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Problem 1 Output Work, Input Work, Slope

Problem 1 Output Work, Input Work, Slope. Complete the following:. In your journal, Draw a picture of an inclined plane Place the following labels and values in the correct locations: Load Force = 20 Newton’s Load Distance = 3 m Effort Force = 15 Newton’s Effort Distance = 5 m

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Problem 1 Output Work, Input Work, Slope

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  1. Problem 1 Output Work, Input Work, Slope

  2. Complete the following: In your journal, • Draw a picture of an inclined plane • Place the following labels and values in the correct locations: • Load Force = 20 Newton’s • Load Distance = 3 m • Effort Force = 15 Newton’s • Effort Distance = 5 m • Rise = 3 m • Run = 4m • Calculate Output Work? • Calculate Input Work? • What is the slope of the incline?

  3. Slope = Rise Run Slope = .75 Slope = .75 <---------Rise--------3 m--------------- Slope Slope = 3 (rise) 4 (run) Slope = Rise Run <--------------------Run---4 m--------------------

  4. Slope = Rise Run Slope = .75 OW = LF x LD OW = 60 Joules OW = 60 Joules --------Load Force----20 Newton’s---- <---------Rise--------3 m--------------- ---------Load Distance---3 m--------- Output Work OW = 20 x 3 = 60 (LF) (LD) Joules Output Work = Load Force x Load Distance <--------------------Run---4 m--------------------

  5. Slope = Rise Run Slope = .75 OW = LF x LD IW = EF x ED OW = 60 Joules IW = 75 Joules <------Effort Force—15 Newton’s-- <------Effort Distance---5 m----- IW = 75 Joules <---------Rise--------3 m--------------- ---------Load Distance---3 m--------- --------Load Force----20 Newton’s--- Input Work IW = 15 x 5 = 75 (EF) (ED) Joules Input Work = Effort Force x Effort Distance <--------------------Run---4 m--------------------

  6. Problem 2 IW, OW, Slope, IMA, AMA, Efficiency

  7. Complete the following: In your journal, • Draw a picture of an inclined plane • Place the following labels and values in the correct locations: • Load Force = 15 Newton’s • Load Distance = 6 m • Effort Force = 11 Newton’s • Effort Distance = 10 m • Run = 8m • Calculate Output Work? • Calculate Input Work? • What is the slope of the incline? • What is the IMA? • What is the AMA? • What is the efficiency?

  8. Slope = Rise Run Slope = .75 Slope = .75 <---Rise—(same as Load Distance)------6 m-------- Slope Slope = 6 (rise) 8 (run) Slope = Rise Run <--------------------Run---8 m--------------------

  9. Slope = Rise Run Slope = .75 OW = 90 Joules OW = LF x LD OW = 90 Joules --------Load Force----15 Newton’s---- <---------Rise--------6 m--------------- Output Work ---------Load Distance---6 m--------- OW = 15 x 6 = 90 (LF) (LD) Joules Output Work = Load Force x Load Distance <--------------------Run---8 m--------------------

  10. Slope = Rise Run Slope = .75 OW = LF x LD OW = 90 Joules IW = EF x ED IW = 110 Joules <------Effort Force—11 Newton’s-- <------Effort Distance---10 m----- IW = 110 Joules <---------Rise--------6 m--------------- ---------Load Distance---6 m--------- --------Load Force----15 Newton’s--- Input Work IW = 11 x 10 = 110 (EF) (ED) Joules Input Work = Effort Force x Effort Distance <--------------------Run---8 m--------------------

  11. Slope = Rise Run Slope = .75 OW = 90 Joules OW = LF x LD IW = EF x ED IW = 110 Joules IMA = ED ÷ LD IMA = 1.67 <------Effort Force—11 Newton’s-- <------Effort Distance---10 m----- IMA = 1.67 <---------Rise--------6 m--------------- ---------Load Distance---6 m--------- --------Load Force----15 Newton’s--- IMA IMA = 10 ÷ 6 = 1.67 (ED) (LD) IMA = Effort Distance ÷ Load Distance <--------------------Run---8 m--------------------

