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May 3, 2012. AGENDA: 1 – Bell Ringer & Part. Log 2 – Review HW 3 – CN: Charles’ Law 4 – Video Demo 5 – Work Time. Today’s Goal: Students will be able to calculate using Charles’ Law. Homework Charles’ Law Work from Week 32 is due by Tomorrow. Make up QUIZ 16 by Monday. Compare
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May 3, 2012 AGENDA: 1 – Bell Ringer & Part. Log 2 – Review HW 3 – CN: Charles’ Law 4 – Video Demo 5 – Work Time Today’s Goal: Students will be able to calculate using Charles’ Law. Homework • Charles’ Law • Work from Week 32 is due by Tomorrow. • Make up QUIZ 16 by Monday.
Compare Formulate Support • Topic:Charles’ Law • Date:5/3/2012 • Charles’ Law = For a given amount of gas at a constant pressure, the VOLUME of the gas is directly related to TEMPERATURE. • So if: T ↑ = V ↑ T ↓ = V ↓ T α V Constant Pressure Volume Temperature
Compare Formulate Support • Topic:Charles’ Law • Date:5/3/2012 • Temperature = Kelvin (K) • Volume = (mL, L) • To convert to Kelvin: K = °C + 273 • For example: If 25°C, what is K temp? K = 25°C + 273 K = 298 K
Compare Formulate Support • Topic:Charles’ Law • Date:5/3/2012 V1 = V2 T1 T2 V1T2 = V2T1
Compare Formulate Support • Topic:Charles’ Law • Date:5/3/2012 • A balloon is at RT (25°C). The volume of the balloon is 2.0L. The balloon is then taken outside to a temperature of -5°C. What is the new volume of the balloon? V1 = V2 T1 T2 2 = V2 298 268 V2 = 1.8L V1=2.0L T1=25°C+273=298K V2=? T2=-5°C+273=268K
http://www.youtube.com/watch?v=ZgTTUuJZAFs Demonstration of Charles’ Law