7. ½ NO 2 - + ½ H 2 O = ½ NO 3 - + H+ + e log K = -14.1 ¼ O 2 + H + = ½ H 2 O log K = 20.8
7. ½ NO 2 - + ½ H 2 O = ½ NO 3 - + H+ + e log K = -14.1 ¼ O 2 + H + = ½ H 2 O log K = 20.8 Which sum to give, ½ NO 2 - + ¼ O 2 = ½ NO 3 - log K = 6.7 With an overall reaction and log K of, NO 2 - + ½ O 2 = NO 3 - log K = 13.4 From the 1 st ½-reaction multiplied by 2,
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