  12. Slope = Rise Run Slope = .75 OW = 90 Joules OW = LF x LD IW = EF x ED IW = 110 Joules IMA = ED ÷ LD IMA = 1.67 AMA = 1.36 AMA = LF ÷ EF <------Effort Force—11 Newton’s-- <------Effort Distance---10 m----- AMA = 1.36 <---------Rise--------6 m--------------- ---------Load Distance---6 m--------- --------Load Force----15 Newton’s--- AMA AMA = 15 ÷ 11 = 1.36 (LF) (EF) AMA = Load Force ÷ Effort Force <--------------------Run---8 m--------------------

  13. Slope = Rise Run Slope = .75 OW = LF x LD OW = 90 Joules IW = EF x ED IW = 110 Joules IMA = ED ÷ LD IMA = 1.66 AMA = LF ÷ EF AMA = 1.36 <------Effort Force—11 Newton’s-- <------Effort Distance---10 m----- Efficiency = 82% Eff = OW ÷ IW x 100 <---------Rise--------6 m--------------- ---------Load Distance---6 m--------- --------Load Force----15 Newton’s--- Efficiency Eff = 82% Efficiency = (90 ÷ 110) = .82 (OW) (IW) .82 x 100 = 82 % Efficiency = (OW ÷ IW) x 100 <--------------------Run---8 m--------------------

  14. Problem 3 IW, OW, Slope, IMA, AMA, Efficiency

  15. Complete the following: In your journal, • Draw a picture of an inclined plane • Place the following labels and values in the correct locations: • Load Force = 120 Newton’s • Load Distance = 12 m • Effort Force = 80 Newton’s • Effort Distance = 22.5 m • Run = 20 m • Calculate Output Work? • Calculate Input Work? • What is the slope of the incline? • What is the IMA? • What is the AMA? • What is the efficiency?

  16. Slope = Rise Run Slope = .6 Slope = .6 <---Rise—(same as Load Distance)------12 m-------- Slope Slope = 12 (rise) 20 (run) Slope = Rise Run <--------------------Run---20 m--------------------

  17. Slope = Rise Run Slope = .6 OW = 1440 Joules OW = LF x LD OW = 1440 Joules -----Load Force----120 Newton’s---- <---------Rise--------12 m--------------- Output Work -------Load Distance---12 m--------- OW = 120 x 12 = 1440 (LF) (LD) Joules Output Work = Load Force x Load Distance <--------------------Run---20 m--------------------

  18. Slope = Rise Run Slope = .75 OW = LF x LD OW = 1440 Joules IW = EF x ED IW = 1800 Joules <------Effort Force—80 Newton’s-- <------Effort Distance---22.5 m----- IW = 1800 Joules <---------Rise--------12 m------------ ---------Load Distance---12 m------- --------Load Force----120 Newton’s- Input Work IW = 80 x 22.5 = 1800 (EF) (ED) Joules Input Work = Effort Force x Effort Distance <--------------------Run---20 m--------------------

  19. Slope = Rise Run Slope = .75 OW = 1440 Joules OW = LF x LD IW = EF x ED IW = 1800 Joules IMA = ED ÷ LD IMA = 1.88 <------Effort Force—80 Newton’s-- <------Effort Distance---22.5 m----- IMA = 1.88 <---------Rise--------12 m--------------- ------Load Distance---12 m--------- -----Load Force----120 Newton’s--- IMA IMA = 22.5 ÷ 12 = 1.88 (ED) (LD) IMA = Effort Distance ÷ Load Distance <--------------------Run---20 m--------------------

  20. Slope = Rise Run Slope = .75 OW = 1440 Joules OW = LF x LD IW = EF x ED IW = 1800 Joules IMA = ED ÷ LD IMA = 1.88 AMA = 1.5 AMA = LF ÷ EF <------Effort Force—80 Newton’s-- <------Effort Distance---22.5 m----- AMA = 1.5 <---------Rise--------12 m--------------- -------Load Distance---12 m--------- ------Load Force----120 Newton’s--- AMA AMA = 120 ÷ 80 = 1.5 (LF) (EF) AMA = Load Force ÷ Effort Force <--------------------Run---20 m--------------------

