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Chapter 7: Momentum

Chapter 7: Momentum. Chapter 7.1: Momentum—Inertia in Motion. 22 km/h. 5225 kg. 75 km/h. 1540 kg. Momentum = mass x velocity or momentum = mv. Which has greater momentum?. Chapter 7.2: Impulse Changes Momentum. Egg drop challenge.

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Chapter 7: Momentum

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  1. Chapter 7: Momentum

  2. Chapter 7.1: Momentum—Inertia in Motion 22 km/h 5225 kg 75 km/h 1540 kg • Momentum = mass x velocity or momentum = mv Which has greater momentum?

  3. Chapter 7.2: Impulse Changes Momentum Egg drop challenge The greater the force acting on an object, the greater its velocity and momentum. Time is also a factor in determining momentum. How long is force applied? Impulse = force x time interval orimpulse = Ft Impulse = change in momentum

  4. Chapter 7.2: Increasing Momentum To increase momentum, force must be applied as hard as possible for as long as possible. This is why follow through is important in a golf swing or in baseball. Impact force hard and fast = maximum impulse Impact measured in N. Impulse measured in N-s

  5. Chapter 7.2: Decreasing Momentum To decrease the force of impact, the impact time (time during which momentum is brought to zero) must be lengthened.

  6. Chapter 7.2: Decreasing Momentum To decrease the force of impact, the impact time (time during which momentum is brought to zero) must be lengthened.

  7. Chapter 7.2: Decreasing Momentum

  8. Chapter 7.2: Decreasing Momentum

  9. Chapter 7.2: Decreasing Momentum

  10. Chapter 7.2: Decreasing Momentum Momentum (mv) is what is gained by the Jumper until the chord begins to stretch.

  11. Chapter 7.2: Decreasing Momentum Momentum (mv) is what is gained by the Jumper until the chord begins to stretch. Ft is the impulse the cord supplies to reduce the momentum to zero. Because of the long time it takes the cord to stretch, the average force (F) on the jumper is minimal.

  12. Chapter 7.2: Decreasing Momentum Yowza! Yowza!

  13. Chapter 7.3: Bouncing Flower pot on the head example Pelton Wheel

  14. Chapter 7.4: Conservation of Momentum • Law of conservation of momentum: In the absence of an external force, the momentum of a system remains unchanged. The bullet gains momentum and so does the rifle, but the rifle-bullet system gains none. See skateboarder example pg 94.

  15. Chapter 7.5: Collisions • When objects collide in the absence of external forces, the net momentum of both objects before the collision equals the net momentum of both objects after the collision. net momentum before collision = net momentum after collision Elastic collision—when objects collide without being deformed permanently or generating heat. Inelastic collision—when colliding objects become tangled or coupled together

  16. Chapter 7.5: Elastic Collisions • The sum of the momentum vectors are the same before and after the collisions.

  17. Chapter 7.5: Inelastic Collisions V = 12 m/s V = 0 • If mass is equal, the momentum is shared equally after the collision by each of the objects. V = 6 m/s

  18. Chapter 7.5: Inelastic Lunch 3 m/s 20 kg 5 kg v = 0

  19. Chapter 7.5: Inelastic Lunch 5 kg v = 0 (net mv) before = (net mv) after (20 kg)(3 m/s)+(5 kg)(0 m/s) = (25 kg)(v after) (60 kg*m/s)+(5 kg) = (25 kg)(v after) (65 kg*m/s) = (25 kg)(v after) 2.6 m/s = (v after) 25 kg 2.6 m/s

  20. Chapter 7.5: Inelastic Lunch 5 kg 3 m/s 20 kg 2 m/s

  21. Chapter 7.5: Inelastic Lunch 5 kg v = 0 (net mv) before = (net mv) after (20 kg)(3 m/s)+(5 kg)(-2 m/s) = (25 kg)(v after) (60 kg*m/s)+(-10 kg*m/s) = (25 kg)(v after) (50 kg*m/s) = (25 kg)(v after) 2 m/s = (v after) 2 m/s 25 kg

  22. Chapter 7.5: Inelastic Lunch 5 kg 10 m/s 3 m/s 20 kg

  23. Chapter 7.5: Inelastic Lunch 5 kg v = 0 (net mv) before = (net mv) after (20 kg)(3 m/s)+(5 kg)(-20 m/s) = (25 kg)(v after) (60 kg*m/s)+(-100 kg*m/s) = (25 kg)(v after) (-40 kg*m/s) = (25 kg)(v after) -1.6 m/s = (v after) 1.6 m/s 25 kg

  24. Chapter 7.6: Momentum Vectors

  25. Chapter Review

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