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XII CBSE Previous Year Question Paper

XII CBSE Previous Year Question Paper. QUESTION NO 1 (E) 2 or 3 Marks. 1 (e) Find the output of the following program : Delhi 2006 2 #include<iostream.h> void main( ) { long NUM= 1234543; int F=0, S=0; do { int Rem = NUM% 10 ; if (Rem % 2 !=0) F+=R; else S+=R; NUM /=10;

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XII CBSE Previous Year Question Paper

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  1. XII CBSE Previous Year Question Paper QUESTION NO 1 (E) 2 or 3 Marks

  2. 1 (e) Find the output of the following program : Delhi 2006 2 #include<iostream.h> void main( ) { long NUM= 1234543; int F=0, S=0; do { int Rem = NUM% 10 ; if (Rem % 2 !=0) F+=R; else S+=R; NUM /=10; }while(NUM>0); cout<<F-S; }

  3. Ans: (e) 2 (assuming R as Rem) (2 marks for correct output as 2) OR (2 marks for identifying error as R is not declared) OR (Full 2 marks to be awarded to the students who have scored at least 1 mark in the entire Q. No. 1 i.e. from 1(a) to 1(f))

  4. 2 (e) Find the output of the following program : OD 2006 2 #include<iostream.h> void main() { long Number = 7583241; int First=0, Second=0; do { int R = Number%10; if(R%2==0) First+=R; else Second+=R; Number /=10; }while(Number>0); cout<<First-Second; }

  5. (e) -2 (Full 2 marks for correct output) OR (Full 2 marks for mentioning values of First as 14 and Second as 16, as representation of minus sign is not very prominent) OR (Full 2 marks for mentioning syntax error with justification as insertion operator << expected in between First and Second)

  6. 3 (e) Find the output of the following program : Delhi 2007 3 #include<iostream.h> void Indirect(int Temp=20) { for (int 1=10; I<=Temp; I+=5) cout<<I<<” , “ ; cout<<endl; } void Direct (int &Num) { Num+=10; Indirect(Num); }

  7. 3 (e) Find the output of the following program : Delhi 2007 3 void main() { int Number=20; Direct(Number) ; Indirect(); cout<< “ Number=” <<Number<<endl ; }

  8. (e) • 10, 15, 20, 25, 30, • 10, 15, 20, • Number=30 • (1 Mark for each correct line of output) • Note: • · ½ Mark to be deducted for missing Commas (,) in each line of output • · ½ Mark to be deducted if endl is not considered in the output

  9. 4 (e) Find the output of the following program : OD 2007 3 # include < iostream.h> void Withdef (int HisNum = 30) { for (int 1=20 ; I<*= HisNum; I+=5) cout<<I<<””; cout<<endl; } void Control (int &MyNum) { MyNum+=10; Withdef(MyNum); }

  10. 4 (e) Find the output of the following program : OD 2007 3 void main () { int YourNum=20; Control (YourNum); Withdef(); cout<<”Number=”<<YourNum<<endl; }

  11. (e) • 20,25,30, • 20,25,30, • Number=30 • (1 Mark for each correct line of output) • Note: • · ½ Mark to be deducted for missing Commas (,) in the output • · ½ Mark to be deducted if endl is not considered in the output

  12. 5 (e) Find the output of the following program: Delhi 2008 2 #include<iostream.h> void main ( ) { int U = 10, V = 20; for (int I = 1; 1 < = 2; 1++) { cout<<“[1]=”<<U++<<“&”<<V–5<<endl; cout<<“[2]=”<<++V<<“&”< <U+ 2< <endl; } }

  13. Ans: Nnd@*Xrk!* (½ Mark for N in the 1st position) (½ Mark for nd in the 2nd and 3rd position) (½ Mark for @ in the 4th position) (½ Mark for * in the 5th position) (½ Mark for Xrk!) (½ Mark for * at the end) OR (Fu1l 3 Marks If error is mentioned in the code for Text (I) after last else)

  14. 6 (e) Find the output of the following program : OD 2008 2 #include<iostream.h> void main ( ) { int A=5, B=10; for (int I = 1; I<=2; 1++) { cout<< “Linel=”<<A++<<“&”<<B–2<<endl; cout<<“Line2=”<<++B<<“&”<<A+3<<endl; } }

  15. Ans: • Line1=5&8 • Line2=11&9 • Line1=6&9 • Line2=12&10 • (½ Mark for each correct line of output) • Note: . • ½ Mark to be deducted for missing Ampersand (&) in each line of output • ½ Mark to be deducted if endl is not considered in the output

