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CCGPS Unit 5 Overview

CCGPS Unit 5 Overview. Area and Volume. MCC6.G.1.

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CCGPS Unit 5 Overview

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  1. CCGPS Unit 5 Overview Area and Volume

  2. MCC6.G.1 Find the area of right triangles, other triangles, special quadrilaterals, and polygons by composing into rectangles or decomposing into triangles and other shapes; apply these techniques in the context of solving real-world and mathematical problems. Examples: Area of Right Triangles Area of Triangles Area of Squares Area of Kites Area of Parallelogram Area of Trapezoid Real-World Problems with Area Vocabulary Words Right Triangle Square Kite Parallelogram Trapezoid Area

  3. A L T I T U D E Base Right Triangle A triangle that has exactly one 90◦angle

  4. AREA of a Right Triangle A = ½BH 4 ft • Substitute the values into the equation. • b = 3ft • h = 4ft • We are solving for A. • A = ½ (4 ft)(3 ft) • A = ½ (12 ft2) • A = 6 ft2 3 ft

  5. AREA of a Right Triangle A = ½BH 8.4 ft We are solving for A. A = ½ (8.4 ft)(6.2 ft) A = ½ (52.08 ft2) A = 26.04 ft2 6.2 ft

  6. A L T I T U D E Triangle A polygon having three sides. Base

  7. AREA of a Triangle A = ½BH We are solving for A. A = ½ (6 ft)(4 ft) A = ½ (24 ft2) A = 12 ft2 4 ft 6 ft

  8. AREA of a Parallelogram 9 ft We are solving for A. A = ½(6 ft)(9 ft) + ½(6 ft)(9 ft) A = ½(54 ft2) + ½(54 ft2) A = 27 ft2 + 27 ft2 A = 54 ft2 6ft 9 ft

  9. AREA of a Parallelogram A = BH 9 ft We are solving for A. A = (6 ft.)(9 ft.) A = 54ft2 6ft

  10. AREA of a Rhombus A = BH 4 ft. 4 ft. A Rhombus is a four-sided Polygon where all sides have equal length (It looks like a someone sat on a square) 4 ft We are solving for A. A = (4 ft)(3 ft) A = 12 ft2 4 ft 3 ft

  11. AREA of a Rectangle A = L x W 15 ft We are solving for A. A = (15 ft)(10 ft) A = 150 ft2 10 ft

  12. AREA of a Square A = s2 We are solving for A. A = (10 ft)(10 ft) A = 100 ft2 10 ft. 10 ft.

  13. AREA of a Kite Suppose you were asked to find the area of this kite. Using what we already know about triangles, how can we find the area of the kite? We are solving for A. A = ½(24in12 in) + ½(24 in36 in) A = ½(288 in2) + ½(864 in2) A = 144 in2 + 432 in2 A = 576 in2 12 in. 36 in. 24 in.

  14. AREA of a Trapezoid How can we find the area of this trapezoid? We are solving for A. A = ½(12 in24 in) ½(12 in 24 in) + (12 in 24 in) A = ½(288 in2) ½(288 in2) + (288 in2) A = 144 in2 + 144 in2 + 288 in2 A = 576 in2 12 in. 24 in. 12 in. 12 in. 12 in. 36 in.

  15. Area = ½ Base x Height A = ½ (9 feet) x (25 feet) A = ½ (225 ft2) A = 112.5 ft2 25 feet 9 feet Mr. and Mrs. Brady purchased this home in Marietta, Georgia. Mrs. Brady is tired of looking at the brown dirt patch in the median of the road in front of their home. She has asked her husband to plant something in that area which will give it a more attractive curb appeal. Mr. Brady knows that the soil will need to be treated with fertilizer in order for it to be able to grow beautiful flowers. Mr. Brady needs to find the area of the ground to be treated. He has provided the length of two sides that make a right angle for you to use to determine the area. One side is twenty five feet. The other side is 9 feet. What is the Area?

