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Lecture #7. What makes a good eye? Part I. Resolution Land and Nilsson first half of chapter 3 2 /14/13. Two key features of an eye. Resolution (today) Precision with which eye can resolve or distinguish a spatial image Sensitivity (next time) How much light can be detected by the eye.
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Lecture #7 What makes a good eye? Part I. Resolution Land and Nilsson first half of chapter 3 2/14/13
Two key features of an eye • Resolution (today) • Precision with which eye can resolve or distinguish a spatial image • Sensitivity (next time) • How much light can be detected by the eye
Eye design • Optical devices are subject to laws of physics and optimized by the engineers who design them • Eyes are subject to laws of physics and optimized by evolution
Vertebrate eye - single lens which transfers image to retina
Spatial resolution depends on cone spacing Wolfe et al Sensory Perception fig 2.9
Human retinal mosaic in fovea JW temporal nasal AN nasal Huge variation from person to person in distribution of cones and in M/L cone ratios! Roorda and Williams 1999
Optimizing resolution • Receptor size and spacing • Lens focal length • Optical imperfections
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Low Resolution High Resolution Why does this even exist?
Reasons that points of light might end up as blurred points of light • Lens does not focus perfectly • Aberration = imperfection • Cornea, lens or humours scatter some of light • Diffraction • When light goes through an aperture, it gets diffracted
Optimal receptor spacing to resolve objects • Need enough photoreceptors to define boundaries between objects
Optimal receptor spacing • If receptors are too big (spaced too coarsely) they can’t resolve fine detail
Want optimal receptor spacing • No reason to have more receptors than this as they won’t resolve the images any better
Refraction: Light bends at interface Bigger incident angle = more bending Less dense More dense
Lens focal length, f • Focal length is distance at which parallel light is focused f
Lens focal length • Determined by curvature of lens surface Lens radius of curvature Curvature as if cut lens out of surface of sphere with that radius
Lens focal length • Determined by curvature of lens surface Radius of curvature of sphere that matches lens’s curvature
Lens focal length is determined by curvature of lens surfaces Large radius of curvature = large focal length Small radius of curvature = small focal length
Lens focal length • Determined by curvature of lens surface For thin lens
Lens focal length How can we make focal length longer? If lens is symmetric, R1=-R2=R If lens is flat on one side, R2=∞
Physics lens equation f Distance of image and object in relation to lens focal length Object Image dO di
So di = f Physics lens equation If dO, object distance is very large dO>>di O I dO di
Note: both cornea and lens focus the light so retina is located at combined focal length of lens and cornea Retina
Eye resolution Determine resolution based on how well can resolve a periodic pattern or grating One period of grating
Quantifying resolution • Minimum resolvable grating will match receptor spacing • If receptor spacing is s then grating covers 2s on retina • Angle = 2s / f Angle f 2s
Angle s f One cycle of grating covers two photoreceptors • Angle = 2s / f • So can resolve one cycle if it covers no less than that angle • Max resolvable spatial frequency • v = 1 / angle of one grating cycle = f / 2s
Angles grating retina θ Tanθ= 2s / f But for small θ tanθ=θ So θ= 2s/f 2s f θ is in radians!
Angle θ s f Interreceptor angle • Angle between two adjacent photoreceptors • θ= s / f
One cycle of grating covers two photoreceptors • To cover full cycle of grating the angle is 2θ= 2s / f • Maximum resolvable spatial frequency, v • v = 1/2θ= f/ 2s Angle 2θ s f
Δρ f d Minimum receptor acceptance angle • Another angle: • Δρ minimum receptor acceptance angle • f eye focal length = distance to retina • d receptor diameter • Resolution =1/ Δρ= f/d In general s ≈ d and 2s/f ≈ 2d/f
Δρ Angle 2θ=2s/f s f f d Two ways to characterize eye resolution • Maximum resolvable spatial frequency, v = f/2s Inter-receptor spacing, Δρ = d/f Grating resolution = f / 2s Receptor resol = 1/Δρ= f/d = f /s
Some typical spatial frequencies - Vertebrate eyes Δρ= 0.0036º * π / 180 º = 6.28 x 10-5 rad
Some typical spatial frequencies - Vertebrate eyes Δρ= 0.0036º * π / 180 º = 6.28 x 10-5 rad v = 1 / 2Δρ = 1 / (2*6.28 x 10-5) = 7960 cycles / rad
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How can we modify an eye to get high acuity night vision?
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Image size relative to object size: Similar triangles • f is focal length of the eye • O = object size • I = image size • U=distance to object • O / U= I / f f
Image size relative to object size: Similar triangles O • O / U= I / f • f is focal length of the eye • O = object size • I = image size • U=distance to object Magnification = I / O = f / U U f I