  16. 7 (e) Find the output of the following program : Delhi 2009 2 #include<iostream.h> #include<ctype.h> void Encode (char Info [ ], int N) ; void main ( ) { char Memo [ ] = “Justnow” ; Encode(Memo, 2) ; cout<<Memo<<endl ; }

  17. 7 (e) Find the output of the following program : Delhi 2009 2 void Encode(char Info[ ], int N) { for (int I = 0 ; Info[I] != ‘\0’ ; 1++) if (1%2= =0) Info[I] = Info[I] –N ; else if (islower(Info[I])) Info[I] = toupper(Info[I]) ; else Info[I] = Info[I] +N ; }

  18. Ans HuqTlOu (½ Mark for writing H, U as the first two characters) (½ Mark for writing q, T as the next two characters) (½ Mark for writing 1, O as the next two characters) (½ Mark for writing u as the last character)

  19. 8 (e) Find the output of the following program: OD 2009 2 #include <iostream.h> #include <ctype.h> void Secret (char Mig [ ], int N); void main ( ) { char SMS[ ] = “rEPorTmE” ; Secret{SMS,2); cout<<SMS<<end1; }

  20. 8 (e) Find the output of the following program: OD 2009 2 void Secret(char Msg[ ], int N) { for (int C=0; Msg[C] ! =’ \0' ;C++) if (C%2==0) Msg[C] = Msg[C]+N; else if (isupper(Msg[C])) Msg[C] = tolower(Msg[C]); else Msg[C] = Msg[C]-N; }

  21. Ans teRmttoe (½ Mark for writing t,e as the first two characters) (½ Mark for writing R,m as the next two characters) (½ Mark for writing t,t as the next two characters) (½ Mark for writing o,e as the next two characters)

  22. 9 (e) Find the output of the following program : Delhi 2010 2 #include <iostream.h> #include <ctype.h> void ChangeIt(char Text[ ], char C) { for (int K=0;Text[K]!='\0';K++) { if (Text[K]>=’F’ && Text[K]<=’L’) Text[K]=tolower(Text[K]); else if (Text[K]=’E’ || Text[K]==’e’) Text[K]= =C;

  23. 9 (e) Find the output of the following program : Delhi 2010 2 else if (K%2==O) Text[K]=toupper(Text[K]); else Text[K]=Text[K-l]; } }

  24. 9 (e) Find the output of the following program : Delhi 2010 2 void main ( ) { char OldText[ ]=”pOwERALone”; ChangeIt(OldText,’%’); cout<<“New TEXT:”<<OldText<<endl; }

  25. Ans. • 16, 24, 6 • 6, 34, 16 • 18, 22, 28 • (1 Mark for each line with -correct values) • OR • (½ Mark for any two correct values in each line) • Note: • Deduct (½ Mark if any/all ‘,’ missing • Deduct (½ Mark if endl is not considered at the right positions

  26. 10 (e) Find the output of the following program: OD 2010 2 #include <iostream.h> #include <ctype.h> void MyCode (char Msg [], char CH) { for (int (Cnt=O;Msg[Cnt]!=’\0';Cnt++) { if (Msg[Cnt]>=’B’ && Msg[Cnt]<=’G’) Msg[Cnt]=tolower(Msg[Cnt]); else if (Msg[Cnt]==’A’|| Msg[Cnt]==’a’) Msg[Cnt]=CH;

  27. 10 (e) Find the output of the following program: OD 2010 2 else if (Cnt%2==0) Msg[Cnt]=toupper(Msg[Cnt]); else Msg[Cnt]=Msg[Cnt-l]; } } void main () { char MyText [] =” ApEACeDriVE”; MyCode(MyText,’@’); cout<<“NEW TEXT:”<<MyText<<endl; }

  28. Ans. NEW TEXT :@@e@ccddIIe (½ Mark for writing @,@,e as the first three characters) (½ Mark for writing @,c,c as the next three characters) (½ Mark for writing d,d, I as the next three characters) (½ Mark for writing I,e as the next two characters) Note: Deduct ½ Mark for not mentioning NEW TEXT:

  29. 11 (e) Find the output of the following program: Delhi 2011 2 #include<iostream.h> void main ( ) { int Track [ ] = {10, 20, 30, 40}, *Striker ; Stxiker=Track : Track [1] += 30 ; cout<<"Striker>"<<*Striker<<end1 ; Striker – =10 ; Striker++ ; cout<<"Next@"<<*Striker<<end1 ; Striker+=2 ; cout<<"Last@"<<*Striker<<end1 ; cout<< "Reset To" <<Track[0] <<end1 ; }