  16. Area = Base x Height A = (2.5 meters) x (50 meters) A = (125 meters2) If one lane is 125 m2. and we have eight lanes than we need to multiple the area of one lane by the total number of lanes 8 125 m2 x 8 = 1000 m2 The Beijing National Aquatics Center has request your help. They require a cover for the Olympic swimming pool that is housed within this beautiful building. The pool has eight lanes that are each 2.5 meters wide. The length of each lane is 50 meters long. How long will the cover need to be if you wish to cover only the surface of the pool?

  17. MCC6.G.2 Find the volume of a right rectangular prism with fractional edge lengths by packing it with unit cubes of the appropriate fraction edge lengths, and show that the volume is the same as it would be found by multiplying the edge lengths of the prism. Apply the formulas V = lwh and V = Bh to find the volumes of right rectangular prisms with fractional edge lengths in the context of solving real-world and mathematical problems. Examples: Use unit cubes to pack a right rectangular prism with fractional edge lengths Find the volume of right rectangular prisms using the volume formulas Real-world problems Vocabulary Words Prism Right Rectangular Prism Edge Base of a Prism Volume Unit Cubes

  18. Volume with fractional Lengths Find the volume of a rectangular prism with fractional edge lengths You cannot use a whole unit block as a visual because when you try the block will extend past the boundary of the original shape. To fill a fractional side we will need a fractional unit cube. 2 units 2 units 1.5 units 1 unit Now we can insert the ½ unit blocks onto the bottom row of our figure . 6 x ½ = 3 whole unit blocks on bottom row 6 X ½ = 3 whole unit blocks on the top row 3 + 3 = 6 total whole unit blocks 1 unit 1/2 in. 1 unit

  19. MCC6.G.4 Represent three-dimensional figures using nets made up of rectangles and triangles using nets made up of rectangles and triangles, and use the nets to find the surface area of these figures. Apply these techniques in the context of solving real-world and mathematical problems. Examples: Nets of triangular prisms Nets of rectangular prisms Nets of square pyramids Nets of rectangular pyramids Surface area of each of the prisms and pyramids Real-world problems Vocabulary Words Nets Triangular Prisms Pyramid Surface Area

  20. SURFACE AREA of a Square Pyramid By looking at a net of this square pyramid determine the surface area. Surface are of the square in the middle: SA = (5 ft.)(5 ft.) SA = 25 ft2 Surface are of one of the triangle segments: SA = ½ (5 ft.)(6 ft.) SA = 15 ft2 By looking at a net of this square pyramid determine the surface area. Surface are of the square in the middle: A = 25 ft2 Surface are of one of the triangle segments: A = 15 ft2 Total Surface Area: 1 square & 4 Triangles A = 25 ft2 + 4 (15 ft2) A = 85 ft2 6 ft. 5 ft.

  21. SURFACE AREA of a Rectangular Prism By looking at a net of this rectangular prism determine the surface area. Similar rectangles are labeled. Surface area of all six rectangles. Rectangle A - SA = 3 ft2 Rectangle A - SA = + 3 ft2. Rectangle B - SA = + 15 ft2 Rectangle B - SA = + 15 ft2 Rectangle C - SA = + 5 ft2 Rectangle C - SA = + 5 ft2 Total = SA = 46 ft2 By looking at a net of this rectangular prism determine the surface area. Similar rectangles are labeled. Surface area of the rectangle B. SA = (3 ft.)(5 ft.) SA = 15 ft2 By looking at a net of this rectangular prism determine the surface area. Similar rectangles are labeled. Surface area of the rectangle C. SA = (5 ft.)(1 ft.) SA = 5ft2 3 ft. By looking at a net of this rectangular prism determine the surface area. Similar rectangles are labeled. Surface area of the rectangle A. SA = (3 ft.)(1 ft.) SA = 3 ft2 A 1 ft. 3 ft. C B C B 5 ft. A

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