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EXAMPLE 4

x. 5. x. 5. a. =. 16. 10. 16. 10. Solve the proportion. ALGEBRA. a. =. 5 16. =. 80. 10 x. =. 10 x. 8. x. =. EXAMPLE 4. Solve proportions. SOLUTION. Write original proportion. Cross Products Property. Multiply. Divide each side by 10. 1. 1. 2. 2. b. =.

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EXAMPLE 4

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  1. x 5 x 5 a. = 16 10 16 10 Solve the proportion. ALGEBRA a. = 5 16 = 80 10 x = 10 x 8 x = EXAMPLE 4 Solve proportions SOLUTION Write original proportion. Cross Products Property Multiply. Divide each side by 10.

  2. 1 1 2 2 b. = y + 1 y + 1 3y 3y b. = 1 3y 2 (y + 1) = 3y 2y + 2 = y 2 = EXAMPLE 4 Solve proportions SOLUTION Write original proportion. Cross Products Property Distributive Property Subtract 2y from each side.

  3. 2 2 5 5 5. = x 8 8 x = 2 8 5 x = 16 5 x = 16 x = 5 for Example 4 GUIDED PRACTICE SOLUTION Write original proportion. Cross Products Property Multiply. Divide each side by 5 .

  4. 1 1 4 4 6. = x – 3 3x x – 3 3x = 3x = 4(x – 3) 3x = 4x – 12 3x – 4x = – 12 – x x – 12 12 = = for Example 4 GUIDED PRACTICE SOLUTION Write original proportion. Cross Products Property Multiply. Subtract 4x from each side.

  5. y – 3 y y 7. = = 7 14 14 y – 3 7 = 7 y 14(y – 3) 14y – 42 = 7y 14y –7y = 42 y 6 = for Example 4 GUIDED PRACTICE SOLUTION Write original proportion. Cross Products Property Multiply. Subtract 7y from each side and add 42 to each side. Subtract , then divide

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