110 likes | 263 Views
ME 221 Statics Lecture #37 Sections 8.1 – 8.3. Homework #12. Chapter 8 problems: 1, 2, 4, 8 & 15 Due Today. No Class Friday, December 5. Quiz #8. Today Friction problem. Final Exam. Section 1 (3:00pm) Monday, 12/8, 3:00 – 5:00pm Section 2 (12:40pm) Wednesday, 12/10, 12:45 – 2:45pm
E N D
ME 221 StaticsLecture #37Sections 8.1 – 8.3 Lecture 36
Homework #12 Chapter 8 problems: • 1, 2, 4, 8 & 15 Due Today Lecture 36
No ClassFriday, December 5 Lecture 36
Quiz #8 Today Friction problem Lecture 36
Final Exam Section 1 (3:00pm) Monday, 12/8, 3:00 – 5:00pm Section 2 (12:40pm) Wednesday, 12/10, 12:45 – 2:45pm See University policy for multiple exams Lecture 36
Chapter 8 - Friction • Last Lecture • Coulomb Friction • Coefficients – static & kinematic • Friction angle • Today • Wedges Lecture 36
Coulomb Friction (dry friction) • Friction force (ƒ) is proportional to the normal force (N) and opposes motion • Coefficient of friction, m, is the proportionality constant f • Static coefficient, ms msN • Kinematic coefficient, mk mkN W f=P P f P N Lecture 36
Friction: Wedges • Wedges are a simple means for lifting • Again, friction force opposes the motion • FBDs are essential for solving problems • Apply equilibrium equations to FBDs Lecture 36
Friction: Wedges • Wedges may exert large normal forces • Used to lift heavy objects • Also used for splitting • Friction holds wedge in place • May be used in pairs Lecture 36
Wedges • The angle θ is called the wedge angle, and it determines the amount of force P required to raise the weight W, as well as the change in height of the weight as the wedge is driven into place. W • In equilibrium (P = 0): • ƒ cos θ – N sin θ = 0 • μs = tan θ P f N Lecture 36
Example Problem Lecture 36