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Outline: 4/11/07

Outline: 4/11/07. CAPA 18 due tonight… CAPA 19 due Friday… Special seminar Thursday pm Special seminar Friday 4pm Pick up Quiz 8 – from me Pick up grade summary – in front. Today: Finish Chapter 19. Coulomb Calculations Redox Applications. Outline: 4/11/07.

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Outline: 4/11/07

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  1. Outline: 4/11/07 • CAPA 18 due tonight… • CAPA 19 due Friday… • Special seminar Thursday pm • Special seminar Friday 4pm • Pick up Quiz 8 – from me • Pick up grade summary – in front Today: Finish Chapter 19 • Coulomb Calculations • Redox Applications

  2. Outline: 4/11/07 • CAPA 18 due tonight… • CAPA 19 due Friday… • Special seminar Thursday pm • Special seminar Friday 4pm • Pick up Quiz 8 – from me • Pick up grade summary – in front Today: Finish Chapter 19 SC 1019 6-8pm Panel @ 8pm • Coulomb Calculations • Redox Applications

  3. Outline: 4/11/07 • CAPA 18 due tonight… • CAPA 19 due Friday… • Special seminar Thursday pm • Special seminar Friday 4pm • Pick up Quiz 8 – from me • Pick up grade summary – in front Today: Finish Chapter 19 • Coulomb Calculations • Redox Applications

  4. Quiz #7 • Average = 8.2 Good!

  5. Chapter 19 practice problems: 19.1, 19.3, 19.5, 19.9, 19.11, 19.13, 19.15, 19.17, 19.19, 19.21, 19.23, 19.25, 19.27, 19.33, 19.35, 19.37, 19.39, 19.41, 19.45, 19.49, 19.53, 19.55, 19.63, 19.65, 19.67, 19.69, 19.73, 19.77, 19.81, 19.83, 19.85

  6. Grade Summary Go over grade summary sheet • 8 quizzes / 70 pts (drop one) • 4 pts/seminar report extra credit • CAPA through 17; w/out a few handins • Exam 1, Exam 2 added at 20 or 15% • Final exam 60% or 75% or 90%... • Please see me if there is an data entry error

  7. Calculational Example: • A lead-acid battery: • PbO2+HSO4-+2H++Pb 2PbSO4 +2H2O • Assume 250 g of PbO2 and that this battery supplies 6 Amps until it dies; how long will it last? Finish Chapter 19: • Current = charge/time • 1 Ampere = 1 Coulomb / second

  8. PbO2  PbSO4 (+4  +2) : 2e •  1.045 mol PbO2 × 2 mol e / mol PbO2= • 2.090 mol e • 250 g PbO2 × 1 mol/ 239.2 g = • 1.045 mol PbO2 • 2.090 mol e × 96485 C/mol = • 201654 C • (time) × (6 C/sec) = 201654 C •  time = 3361 sec = 9.34 hours

  9. Problem #3 - Worksheet #12: • Current calculation…. • Which equations? • What is the limiting reagent? • How many moles? • How much time at 0.2 mA?

  10. HgO Hg (+2  0) : 2e • Zn ZnO (0  +2) : 2e • Worksheet #12 • Moles of everything: • 1 g HgO × 1mol/216.6g = 0.00462 mol • 1 g Zn × 1mol/65.4g = 0.01530 mol • What is the limiting reagent? • HgO • Moles of electrons: • 0.00462l mols HgO × 2 mols e-/mol HgO

  11. Moles e- to Coulombs conversion: • 0.00924 mol e- × 96485 C/mol e- • = 891.5 C = 891.5 Amp . sec • How long? • 891.5 Amp . sec = (x sec)(0.2×10-3 Amp) • x = 4.46×106 sec = 1238 hours • Practice! Practice!Practice!Practice!

  12. Redox applications: • Batteries • Fuel Cells • Electroplating • Ore Extraction/Mining • Rust Protection • Metallurgy/Alloys • Electrolysis • Read pp. 847 - 857 in textbook

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