + 4) = –x2 – 4x Note that, in this case, (f g)(x) (g f)(x). Definition of g f Definition of f(x) Definition of g(x) Expand. Simplify.
Example 3 – Solution cont’d c. Using the result of part (b), you can write the following. (g f )(–2) = –(–2)2 – 4(–2) = –4 + 8 = 4 Substitute. Simplify. Simplify. Do Example 2 on notes 1.8
Composition of Functions In calculus, it is also important to be able to identify two functions that make up a given composite function.
Composition of Functions Basically, to “decompose” a composite function, h(x) = (3x – 5)3 look for an “inner” function and an “outer” function. g(x) = 3x – 5 is the inner function and f(x) = x3 is the outer function. Therefore, h(x) = f(g(x)) = (3x – 5)3.
Example 4 – decompose the composite functions so that h(x) = f(g(x)) cont’d Do Example 3 on notes 1.8
p. 88 # 19-27 odd, 49, 51 Classwork
Homework Homework(1.8) p. 88 #12,16, 24,28,38, 42,46, 50, 52, 58
Find the domain of f(g(x)) Closure