  30. Ans • Striker>10 • Next@50 • Last@40 • Reset to 0 • (½ for writing each line of output correctly) • Note: • Deduct ½ Mark if any/all special characters are missing • Deduct ½ Mark if endl is not considered at the right positions

  31. 12 (e) Find the output of the following program: OD 2011 2 #include<iostream.h> void main ( ) { int *Queen, Moves [ ] = {11, 22, 33, 44}; Queen = Moves; Moves [2] + = 22; cout<< "Queen @"<<*Queen<<end1; *Queen - = 11; Queen + = 2; cout<< "Now @"<<*Queen<<end1; Queen++; cout<< "Finally@"<<*Queen«end1; cout<< "New Origin @"<<Moves[0]<<end1; }

  32. Ans • Queen @11 • Now @55 • Finally @44 • New origin @0 • (½ Mark for writing each line of output correctly) • Note: • Deduct ½ Mark if any/all '@' missing or/and endl is not considered at the right positions

  33. 13 (e) Find the output of the following program: SAMPLE PAPER 2009 SET I 2 #include <iostream.h> #include <ctype.h> void Encrypt(char T[]) { for (int i=0;T[i]!='\0';i+=2) if (T[i]=='A' || T[i]=='E') T[i]='#'; else if (islower(T[i])) T[i]=toupper(T[i]); else T[i]='@'; }

  34. 13 (e) Find the output of the following program: SAMPLE PAPER 2009 SET I 2 void main() { char Text[]="SaVE EArtH";//The two words in the string Text //are separated by single space Encrypt(Text); cout<<Text<<endl; }

  35. Answer: @a@E@E#rTH (1 Mark for writing all alphabets at correct positions) (1/2 Mark for writing @ at correct positions) (1/2 Mark for writing # at correct position)

  36. 14 (e) Find the output of the following program: SAMPLE PAPER 2009 SET II 2 #include <iostream.h> struct Game { char Magic[20];int Score; }; void main() { Game M={“Tiger”,500}; char *Choice;

  37. 14 (e) Find the output of the following program: SAMPLE PAPER 2009 SET II 2 Choice=M.Magic; Choice[4]=’P’; Choice[2]=’L’; M.Score+=50; cout<<M.Magic<<M.Score<<endl; Game N=M; N.Magic[0]=’A’;N.Magic[3]=’J’; N.Score-=120; cout<<N.Magic<<N.Score<<endl; }

  38. Answer: • TiLeP550 • AiLJP430 • (1 Mark for each line of output)

  39. 15 (e) Find the output of the following program: SAMPLE PAPER 2010 SET I 2 #include <iostream.h> void Secret(char Str[ ]) { for (int L=0;Str[L]!='\0';L++); for (int C=0;C<L/2;C++) if (Str[C]=='A' || Str[C]=='E') Str[C]='#'; else { char Temp=Str[C];

  40. 15 (e) Find the output of the following program: SAMPLE PAPER 2010 SET I 2 Str[C]=Str[L-C-1]; Str[L-C-1]=Temp; } } void main() { char Message[ ]="ArabSagar"; Secret(Message); cout<<Message<<endl; }

  41. ANS: #agaSbarr (2 Marks for correct line of output)

  42. 16 (e) Find the output of the following program: SAMPLE PAPER 2010 SET II 2 #include <iostream.h> struct Game { char Magic[20];int Score; }; void main() { Game M={"Tiger",500}; char *Choice;

  43. 16 (e) Find the output of the following program: SAMPLE PAPER 2010 SET II 2 Choice=M.Magic; Choice[4]='P'; Choice[2]='L'; M.Score+=50; cout<<M.Magic<<M.Score<<endl; Game N=M; N.Magic[0]='A';N.Magic[3]='J'; N.Score-=120; cout<<N.Magic<<N.Score<<endl; }

  44. ANS: • TiLeP550 • AiLJP430 • (1 Mark for each line of output)

  45. 17 SAMPLE PAPER 2012 SET I

  46. 17 SAMPLE PAPER 2012 SET I

  47. 17 SAMPLE PAPER 2012 SET I

  48. 18 SAMPLE PAPER 2012 SET II

  49. 18 SAMPLE PAPER 2012 SET II

  50. THANK YOU

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