  21. Slope = Rise Run Slope = .75 OW = LF x LD OW = 1440 Joules IW = EF x ED IW = 1800 Joules IMA = ED ÷ LD IMA = 1.88 AMA = LF ÷ EF AMA = 1.5 <------Effort Force—80 Newton’s-- <------Effort Distance---22.5 m----- Efficiency = 80% Eff = OW ÷ IW x 100 <---------Rise--------12 m--------------- -----Load Distance---12 m--------- -----Load Force----120 Newton’s--- Efficiency Eff = 80% Efficiency = (1440 ÷ 1800) = .80 (OW) (IW) .80 x 100 = 80 % Efficiency = (OW ÷ IW) x 100 <--------------------Run---20 m--------------------

  22. Problem 4 IW, OW, Slope, IMA, AMA, Efficiency

  23. Complete the following: In your journal, • Draw a picture of an inclined plane • Place the following labels and values in the correct locations: • Load Force = 18 Newton’s • Load Distance = 6 m • Effort Force = 12 Newton’s • Effort Distance = 10 m • Run = 8m • Calculate Output Work? • Calculate Input Work? • What is the slope of the incline? • What is the IMA? • What is the AMA? • What is the efficiency?

  24. Slope = Rise Run Slope = .75 Slope = .75 <---Rise—(same as Load Distance)------6 m-------- Slope Slope = 6 (rise) 8 (run) Slope = Rise Run Click to continue <--------------------Run---8 m--------------------

  25. Slope = Rise Run Slope = .75 OW = LF x LD OW = 108 Joules OW = 108 Joules --------Load Force----18 Newton’s---- <---------Rise--------6 m--------------- Output Work ---------Load Distance---6 m--------- OW = 18 x 6 = 108 (LF) (LD) Joules Click to continue Output Work = Load Force x Load Distance <--------------------Run---8 m--------------------

  26. Slope = Rise Run Slope = .75 OW = LF x LD OW = 108 Joules IW = EF x ED IW = 120 Joules <------Effort Force—12 Newton’s-- <------Effort Distance---10 m----- IW = 120 Joules <---------Rise--------6 m--------------- ---------Load Distance---6 m--------- --------Load Force----18 Newton’s--- Input Work IW = 12 x 10 = 120 (EF) (ED) Joules Click to continue Input Work = Effort Force x Effort Distance <--------------------Run---8 m--------------------

  27. Slope = Rise Run Slope = .75 OW = LF x LD OW = 108 Joules IW = EF x ED IW = 120 Joules IMA = ED ÷ LD IMA = 1.67 <------Effort Force—12 Newton’s-- <------Effort Distance---10 m----- IMA = 1.67 <---------Rise--------6 m--------------- ---------Load Distance---6 m--------- --------Load Force----18 Newton’s--- IMA IMA = 10 ÷ 6 = 1.67 (ED) (LD) Click to continue IMA = Effort Distance ÷ Load Distance <--------------------Run---8 m--------------------

  28. Slope = Rise Run Slope = .75 OW = 108 Joules OW = LF x LD IW = EF x ED IW = 120 Joules IMA = ED ÷ LD IMA = 1.67 AMA = LF ÷ EF AMA = 1.5 <------Effort Force—12 Newton’s-- <------Effort Distance---10 m----- AMA = 1.5 <---------Rise--------6 m--------------- ---------Load Distance---6 m--------- --------Load Force----18 Newton’s--- AMA AMA = 18 ÷ 12 = 1.5 (LF) (EF) Click to continue AMA = Load Force ÷ Effort Force <--------------------Run---8 m--------------------

  29. Slope = Rise Run Slope = .75 OW = LF x LD OW = 108 Joules IW = EF x ED IW = 120 Joules IMA = ED ÷ LD IMA = 1.66 AMA = LF ÷ EF AMA = 1.5 <------Effort Force—12 Newton’s-- <------Effort Distance---10 m----- Efficiency = 90% Eff = OW ÷ IW x 100 <---------Rise--------6 m--------------- ---------Load Distance---6 m--------- --------Load Force----18 Newton’s--- Efficiency Eff = 90% Efficiency = (108 ÷ 120) = .90 (OW) (IW) .90 x 100 = 90% Click to continue Efficiency = (OW ÷ IW) x 100 <--------------------Run---8 m--------------------

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