1 / 26

Fluids - Hydrodynamics

Fluids - Hydrodynamics. Physics 6B. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB. With the following assumptions, we can find a few simple formulas to describe flowing fluids: Incompressible – the fluid does not change density due to the pressure exerted on it.

harrison-terrance
Download Presentation

Fluids - Hydrodynamics

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Fluids - Hydrodynamics Physics 6B Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  2. With the following assumptions, we can find a few simple formulas to describe flowing fluids: Incompressible – the fluid does not change density due to the pressure exerted on it. No Viscosity - this means there is no internal friction in the fluid. Laminar Flow – the fluid flows smoothly, with no turbulence. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  3. With the following assumptions, we can find a few simple formulas to describe flowing fluids: Incompressible – the fluid does not change density due to the pressure exerted on it. No Viscosity - this means there is no internal friction in the fluid. Laminar Flow – the fluid flows smoothly, with no turbulence. With these assumptions, we get the following equations: Continuity – this is conservation of mass for a flowing fluid. Here A=area of the cross-section of the fluid’s container, and the small v is the speed of the fluid. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  4. With the following assumptions, we can find a few simple formulas to describe flowing fluids: Incompressible – the fluid does not change density due to the pressure exerted on it. No Viscosity - this means there is no internal friction in the fluid. Laminar Flow – the fluid flows smoothly, with no turbulence. With these assumptions, we get the following equations: Continuity – this is conservation of mass for a flowing fluid. Here A=area of the cross-section of the fluid’s container, and the small v is the speed of the fluid. Bernoulli’s Equation - this is conservation of energy per unit volume for a flowing fluid. Notice that there is a potential energy term and a kinetic energy term on each side. Some examples will help clarify how to use these equations: Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  5. Example 1: Water travels through a 9.6cm diameter fire hose with a speed of 1.3m/s. At the end of the hose, the water flows out through a nozzle whose diameter is 2.5 cm. What is the speed of the water coming out of the nozzle? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  6. Example 1: Water travels through a 9.6cm diameter fire hose with a speed of 1.3m/s. At the end of the hose, the water flows out through a nozzle whose diameter is 2.5 cm. What is the speed of the water coming out of the nozzle? We use continuity for this one. We have most of the information, but don’t forget we need the cross-sectional areas, so we need to compute them from the given diameters. slower here faster here 1• 2• Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  7. Example 1: Water travels through a 9.6cm diameter fire hose with a speed of 1.3m/s. At the end of the hose, the water flows out through a nozzle whose diameter is 2.5 cm. What is the speed of the water coming out of the nozzle? We use continuity for this one. We have most of the information, but don’t forget we need the cross-sectional areas, so we need to compute them from the given diameters. slower here faster here 1• 2• Note: We didn’t really need to change the units of the areas - as long as both of them are the same, the units will cancel out. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  8. Example 1: Water travels through a 9.6cm diameter fire hose with a speed of 1.3m/s. At the end of the hose, the water flows out through a nozzle whose diameter is 2.5 cm. What is the speed of the water coming out of the nozzle? We use continuity for this one. We have most of the information, but don’t forget we need the cross-sectional areas, so we need to compute them from the given diameters. slower here faster here 1• 2• Note: We didn’t really need to change the units of the areas - as long as both of them are the same, the units will cancel out. Plugging in the numbers, we get: Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  9. Example 1: Water travels through a 9.6cm diameter fire hose with a speed of 1.3m/s. At the end of the hose, the water flows out through a nozzle whose diameter is 2.5 cm. What is the speed of the water coming out of the nozzle? We use continuity for this one. We have most of the information, but don’t forget we need the cross-sectional areas, so we need to compute them from the given diameters. slower here faster here 1• 2• Note: We didn’t really need to change the units of the areas - as long as both of them are the same, the units will cancel out. Plugging in the numbers, we get: Using the shortcut, we get: Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  10. Example 2: At one point in a pipeline, the water’s speed is 3 m/s and the gauge pressure is 40 kPa. Find the gauge pressure at a second point that is 11 m lower than the first if the pipe diameter at the second point is twice that of the first. