E N D
Introduction Arithmetic sequences are linear functions that have a domain of positive consecutive integers in which the difference between any two consecutive terms is equal. Arithmetic sequences can be represented by formulas, either explicit or recursive, and those formulas can be used to find a certain term of the sequence or the number of a certain value in the sequence. An explicit formula is a formula used to find the nth term of a sequence and a recursive formula is a formula used to find the next term of a sequence when the previous term is known. 3.8.1: Arithmetic Sequences
Key Concepts An arithmetic sequence is a list of terms separated by a common difference, the number added to each consecutive term in an arithmetic sequence. An arithmetic sequence is a linear function with a domain of positive consecutive integers in which the difference between any two consecutive terms is equal. The rule for an arithmetic sequence can be expressed either explicitly or recursively. 3.8.1: Arithmetic Sequences
Key Concepts, continued The explicit rule for an arithmetic sequence is an= a1 + (n – 1)d, where a1 is the first term in the sequence, n is the term, d is the common difference, and an is the nth term in the sequence. The recursive rule for an arithmetic sequence is an= an – 1 + d, where an is the nth term in the sequence, an – 1is the previous term, and d is the common difference. 3.8.1: Arithmetic Sequences
Common Errors/Misconceptions identifying a non–arithmetic sequence as arithmetic defining the common difference, d, in a decreasing sequence as a positive number incorrectly using the distributive property when finding the nth term with the explicit formula forgetting to identify the first term when defining an arithmetic sequence recursively 3.8.1: Arithmetic Sequences
Guided Practice Example 2 Write a linear function that corresponds to the following arithmetic sequence. 8, 1, –6, –13, … 3.8.1: Arithmetic Sequences
Guided Practice: Example 2, continued Find the common difference by subtracting two successive terms. 1 – 8 = –7 3.8.1: Arithmetic Sequences
Guided Practice: Example 2, continued Confirm that the difference is the same between all of the terms. –6 – 1 = –7 and –13 – (–6) = –7 3.8.1: Arithmetic Sequences
Guided Practice: Example 2, continued Identify the first term (a1). a1 = 8 3.8.1: Arithmetic Sequences
Guided Practice: Example 2, continued Write the explicit formula. an = a1 + (n – 1)dExplicit formula for any given arithmetic sequence an= 8 + (n – 1)(–7) Substitute values for a1and d. 3.8.1: Arithmetic Sequences
Guided Practice: Example 2, continued Simplify the explicit formula. an = 8 – 7n + 7 Distribute–7 over (n – 1). an= –7n + 15 Combinelike terms. 3.8.1: Arithmetic Sequences
Guided Practice: Example 2, continued Write the formula in function notation. ƒ(x) = –7x + 15 Note that the domain of an arithmeticsequenceispositive consecutiveintegers. ✔ 3.8.1: Arithmetic Sequences
Guided Practice: Example 2, continued 12 3.8.1: Arithmetic Sequences
Guided Practice Example 3 An arithmetic sequence is defined recursively by an= an – 1 + 5, with a1 = 29. Find the first 5 terms of the sequence, write an explicit formula to represent the sequence, and find the 15th term. 3.8.1: Arithmetic Sequences
Guided Practice: Example 3, continued Using the recursive formula: a1 = 29 a2 = a1 + 5 a2= 29 + 5 = 34 a3 = 34 + 5 = 39 a4 = 39 + 5 = 44 a5 = 44 + 5 = 49 The first five terms of the sequence are 29, 34, 39, 44, and 49. 3.8.1: Arithmetic Sequences
Guided Practice: Example 3, continued The first term is a1 = 29 and the common difference is d = 5, so the explicit formula is an = 29 + (n – 1)5. 3.8.1: Arithmetic Sequences
Guided Practice: Example 3, continued Simplify. an = 29 + 5n – 5 an= 5n + 24 Combine like terms. 3.8.1: Arithmetic Sequences
Guided Practice: Example 3, continued Substitute 15 in for n to find the 15th term in the sequence. a15 = 5(15) + 24 a15= 75 + 24 a15= 99 The 15th term in the sequence is 99. ✔ 3.8.1: Arithmetic Sequences
Guided Practice: Example 3, continued 3.8.1: Arithmetic Sequences