270 likes | 812 Views
Electron Count Oxidation State Coordination Number. Basic tools for understanding structure and reactivity. Doing them should be “automatic”. Not always unambiguous Þ don’t just follow the rules, understand them!. The basis of counting electrons.
E N D
Electron CountOxidation StateCoordination Number Basic tools for understandingstructure and reactivity. Doing them should be “automatic”. Not always unambiguous Þ don’t just follow the rules, understand them! Counting Electrons
The basis of counting electrons • Every element has a certain number of valence orbitals: 1 (1s) for H 4 (ns, 3´np) for main group elements 9 (ns, 3´np, 5´(n-1)d) for transition metals s px py pz dxy dxz dyz dx2-y2 dz2 Counting Electrons
The basis of counting electrons • Every orbital wants to be “used", i.e. contribute to binding an electron pair. • Therefore, every element wants to be surroundedby 2/8/18 electrons. • The strength of the preference for electron-precise structures depends on the position of the element in the periodic table. Counting Electrons
The basis of counting electrons • Too few electrons: An empty orbital makes the compound very electrophilic,i.e. susceptible to attack by nucleophiles. • Too many electrons: There are fewer covalent bonds than one would think (not enough orbitals available). An ionic model is required to explain part of the bonding. The "extra" bonds are relatively weak. • Metal-centered (unshared) electron pairs: Metal orbitals are fairly high in energy. A metal atom with a lone pair is a strong s-donor (nucleophile) and susceptible to electrophilic attack. Counting Electrons
Use a localized (valence-bond) modelto count electrons H2 Every H has 2 e. OK CH4 H has 2 e, C 8. OK NH3 N has 8 e. Nucleophile! OK Counting Electrons
C2H4 C has 8 e. OK singlet CH2 C has only 6 e, and an empty pz orbital: extremely reactive ("singlet carbene"). Unstable. Sensitive to nucleophiles and electrophiles. triplet CH2 C has only 6 e, is a "biradical" and extremely reactive ("triplet carbene"), but not especially for nucleophiles or electrophiles. Counting Electrons
CH3+ C has only 6 e, and an empty pz orbital: extremely reactive. Unstable. Sensitive to nucleophiles. CH3- C has 8 e, but a lone pair. Sensitive to electrophiles. Cl- Cl has 8 e, 4 lone pairs. OK Somewhat sensitive to electrophiles. Counting Electrons
BH3 B has only 6 e, not stable as monomer,forms B2H6: B2H6 B has 8 e, all H's 2 (including the bridgingH!). 2-electron-3-center bonds! OK AlCl3 Al has only 6 e, not stable as monomer,forms Al2Cl6: Al2Cl6 Al has 8 e, all Cl's too (including thebridging Cl!). Regular2-electron-2-center bonds! OK Counting Electrons
2 MeAlCl2® Me2Al2Cl4 2-electron-3-center bonds are a stopgap! H3B·NH3 N-B: donor-acceptor bond (nucleophile NH3 has attacked electrophile BH3). Organometallic chemists are "sloppy" and write . Writing or would be more correct (although the latter does not reflect the “real” charge distribution). Counting Electrons
PCl5 P would have 10 e, but only has 4 valence orbitals, so it cannot form more than 4 “net” P-Cl bonds.You can describe the bonding using ionic structures (hyperconjugation). Easy dissociation in PCl3 en Cl2. HF2- Write as FH·F-, mainly ion-dipole interaction. Counting Electrons
How do you count? • Number of valence electrons(from periodic table) • Correct for charge, if any(only if it belongs to that atom!) • Count 1 e for every covalent bond to another atom • Count 2 e for every dative bond from another atom • Add Counting Electrons
Examples: counting electrons Pd = 10 - = 1 3´Cl = 3 1´NH3 = 2 tot = 16 could have additional 2 e(Pd-Cl p-bond?) B = 3 - = 1 4´H = 4 tot = 8 OK C = 4 1´=O = 2 2´H = 2 tot = 8 OK Ru = 8 2´Cl = 2 2´PMe3 = 4 1´CH2 = 2 tot = 16 could have additional 2 e Counting Electrons
Counting is not always trivial Pd = 10 2´- = 2 3´Cl = 3 1´CH2 = 1 tot = 16 could have additional 2 e Counting Electrons
