Essential Oils for Natural Wellness Guide

Feb 27, 2025

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Discover the benefits of essential oils for your well-being with our comprehensive guide. Learn how to use these natural remedies effectively.

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Essential Oils for Natural Wellness Guide

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1. C5H10O2 1* 9
185.90 38.67 27.01
2. C5H8O2 dqd s d 1 1 3 3
167.03 144.74 122.58 51.33 17.93
3. C5H9ClO2 q t tt 2 2 2 3

4. C6H10O2 S* dt d m sext t 1* 1 1 2 2 3

5. C9H12O2 d d s q s* t 2 2 2 2 1* 3
158.38 133.15 128.57 114.47 64.57 63.47 14.79

C 5 H 12 O MW = 88.15

C 5 H 12 O MW = 88.15. C 5 H 12 O MW = 88.15. C 5 H 12 O MW = 88.15. C 5 H 12 O MW = 88.15. Solve the structure with no further information. Solve the structure with no further information. Two equally sized peaks That differ by 2 units: Bromine.

1.35k views • 96 slides

Alkynes . C n H 2n-2 C 2 H 2 H:C:::C:H H—C  C—H sp => linear, 180 o acetylene

Alkynes . C n H 2n-2 C 2 H 2 H:C:::C:H H—C  C—H sp => linear, 180 o acetylene ethyne C 3 H 4 CH 3 CCH methylacetylene propyne. nomenclature : common names: “alkylacetylene”

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Part 1 Yes C 25 H 52 + 38 O 2  25 CO 2 + 26 H 2 O Part 2 2 C 2 H 2 + 5 O 2  4 CO 2 + 2 H 2 O Complete: 1/10,

Part 1 Yes C 25 H 52 + 38 O 2  25 CO 2 + 26 H 2 O Part 2 2 C 2 H 2 + 5 O 2  4 CO 2 + 2 H 2 O Complete: 1/10, Incomplete: 1 Black deposit/product 12. Yes Questions H 2 O and CO 2 C, CO, CO 2 , H 2 O (always produced) Carbon (C).

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2 C + 1 O + 4 H + 1 C + 1 O + 4 H = 3 C + 2 O + 8 H

Même nombre de carbones, alcène au départ, aldéhyde à l’arrivée, donc modification de groupe caractéristique. Même nombre de carbones, alcène au départ, dérivé chloré à l’arrivée, donc modification de groupe caractéristique.

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ETHANOL C 2 H 5 OH

H. H. H. H. C. C. O. H. H. ETHANOL C 2 H 5 OH. Making Ethanol 1: FERMENTATION. Warm a solution of sucrose or glucose (sugars) with a yeast catalyst (enzyme). T = 37 ° C yeast catalyst. C 6 H 12 O 6. 2C 2 H 5 OH + 2CO 2. glucose. ethanol.

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Fischer Ester Formation: H + catalyzes (1) C=O attack and (2) H 2 O loss.

H. O. H. H. O. O. H. O. O. H. H. H. C. O. 3. H. C. 3. H. O. H. O. H. O. H. H. C. H. O. 3. O. H. O. C. H. 3. H. H. H. O. H. O. C. H. O. 3. O. H. H. O. O. C. H. 3. Timing by mouse click.

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C h 10

C h 10. Money. Money- anything that serves as medium of exchange Medium of Exchange- anything that is used to determine value during and exchange of goods and services Barter- direct exchange of one set of goods or services for another.

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Alkyne combustion reaction: 2 C 2 H 2 + 5 O 2 4 CO 2 + 2 H 2 O

Alkyne combustion reaction: 2 C 2 H 2 + 5 O 2 4 CO 2 + 2 H 2 O The combustion reactions are all exothermic . . Substitution Reactions. Substitution Reactions. Reaction with chlorine :. Substitution Reactions. Reaction with chlorine :

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6 CO 2 + 6 H 2 O C 6 H 12 O 6 + 6 O 2

ugljeni hidrati. porfirinski prsten. 6 CO 2 + 6 H 2 O C 6 H 12 O 6 + 6 O 2. glukoza. skrob. celuloza. ugljovodonični rep. Calvinov ciklus biosinteze glukoze. 2-. 2-. 2-. 2-. 2-. 2-. D-eritropentuloza- -1,5-difosfat. D-glukoza. 2-. 2-.

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H O C | H - C - OH | OH - C - H | OH - C - H

156 views • 2 slides

H 2 O + CO 2  C 6 H 12 O 6 + O 2

Via wortelhaartjes en microscopisch kleine buisjes tot in de bladeren. H O 2 ?. CO 2 ?. Via huidmondjes in bladeren. Hoe neemt de plant deze stoffen op?. Nodig voor de fotosynthese. Aanpassingen om zoveel mogelijk licht op te vangen?. H 2 O + CO 2  C 6 H 12 O 6 + O 2. 6. 6.

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H 2 O (l) H 2 O (g) H = 44 kJ.mol -1

1.-Calcula a entalpía de formación da auga gas a 298K, se a esta temperatura a entalpía de formación da auga líquida é -286kJ.mol -1 e a entalpía molar de vaporización da auga é 44 kJ.mol -1. Form. da auga líquida.

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K a = [ H + ] [ C 2 H 3 O 2 - ] [ HC 2 H 3 O 2 ]

Buffers Buffer - Substances in a solution that resist changes in pH a weak acid and its conjugate salt a weak base and its conjugate salt.

