1 / 8

Ex 1:

3. 4. –4. –3. 3 4. Slope is = = –. rise run. –3 4. Write the equation of the graphed line in slope-intercept form. Ex 1:. Identify the y -intercept. The y -intercept b is 1. Step 1. Step 2 Find the slope.

hprunty
Download Presentation

Ex 1:

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 3 4 –4 –3 3 4 Slope is = = – . rise run –3 4 Write the equation of the graphed line in slope-intercept form. Ex 1: Identify the y-intercept. The y-intercept b is 1. Step 1 Step 2 Find the slope. Choose any two convenient points on the line, such as (0, 1) and (4, –2). Count from (0, 1) to (4, –2) to find the rise and the run. The rise is –3 units and the run is 4 units. Step 3 Write the equation in slope-intercept form. y = mx + b y = – ¾x + 1

  2. Notice that for two points on a line, the rise is the differences in the y-coordinates, and the run is the differences in the x-coordinates. Using this information, we can define the slope of a line by using a formula.

  3. Find the slope of the line through (–1, 1) and (2, –5). Ex 2: Let (x1, y1) be (–1, 1) and (x2, y2) be (2, –5). The slope of the line is –2. Find the slope of the line. Let (x1, y1) be (4, 2) and (x2, y2) be (8, 5). The slope of the line is ¾.

  4. Because the slope of line is constant, it is possible to use any point on a line and the slope of the line to write an equation of the line in point-slope form. Ex 3: In slope-intercept form, write the equation of the line that contains the points in the table. First, find the slope. Let (x1, y1) be (–8, –5) and (x2, y2) be (8, 1). Next, choose a point, and use either form of the equation of a line.

  5. Rewrite in slope-intercept form. Method A Point-Slope Form Using (8, 1): y – y1= m(x – x1) Method B Slope-intercept Form Rewrite the equation using m and b. Using (8, 1), solve for b. y= mx+ b 1 = 3 + b b = –2

  6. The table shows the rents and selling prices of properties from a game. Ex 4: Express the rent as a function of the selling price. Let x = selling price and y = rent. Find the slope by choosing two points. Let (x1, y1) be (75, 9)and (x2, y2) be (90, 12). To find the equation for the rent function, use point-slope form. y – y1= m(x – x1)

  7. By comparing slopes, you can determine if the lines are parallel or perpendicular. You can also write equations of lines that meet certain criteria.

  8. perpendicular toand through (9, –2) Ex 5: Write the equation of the line in slope-intercept form. parallel toy = 1.8x + 3 and through (5, 2) Parallel lines have equal slopes. m = 1.8 y –2 = 1.8(x – 5) Use y – y1 = m(x – x1) with (x1, y1) = (5, 2). y –2 = 1.8x – 9 Distributive property. y= 1.8x – 7 Simplify. The slope of the given line is – 3/2, so the slope of the perpendicular line is the opposite reciprocal, 2/3. Use y – y1 = m(x – x1). y + 2 is equivalent to y – (–2). Distributive property. Simplify.

More Related