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Fundamentals of Engineering Analysis EGR 1302 Unit 4, Lecture C

Learn the principles of set expressions and Venn diagrams in engineering analysis. Explore cardinality of sets and solve puzzles. Join the online lecture presented by Baylor University.

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Fundamentals of Engineering Analysis EGR 1302 Unit 4, Lecture C

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  1. Fundamentals of Engineering Analysis EGR 1302 Unit 4, Lecture C Approximate Running Time is 19 Minutes Distance Learning / Online Instructional Presentation Presented by Department of Mechanical Engineering Baylor University • Procedures: • Select “Slide Show” with the menu: Slide Show|View Show (F5 key), and hit “Enter” • You will hear “CHIMES” at the completion of the audio portion of each slide; hit the “Enter” key, or the “Page Down” key, or “Left Click” • You may exit the slide show at any time with the “Esc” key; and you may select and replay any slide, by navigating with the “Page Up/Down” keys, and then hitting “Shift+F5”.

  2. E P C Venn Diagram from a Defined Event E- the set of all students taking English C- the set of all students taking Chemistry P- the set of all students taking Physics Graph the Event - Students who are taking English and at least one science course

  3. Set Expressions from Venn Diagrams A B 2 3 1 7 4 6 5 C 8

  4. Set Expressions from Venn Diagrams Sum of Products P E C

  5. Set Expressions & Venn Diagrams Use Sum of Products

  6. Set Expressions Example B A C

  7. A B 2 10 10 Cardinality of Sets The Number of Elements (or Objects) in a Set A B

  8. Cardinality of Sets Example (Text Example 35.7) An example of evaluating Process quality

  9. Cardinality of Sets Puzzle Every Blip is a Blop. Half of all Bleeps are Blops. Half of all Blops are Blips. There are 30 Bleeps and 20 Blips. No Bleep is a Blip. How many Blops are neither Blips nor Bleeps? BEFORE YOU LOOK AT THE SOLUTION: Construct a Venn Diagram that shows the relationship between these sets, and show the number of elements of each section of the set.

  10. Cardinality of Sets Puzzle Solution 1. Every blip is a blop blop blop 5 blip bleep 15 20 blip 15 2. Half of all bleeps are blops blop bleep 0.5 blip The Answer is 5. 0.5 3. Half of all blops are blips n(blops) = 40 n(blips) = 20 n(bleeps) = 30 blop 0.5 No bleep is a blip bleep 0.5 0.5 blip 0.5

  11. This concludes Unit 4, Lecture C

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