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  11. Example 2: At one point in a pipeline, the water’s speed is 3 m/s and the gauge pressure is 40 kPa. Find the gauge pressure at a second point that is 11 m lower than the first if the pipe diameter at the second point is twice that of the first. We need Bernoulli’s Equation for this one (really it’s just conservation of energy for fluids). Notice we set up the y-axis so point 2 is at y=0. 1• y1=11 m y2=0 2• Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  12. Example 2: At one point in a pipeline, the water’s speed is 3 m/s and the gauge pressure is 40 kPa. Find the gauge pressure at a second point that is 11 m lower than the first if the pipe diameter at the second point is twice that of the first. We need Bernoulli’s Equation for this one (really it’s just conservation of energy for fluids). Notice we set up the y-axis so point 2 is at y=0. 1• y1=11 m Here’s Bernoulli’s equation – we need to find the speed at point 2 using continuity, then plug in the numbers. y2=0 2• Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  13. Example 2: At one point in a pipeline, the water’s speed is 3 m/s and the gauge pressure is 40 kPa. Find the gauge pressure at a second point that is 11 m lower than the first if the pipe diameter at the second point is twice that of the first. We need Bernoulli’s Equation for this one (really it’s just conservation of energy for fluids). Notice we set up the y-axis so point 2 is at y=0. 1• y1=11 m Here’s Bernoulli’s equation – we need to find the speed at point 2 using continuity, then plug in the numbers. y2=0 2• Continuity Equation: This is the ratio of the AREAS – it is the square of the ratio of the diameters Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  14. Example 2: At one point in a pipeline, the water’s speed is 3 m/s and the gauge pressure is 40 kPa. Find the gauge pressure at a second point that is 11 m lower than the first if the pipe diameter at the second point is twice that of the first. We need Bernoulli’s Equation for this one (really it’s just conservation of energy for fluids). Notice we set up the y-axis so point 2 is at y=0. 1• y1=11 m Here’s Bernoulli’s equation – we need to find the speed at point 2 using continuity, then plug in the numbers. y2=0 2• Continuity Equation: This is the ratio of the AREAS – it is the square of the ratio of the diameters Plugging in the numbers to the Bernoulli Equation: Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  15. Example 3: A medical technician is trying to determine what percentage of a patient’s artery is blocked by plaque. To do this, she measures the blood pressure just before the region of blockage and finds that it is 12 kPa, while in the region of blockage it is 11.5 kPa. Furthermore, she knows that the blood flowing through the normal artery just before the blockage is traveling at 30 cm/s, and the density of the patient’s blood is 1060 kg/m3. What percentage of the cross-sectional area of the patient’s artery is blocked by plaque? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  16. Example 3: A medical technician is trying to determine what percentage of a patient’s artery is blocked by plaque. To do this, she measures the blood pressure just before the region of blockage and finds that it is 12 kPa, while in the region of blockage it is 11.5 kPa. Furthermore, she knows that the blood flowing through the normal artery just before the blockage is traveling at 30 cm/s, and the density of the patient’s blood is 1060 kg/m3. What percentage of the cross-sectional area of the patient’s artery is blocked by plaque? There is a lot going on in this problem, but it is really just like the last one. In fact, it’s easier if we assume the artery is horizontal. We’ll use Bernoulli’s Equation to find the speed just after the blockage, then continuity will tell us the ratio of the areas. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  17. Example 3: A medical technician is trying to determine what percentage of a patient’s artery is blocked by plaque. To do this, she measures the blood pressure just before the region of blockage and finds that it is 12 kPa, while in the region of blockage it is 11.5 kPa. Furthermore, she knows that the blood flowing through the normal artery just before the blockage is traveling at 30 cm/s, and the density of the patient’s blood is 1060 kg/m3. What percentage of the cross-sectional area of the patient’s artery is blocked by plaque? There is a lot going on in this problem, but it is really just like the last one. In fact, it’s easier if we assume the artery is horizontal. We’ll use Bernoulli’s Equation to find the speed just after the blockage, then continuity will tell us the ratio of the areas. V1 = 30 cm/s solve for this speed V2 = ? cm/s these will be 0 Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  18. Example 3: A medical technician is trying to determine what percentage of a patient’s artery is blocked by plaque. To do this, she measures the blood pressure just before the region of blockage and finds that it is 12 kPa, while in the region of blockage it is 11.5 