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Projectile Motion

Projectile Motion. Important points to consider: The most straight-forward technique of solving these problems is to separate motion occurring in the ‘x’ direction and motion occurring in the ‘y’ direction.

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Projectile Motion

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  1. Projectile Motion Important points to consider: • The most straight-forward technique of solving these problems is to separate motion occurring in the ‘x’ direction and motion occurring in the ‘y’ direction. • Because we are considering no air friction, the body experiences an acceleration of zero in the ‘x’ direction. Therefore, vx is constant. • Because we are considering no air friction, movement in the ‘y’ direction is the same as a freely falling body:

  2. Projectile Motion Important points to consider: • When finding travel time, remember that the projectile must travel up, stop, and travel back down. So, at the top of the path (maximum height) vy = 0. • It’s very important to realize that the travel time is equal for both the ‘y’ and ‘x’ directions. • Always draw a coordinate system and clearly mark values. This is an excellent use for subscripts. • In these free-fall problems, final velocity is not zero. vf is the velocity of the body just before reaching the end of the fall.

  3. v0 + y v0 y  + x v0 x • The Problem: • A baseball is thrown with an initial velocity of 10 m/s at an angle 60 o above horizontal. Find the following values: • 1. maximum height • 2. travel time (time the ball is in the air) • 3. distance traveled in the horizontal direction

  4. In the “y” direction, treat the ball as though it was thrown vertically upward at 8.7 m/s. At the top According to our coordinate system

  5. 0 0 Find maximum height:

  6. 0 Find the time the ball is in the air. This is the time for the ball to rise 3.9 m and return to y = 0. Rise time:

  7. Find fall time. Treat this as a freely-falling body, where: At the top

  8. 0 0 So, yes, in the absence of air, it takes the same time to rise as it does to fall.

  9. Distance in x-dir. Finally, let’s find the distance the ball will travel in the horizontal (x) direction. Remember that The ball leaves with vox = 5.0 m/s and continues at that constant velocity in the x-direction for 1.8 s. Acceleration in the x-direction is zero because there is no force to change the motion of the ball.

  10. 0 0

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