Remember, when counting: • Odd electron counts are rare. • In reactions you nearly always go from even to even (or odd to odd), and from n to n-2, n or n+2. • Electrons don’t just “appear” or “disappear”. • The optimal count is 2/8/18 e. 16 e also occurs frequently, other counts are much more rare. Counting Electrons
Oxidation States Most elements have a clear preference for certain oxidation states. These are determined by (a.o.) electronegativity and the number of valence electrons: Li: nearly always +1.Has only 1 valence electron, so cannot go higher. Is very electropositive, so doesn’t want to go lower. Cl: nearly always -1.Already has 7 valence electrons, so cannot go lower.Is very electronegative, so doesn’t want to go higher. Counting Electrons
Calculating theformal oxidation state • Start with the formal charge on the metal • Ignore dative bonds • Ignore bonds between atoms of the same element (this one is a bit silly) • Assign every covalent electron pair to the most electronegative element in the bond: this produces + and – charges (usually + at the metal) • Add Counting Electrons
Examples: oxidation states charge Al = -1 4´Al-Cl: Al+-Cl- = +4 tot = +3 charge Pd = -2 4´Pd-Cl: Pd+-Cl- = +4 tot = +2 charge C = 0 4´C-Cl: C+-Cl- = +4 tot = +4 charge C = 0 2´C-Cl: C+-Cl- = +2 1´C=O: C2+-O2- = +2 tot = +4 charge Mn = -1 4´Mn=O: Mn2+-O2- = +8 tot = +7 Counting Electrons
Examples: oxidation states charge Pt = -2 3´Pt-Cl: Pt+-Cl- = +3 tot = +1 univalent Pt ? charge C = 0 3´C-Cl: C+-Cl- = +3 tot = +3 trivalent carbon ? charge Mg = 0 4´Mg-Me: Mg+-Me- = +4 tot = +4 impossible, Mg has only 2 valence electrons! Counting Electrons
The significance ofan oxidation state ? Oxidation states are formal. However, they do give an indication whether a structure or composition is reasonable (apart from the M-M complication). Counting Electrons
Acceptable oxidation states For group n or n+10: • never >+n or <-n (except group 11: frequently +2 of +3) • usually even for n even, odd for n odd • usually ³ 0 for metals • usually +n for very electropositive metals • usually 0-3 for 1st-row transition metals of groups 6-11, often higher for 2nd and 3rd row • electronegative ligands (F,O) stabilize higher oxidation states, p-acceptor ligands (CO) stabilize lower oxidation states • oxidation states usually change from m to m-2, m or m+2 in reactions Counting Electrons
Coordination number Simply the number of atoms directly bonded to the atom you are interested in, regardless of bond orders etc. CH4: 4 C2H4: 3 C2H2: 2 AlCl4-: 4 Me4Zn2-: 4 OsO4: 4 B2H6: 4 (B) 1 (terminal H) 2 (bridging H) Counting Electrons
Coordination Number For complexes with p-system ligands, the whole ligand is usually counted as 1: Cyclopentadienyl groups are sometimes counted as 3,because a single Cp group can replace 3 individual ligands: C.N. 4 Counting Electrons
Coordination Number The most common coordination numbers for organometallic compounds are: 2-6 for main group metals 4-6 for transition metals Coordination numbers >6 are relatively rare. So are very low coordination numbers (<4) together with a “too-low” electron count. Counting Electrons
Coordination number and coordination geometry C.N. "Normal" geometry 2 linear or bent 3 planar trigonal, pyramidal, "T-shaped" 4 square planar, tetrahedral 5 square pyramid, trigonal bipyramid 6 octahedron Counting Electrons
Illustration:protonation of WH6(PMe3)3 Could WH6(PMe3)3 be ? Count W: 18 VE (OK), oxidation state 6 (OK), coordination number 9 (very high). Possible. Protonation gives WH7(PMe3)3+. Could that be ? Count W: 18 VE (OK), oxidation state 8 (too high), coordination number 10 (extremely high). W+ must form 7 covalent bonds using only 5 electrons. That will not work! Counting Electrons
Exercises Give electron count and oxidation state for the following compounds. Draw conclusions about their (in)stability. Me2Mg Pd(PMe3)4 MeReO3 ZnCl4 Pd(PMe3)3 OsO3(NPh) ZrCl4 ZnMe42- OsO4(pyridine) Co(CO)4- Mn(CO)5- Cr(CO)6 V(CO)6- V(CO)6 Zr(CO)64+ PdCl(PMe3)3 RhCl2(PMe3)2 Ni(PMe3)Cl4 Ni(PMe3)Cl3 Ni(PMe3)2Cl2 Counting Electrons