kPa. Furthermore, she knows that the blood flowing through the normal artery just before the blockage is traveling at 30 cm/s, and the density of the patient’s blood is 1060 kg/m3. What percentage of the cross-sectional area of the patient’s artery is blocked by plaque? There is a lot going on in this problem, but it is really just like the last one. In fact, it’s easier if we assume the artery is horizontal. We’ll use Bernoulli’s Equation to find the speed just after the blockage, then continuity will tell us the ratio of the areas. V1 = 30 cm/s solve for this speed V2 = 102 cm/s these will be 0 Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  19. Example 3: A medical technician is trying to determine what percentage of a patient’s artery is blocked by plaque. To do this, she measures the blood pressure just before the region of blockage and finds that it is 12 kPa, while in the region of blockage it is 11.5 kPa. Furthermore, she knows that the blood flowing through the normal artery just before the blockage is traveling at 30 cm/s, and the density of the patient’s blood is 1060 kg/m3. What percentage of the cross-sectional area of the patient’s artery is blocked by plaque? There is a lot going on in this problem, but it is really just like the last one. In fact, it’s easier if we assume the artery is horizontal. We’ll use Bernoulli’s Equation to find the speed just after the blockage, then continuity will tell us the ratio of the areas. V1 = 30 cm/s solve for this speed V2 = 102 cm/s these will be 0 Now use continuity: So the artery is 70% blocked (the blood is flowing through a cross-section that is only 30% of the unblocked area) Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  20. The Bernoulli ‘Effect’ Fast Flow=Low Pressure ↔ Slow Flow=High Pressure Airplane Wing Atomizer Hurricane Damage Curveballs, Backspin, Topspin Motorcycle Jacket Attack of the Shower Curtain Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  21. Example 4: Hurricane • If the speed of the wind is 50 m/s (that’s about 100 miles per hour), and the density of the air is 1.29 kg/m3, Find the reduction in air pressure due to the wind. • If the area of the roof measures 10m x 20m, what is the net upward force on the roof? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  22. Example 4: Hurricane • If the speed of the wind is 50 m/s (that’s about 100 miles per hour), and the density of the air is 1.29 kg/m3, Find the reduction in air pressure due to the wind. • If the area of the roof measures 10m x 20m, what is the net upward force on the roof? • For part a) we need to use Bernoulli’s equation. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  23. Example 4: Hurricane • If the speed of the wind is 50 m/s (that’s about 100 miles per hour), and the density of the air is 1.29 kg/m3, Find the reduction in air pressure due to the wind. • If the area of the roof measures 10m x 20m, what is the net upward force on the roof? • For part a) we need to use Bernoulli’s equation. • We can assume (as in the last example) that y1=y2=0. • We can also assume that the wind is not blowing inside. • Take point 1 to be inside the house, and point 2 to be outside. these will be 0 Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  24. Example 4: Hurricane • If the speed of the wind is 50 m/s (that’s about 100 miles per hour), and the density of the air is 1.29 kg/m3, Find the reduction in air pressure due to the wind. • If the area of the roof measures 10m x 20m, what is the net upward force on the roof? • For part a) we need to use Bernoulli’s equation. • We can assume (as in the last example) that y1=y2=0. • We can also assume that the wind is not blowing inside. • Take point 1 to be inside the house, and point 2 to be outside. these will be 0 Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  25. Example 4: Hurricane • If the speed of the wind is 50 m/s (that’s about 100 miles per hour), and the density of the air is 1.29 kg/m3, Find the reduction in air pressure due to the wind. • If the area of the roof measures 10m x 20m, what is the net upward force on the roof? • For part a) we need to use Bernoulli’s equation. • We can assume (as in the last example) that y1=y2=0. • We can also assume that the wind is not blowing inside. • Take point 1 to be inside the house, and point 2 to be outside. these will be 0 • Part b) is just a straightforward application of the definition of pressure. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  26. Example 4: Hurricane • If the speed of the wind is 50 m/s (that’s about 100 miles per hour), and the density of the air is 1.29 kg/m3, Find the reduction in air pressure due to the wind. • If the area of the roof measures 10m x 20m, what is the net upward force on the roof? • For part a) we need to use Bernoulli’s equation. • We can assume (as in the last example) that y1=y2=0. • We can also assume that the wind is not blowing inside. • Take point 1 to be inside the house, and point 2 to be outside. these will be 0 • Part b) is just a straightforward application of the definition of pressure. • Assuming the roof is flat, we just multiply: Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

More Related