1 / 33

Chapter 6 Continuous Probability Distributions

Chapter 6 Continuous Probability Distributions. Figure 6.1 A Discrete Probability Distribution. Probability is represented by the height of the bar. P( x ). 1 2 3 4 5 6 7 x. Holes or breaks between values. f ( x ).

hyatt-suarez
Download Presentation

Chapter 6 Continuous Probability Distributions

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 6Continuous Probability Distributions

  2. Figure 6.1 A Discrete Probability Distribution Probability is represented by the height of the bar. P(x) 1 2 3 4 5 6 7 x Holes or breaks between values

  3. f(x) Probability is represented by area under the curve. x No holes or breaks along the x axis Figure 6.2 A Continuous Probability Distribution

  4. f(x) 1/20 62 72 82 x (commute time in minutes) Figure 6.3 Maria’s Commute Time Distribution

  5. f(x) 1/20 62 64 67 82 x (commute time in minutes) Figure 6.4 Computing P(64 <x< 67) Probability = Area = Width x Height= 3 x 1/20 = .15 or 15%

  6. Total Area = 20 x 1/20 = 1.0 1/20 62 82 20 Figure 6.5 Total Area = 1.0 1/20

  7. Uniform Probability Density Function (6.1) 1/(b-a) for a<x<b f(x) = 0 everywhere else

  8. m Figure 6.7 The Bell-Shaped Normal Distribution Mean is m Standard Deviation is s x

  9. Normal Probability Density Function (6.5) f(x)=

  10. Normal Distribution Properties • Approximately 68.3% of the values in a normal distribution will be within one standard deviation of the distribution mean, m. • Approximately 95.5% of the values in a normal distribution will be within two standard deviations of the distribution mean, m. • Approximately 99.7% of the values (nearly all of them) in a normal distribution will be found within three standard deviations of the distribution mean, m.

  11. .683 m-1s m m+1s Figure 6.8 Normal Area for m+ 1s

  12. .955 Figure 6.9 Normal Area for m+ 2s m-2s m m+2s

  13. .997 m-3s m m+3s Figure 6.10 Normal Area for m+ 3s

  14. Standard Normal Table

  15. Normal Table (2)

  16. Normal Table (3)

  17. Normal Table (4)

  18. Figure 6.11 Area in a Standard Normal Distribution for a z of +1.2 .3849 0 1.2 z

  19. z-score Calculation (6.6) z =

  20. m =50 s = 4 .3944 50 55 x (diameter) 0 1.25 z Figure 6.12 P(50 <x< 55)

  21. Figure 6.13 P(x> 58) m =50 s = 4 .0228 .4772 50 58 x(diameter) 0 2.0 z

  22. .2734 .4332 m = 50 s = 4 47 50 56 x(diameter) -.75 0 1.5 z Figure 6.14 P(47 < x < 56)

  23. m = 50 s = 4 .3413 .4772 50 54 58 x (diameter) 0 1.0 2.0 z Figure 6.15 P(54 < x < 58)

  24. Figure 6.16 Finding the z score for an Area of .25 .2500 0 ? z

  25. Exponential Probability (6.7) Density Function f(x) =

  26. Figure 6.17 Exponential Probability Density Function f(x) f(x) =l/elx x

  27. Calculating Area for the (6.8) Exponential Distribution P(x >a) =

  28. f(x) P(x>a) = 1/ela x a Figure 6.18 Calculating Areas for the Exponential Distribution

  29. f(x) P(1.0 <x< 1.5) x 1.0 1.5 Figure 6.19 Finding P(1.0 <x< 1.5)

  30. f(x) P(x> 1.0) = .1354 P(x> 1.5) = .0498 x 1.0 1.5 Figure 6.20 Finding P(1.0 <x< 1.5)

  31. Expected Value for the (6.9) Exponential Distribution E(x) =

  32. Variance for the Exponential (6.10)Distribution 2 s2 =

  33. Standard Deviation for the (6.11)Exponential Distribution s = =

More Related