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Chapter 7; Chapter 8. KD5 Conservation of momentum and energy. Review: Momentum. Momentum - Mass in motion momentum = mass X velocity Vector quantity (magnitude and direction). Review: Momentum. What are the 2 ways to increase momentum?
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Chapter 7; Chapter 8 KD5 Conservation of momentum and energy
Review: Momentum • Momentum - Mass in motion • momentum = mass X velocity • Vector quantity (magnitude and direction)
Review: Momentum • What are the 2 ways to increase momentum? • If the velocity of an object doubles, what happens to the momentum? • Which has more momentum a car moving down a hill or a roller skate moving with the same speed? • Which has more momentum a skateboard moving at 2 m/s or a truck at a red light? Increase mass OR increase velocity Momentum Doubles Car due to more mass with the same velocities Skateboard due to the Truck has no velocity Thus no momentum
Review: Momentum • Calculate the momentum of a 90 kg football player running at 6 m/s. 540 kg m/s
Law of Conservation • Physical properties in an isolated system don’t change • Just transferred from 1 object to another • Examples: • Law of Conservation of Momentum • Law of Conservation of Energy • Law of Conservation of Mass
Law of Conservation of Momentum • Example: 2 cars collide • The momentum of the 2 vehicles before the collision is equal to the total momentum of the 2 vehicles after the collision • The momentums of each car might change but the total momentum remains the same
Law of Conservation of Momentum • The total momentum of any closed, isolated system does not change • Momentum is NEVER lost! • Just transferred
Law of Conservation of Momentum • p = p or • m1v1 + m2v2 = m1v1 + m2v2
Example • A ball with a mass of 0.10 kg moves to the right with a speed of 2.0 m/s. It hits a .040 kg ball which is standing still. After the balls hit, the 2nd ball moves to the right with a speed of 0.80 m/s. What is the velocity of the 1st ball?
Answer • A ball with a mass of 0.10 kg moves to the right with a speed of 2.0 m/s. It hits a .040 kg ball which is standing still. After the balls hit, the 2nd ball moves to the right with a speed of 0.80 m/s. What is the velocity of the 1st ball? m(ball 1) v(ball 1) + m(ball 2) v(ball 2) = m(ball 1) v(ball 1) + m(ball 2) v(ball 2) .1kg (2.0 m/s) + .04kg (0 m/s) = .1 kg (v) + .04 (.8 m/s) .2 + 0 = .1 (v) + .032 .168 = .1 (v) 1.68 = v
Collisions • p (before a collision or explosion) = p (after a collision or explosion)
2 Types of Collisions • 1. Elastic Collision-Objects hit and bounce off • Both momentum and kinetic energy are conserved • Ex) Pool balls collide
2 Types of Collisions • 2. Inelastic Collision-Objects hit and stick together • Only momentum is conserved • Ex) 2 cars collide and stick together
Energy • Energy-The ability to do work • Forms of energy: • Electrical • Chemical • Solar • Thermal • Mechanical
Mechanical Energy • 1. Kinetic energy • 2. Gravitational Potential Energy • 3. Elastic Potential Energy
Mechanical Energy: Kinetic • Kinetic Energy-Energy of motion • KE = ½ mv² • m=mass (kg) • v=velocity (m/s) • KE=kinetic energy (J)
Mechanical Energy: Gravitational • Gravitational Potential Energy-Stored energy of position • GPE = m g h • m=mass (kg) • g=9.8 m/s² • h=height (m) • GPE=gravitational potential energy (J)
Mechanical Energy: Elastic • Elastic Potential Energy-Stored energy of stretch or compression • EPE = ½ k x² • k=elastic constant (N/m) • x=distance stretched/compressed from rest (m) • EPE=elastic potential energy (J)
Law of Conservation of Energy • The total energy of a system remains constant • Energy is neither created or destroyed (only transferred to another form) • Total Energy Before = Total Energy After • KE + GPE + EPE = KE´ + GPE´ + EPE´
“The Process” to Solve Energy Problems • 1. Sketch a picture of the problem • 2. Identify the types of mechanical energy present at the important stages of the problem • 3. Set the before energies equal to the after • 4. Substitute • 5. Solve and Label
Example: • Bill throws a 0.1 kg ball straight up with a speed of 7.5 m/s. How high did the ball go?
Remember • Bill throws a 0.1 kg ball straight up with a speed of 7.5 m/s. How high did the ball go? • KE + GPE + EPE = KE´ + GPE´ + EPE´ ½ mv2 + mgh + 1/2 kx2 = ½ mv2 + mgh + 1/2 kx2 Only velocity to start with (only KE) = Only height to end with (only GPE) ½ m v2 = mgh ½ (.1 kg) (7.5 m/s)2 = .1kg (9.8 m/s2) v2