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Moon River

Moon River. How Tides Affect the Volumetric Flow of the Columbia River. Volumetric Flow. Q = A*C The volume of fluid = Q A circle = πr 2 C = Velocity of the water. Volumetric Flow Through a Pipe. Plugging in the data… Given: Pipe – 2 m, Velocity = 4m/s Equations: Q = A*C

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Moon River

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  1. Moon River How Tides Affect the Volumetric Flow of the Columbia River

  2. Volumetric Flow Q = A*C The volume of fluid = Q Acircle = πr2 C = Velocity of the water

  3. Volumetric FlowThrough a Pipe Plugging in the data… Given: Pipe – 2 m, Velocity = 4m/s Equations: Q = A*C Acircle = πr2 = A = 3 * (2)2. Area = 12 m2 C = Velocity of the water C = 4 m/s Q = (12 m2) * (4 m/s) Q = 48 m3/s

  4. Volumetric FlowThrough a Pipe What would the volumetric flow be if we slowed the water flowing into the pipe, and the pipe was only ½ filled with water? Q = 48 m3/s / 2 Q = 24 m3/s

  5. Applying This Concept to the Columbia River Given: Depth of the Columbia River: 12.5 m Velocity (C) at 7 m = 2.25 m/s Equations: Q = A*C Acircle = πr2 The river can be thought of as a ½ pipe, so the surface area should be halved.

  6. Applying This Concept to the Columbia River Given: Depth of the Columbia River: 12.5 m Velocity (C) at 7 m = 2.5 m/s Equations: Q = A*C Acircle = πr2 (3)(12.5)2 = 469 m2. Because the river is like a ½ pipe… 469/2 = 234.5 m2.

  7. Applying This Concept to the Columbia River Given: Depth of the Columbia River: 12.5 m Velocity (C) at 7 m = 2.25 m/s Equations: Q = A*C Acircle = 234.5 m2. C = 2.25 m/s Q = (234.5 m2)(2.25 m/s) Q = 527.6 m3/s

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