Entry Task: Jan 7 th Monday

Entry Task: Jan 7th Monday Provide the Kc expression for this equation. 3 Ca2+(aq) + 2 PO43-(aq) ↔ Ca3(PO4)2(s) You have 5 minutes

Agenda: • Discuss Kc Equilibrium constant ws • HW: • Ch. 15 sec. 4- Calculating Equilibrium constants PLEASE MUDDLE THROUGH IT!!

1. What are the 3 conditions necessary for equilibrium? • Must have a closed system • Must have a constant temperature • Ea must be low enough to allow a reaction.

2. What is a forward reaction versus a reverse reaction? • In a forward reaction, the reactants collide to produce products and it goes from left to right. • In a reverse reaction, the products collide to produce reactants and it goes form right to left.

3. Why does the forward reaction rate decrease as equilibrium is approached? • As the reaction goes to the right, the reaction concentration decreases and therefore, there are less reactant collisions causing the forward rate to decrease.

4. What are the characteristics of equilibrium or define equilibrium? • Forward rate is equal to the reverse rate. • The concentration of reactants and products are constant.(not equal) • Macroscopic properties are constant (color, mass, density, pressure, concentrations).

5. As a reaction is approaching equilibrium describe how the following change. Explain what causes each change. a. Reactant concentration • As the reaction goes to the right, the reaction concentration decreases. b. Products concentration • As the reaction goes from left to right, the concentration of the products increases.

5. As a reaction is approaching equilibrium describe how the following change. Explain what causes each change. c. Forward reaction rate. The reaction concentration decreases and therefore, there are less reactant collisions causing the forward rate to decreases. d. Reverse reaction rate The concentrations of the products increases, therefore there are more product collisions causing the reverse reaction rate to increase.

6. What is equal at equilibrium? The forward and reverse rates are equal.

7. What is constant at equilibrium? The reactant and product concentrations and the macroscopic properties are constant.

For the following three reactions,*Write the Kc expression AND calculate the value of Kc.*State whether the equilibrium is product-favored, reactant-favored, or fairly even ([products]  [reactants]). 8. N2 (g) + 3 H2(g)  2 NH3(g) Kc = 8.33 x 10-6 Small Kc favors reactant

For the following three reactions,*Write the Kc expression AND calculate the value of Kc.*State whether the equilibrium is product-favored, reactant-favored, or fairly even ([products]  [reactants]). • 9. HF(aq)  H+(aq) + F-(aq) Kc = 1.8 x 10-6 Small Kc favors reactant

For the following three reactions,*Write the Kc expression AND calculate the value of Kc.*State whether the equilibrium is product-favored, reactant-favored, or fairly even ([products]  [reactants]). 10. Fe3+(aq) + SCN-(aq)  FeSCN2+(aq) Kc = 1.8 Kc is very close to 1 so even

Summarize:Fill in the blanks with product-favored, reactant-favored, and approximately equal Products favored Reactant favored ~Equal~

11. Write equilibrium expressions for each of the following reactions: a) CaCO3(s)  CaO(s) + CO2(g) b) Ni(s) + 4CO(g)  Ni(CO)4(g) c) 5CO(g) + I2O5(s)I2(g) + 5CO2(g)

11. Write equilibrium expressions for each of the following reactions: d) Ca(HCO3)2(aq) CaCO3(s) + H2O(l) + CO2(g) e) AgCl(s)Ag+(aq) + Cl-(aq)

12. Write the equilibrium expression in terms of partial pressures (Kp) for each of the following reactions. Rate the reactions in order of their increasing tendency to proceed toward completion (products): ___ ___ ___ ___ • 4NH3(g) + 3O2(g) 2N2(g) + 6H2O(g) Kp= 1 x 10228

12. Write the equilibrium expression in terms of partial pressures (Kp) for each of the following reactions. Rate the reactions in order of their increasing tendency to proceed toward completion (products): ___ ___ ___ ___ (b) N2(g) + O2(g)2NO(g) Kp = 5 x 10-31

12. Write the equilibrium expression in terms of partial pressures (Kp) for each of the following reactions. Rate the reactions in order of their increasing tendency to proceed toward completion (products): ___ ___ ___ ___ (c) 2HF(g) H2(g) + F2(g) Kp = 1 x 10-13

12. Write the equilibrium expression in terms of partial pressures (Kp) for each of the following reactions. Rate the reactions in order of their increasing tendency to proceed toward completion (products): ___ ___ ___ ___ (d) 2NOCl(g) 2NO(g) + Cl2(g) Kp = 4.7 x 10-4

12. Write the equilibrium expression in terms of partial pressures (Kp) for each of the following reactions. Rate the reactions in order of their increasing tendency to proceed toward completion (products): ___ ___ ___ ___ (d) 2NOCl(g) 2NO(g) + Cl2(g) Kp= 4.7 x 10-4 B C D A • 4NH3(g) + 3O2(g)  2N2(g) + 6H2O(g)Kp = 1 x 10228 (b) N2(g) + O2(g) 2NO(g)Kp = 5 x 10-31 (c) 2HF(g)  H2(g) + F2(g) Kp = 1 x 10-13 Lowest value is reactant favored- least likely to complete reaction Highest value is product favored- most likely to complete reaction

13. (a) Write the Kc expression for2 SO2(g) + O2(g)  2 SO3(g)Calculate the value of Kc: Kc = 4.36

13. (b) If we reverse the equation, it is:2 SO3(g)  2 SO2(g) + O2(g) Write the Kc expression for this equation and calculate the new value of Kc: Kc = 0.229

13. (b) If we reverse the equation, it is:2 SO3(g)  2 SO2(g) + O2(g) Write the Kc expression for this equation and calculate the new value of Kc:How does the expression and the value of Kc in 7(b) compare with those in 7(a)? Kc = 1/Kc

(c) If we now multiply all of the coefficients by ½:SO3(g)  SO2(g) + ½ O2(g) Write the Kc expression for this equation and calculate the new value of Kc: • Kc  = 0.479

(c) If we now multiply all of the coefficients by ½:SO3(g)  SO2(g) + ½ O2(g) Write the Kc expression for this equation and calculate the new value of Kc:How do they compare with 7(b)? Kc = 0.229 Kc = 0.479 • Kc = square root of Kc

(d) What would happen to the Kc expression and its value if we doubled the coefficients? • Kc = (Kc)2

Summarize: squared Inverse or 1/Kc Square root

Entry Task: Jan 7 th Monday