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C 2 H 5 OH

Выявление и пресечение деятельности участников нелегального производства и оборота алкогольной продукции на примере ООО «Каравелла» и ООО «ЛВЗ « Дистар ».

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C 3 H 8 + 5 O 2  3 CO 2 + 4 H 2 O

C 3 H 8 + 5 O 2  3 CO 2 + 4 H 2 O. 220 g of C 3 H 8 react in the above reaction. What mass of H 2 O is produced?. Pb (NO 3 ) 2 + 2 NaI  PbI 2 + 2 NaNO 3. 50 mL of a 0.5 mol /L solution of NaI reacts to produce how many grams of PbI 2 ?. C =. n V.

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C 4 H 8 O 2

C 4 H 8 O 2. C 4 H 8 O 2. C 5 H 10 O. C 5 H 11 Cl. C 4 H 9 OBr. C 6 H 12 O 3. C 3 H 7 NO 2. C 6 H 12 O 2. C 6 H 13 OCl. C 6 H 13 OBr. C 4 H 10 O. C 3 H 7 O 2 Br. C 5 H 12 O. C 6 H 12 O 2. C 6 H 14 O. C 7 H 16 O 2. C 8 H 14 O 3. C 8 H 14 O 4. C 4 H 10 O 2. C 8 H 18 O 4.

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NMR Practice: C 4 H 10 O

NMR Practice: C 4 H 10 O. Given a molecular formula and an NMR spectrum, what is the structure of the compound?. 3 H. 2 H. integral. NMR Practice – C 6 H 12 O 2. ratio 1 : 3.0. NMR : C 4 H 8 O 2. 3 H. 2 H. 3 H. q. t. Common Patters for Proton NMR.

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CH 3 OH + O 2  CO 2 + H 2 O C= C=

CH 3 OH + O 2  CO 2 + H 2 O C= C= H= H= O= O=. 2. 3. 2. 4. 1.5. 2. 2. 2. 8. 8. 8. 8. 1. 1. 2. 4. 4. 3. 4. 4. 3.

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Example 2 C 2 H 6  C 2 H 2 + 2H 2 C-C = 347, C-H = 413, C C = 837, H-H = 436

Example 2 C 2 H 6  C 2 H 2 + 2H 2 C-C = 347, C-H = 413, C C = 837, H-H = 436 H H | | H-C —C-H  H-C C-H + 2(H-H) | | H H Calculate H.

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2 C 6 H 6 + 15 O 2 → 12 CO 2 + 6 H 2 O

2 C 6 H 6 + 15 O 2 → 12 CO 2 + 6 H 2 O. How many moles of water are made by burning 0.35 moles of C 6 H 6 ?. 6 mol H 2 O = 3 = X 2 mol C 6 H 6 1 0.35 X = 1.1 mol H 2 O. 2 C 6 H 6 + 15 O 2 → 12 CO 2 + 6 H 2 O.

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2 H 2 + O 2 → 2 H 2 O

2 H 2 + O 2 → 2 H 2 O. +. Identify the factors that could affect the rate of a chemical reaction. Use the Collision Theory to explain the factors influencing the rate of a reaction. Explain the effect these factors have on the shape of a kinetic energy distribution curve.

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10 15 kg H 2 O

10 15 kg H 2 O. 10 12 kg de C. Hidr ó geno. No se parece mucho a los metales alcalinos: La sustancia elemental es un gas, no un metal La sustancia elemental no reacciona con agua Es mucho mas electronegativo que los metales alcalinos. Enlace del H 2. Enlace del H 2. Enlace del H 2.

418 views • 25 slides

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Essential Oils for Natural Wellness Guide

Essential Oils for Natural Wellness Guide

Presentation Transcript

C 5 H 12 O MW = 88.15

Alkynes . C n H 2n-2 C 2 H 2 H:C:::C:H H—C  C—H sp =&gt; linear, 180 o acetylene

Part 1 Yes C 25 H 52 + 38 O 2  25 CO 2 + 26 H 2 O Part 2 2 C 2 H 2 + 5 O 2  4 CO 2 + 2 H 2 O Complete: 1/10,

2 C + 1 O + 4 H + 1 C + 1 O + 4 H = 3 C + 2 O + 8 H

ETHANOL C 2 H 5 OH

Fischer Ester Formation: H + catalyzes (1) C=O attack and (2) H 2 O loss.

C h 10

Alkyne combustion reaction: 2 C 2 H 2 + 5 O 2 4 CO 2 + 2 H 2 O

6 CO 2 + 6 H 2 O C 6 H 12 O 6 + 6 O 2

H O C | H - C - OH | OH - C - H | OH - C - H

H 2 O + CO 2  C 6 H 12 O 6 + O 2

H 2 O (l) H 2 O (g) H = 44 kJ.mol -1

K a = [ H + ] [ C 2 H 3 O 2 - ] [ HC 2 H 3 O 2 ]

C 2 H 5 OH

C 3 H 8 + 5 O 2  3 CO 2 + 4 H 2 O

C 4 H 8 O 2

NMR Practice: C 4 H 10 O

CH 3 OH + O 2  CO 2 + H 2 O C= C=

Example 2 C 2 H 6  C 2 H 2 + 2H 2 C-C = 347, C-H = 413, C C = 837, H-H = 436

2 C 6 H 6 + 15 O 2 → 12 CO 2 + 6 H 2 O

2 H 2 + O 2 → 2 H 2 O

10 15 kg H 2 O

Alkynes . C n H 2n-2 C 2 H 2 H:C:::C:H H—C  C—H sp => linear, 180 o acetylene