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Another Terrain Conductivity Modeling Problem

Another Terrain Conductivity Modeling Problem. 27.26. 13.4. 7.48. 4.6. the Pit floor. In the current application we now have 4 conductivity layers. The equation you need to solve will look like this.

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Another Terrain Conductivity Modeling Problem

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  1. Another Terrain Conductivity Modeling Problem 27.26 13.4 7.48 4.6 the Pit floor

  2. In the current application we now have 4 conductivity layers. The equation you need to solve will look like this. In this problem we retain the conductivity of the contaminated regions as AMD = 100 mmhos/m and add a bedrock with conductivity of BR = 10 mmhos/m. S is the conductivity of uncontaminated spoil (4 mmhos/m) z RV(z) 0.83 0.53 1.67 0.29 2.5 0.196 3.33 0.149 4.17 0.119 5 0.1 Computing z’s for depths of 10, 20, 30, 40, and 50 feet using the EM31 vertical dipole configuration we can easily solve for the contribution of the contamination zone to the overall ground conductivity measured at the surface of the spoil.

  3. Relative contribution of the AMD zone to the overall ground conductivity. EM31 vertical dipole mode

  4. Sounding Coil spacing Midpoint 40m 20m 10m 3.7m EM34 EM34 EM34 EM31 Surface 5.5m depth Exploration 15m depth Depth 30m depth 60mdepth

  5. Combined profiling and sounding 40 m 20 m 10 m 3.67m Depth Individual midpoints

  6. Depth Individual midpoints

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