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Mendelian Genetics. More Genetics Problems. Linked Genes. Chromosomal Disorders. Bio Trivia. 5 pt. 5 pt. 5 pt. 5 pt. 5 pt. 10 pt. 10 pt. 10 pt. 10 pt. 10 pt. 15 pt. 15 pt. 15 pt. 15 pt. 15 pt. 20 pt. 20 pt. 20 pt. 20 pt. 20 pt. 25 pt. 25 pt. 25 pt. 25 pt. 25 pt.
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Mendelian Genetics More Genetics Problems Linked Genes Chromosomal Disorders Bio Trivia 5 pt 5 pt 5 pt 5 pt 5 pt 10 pt 10 pt 10 pt 10 pt 10 pt 15 pt 15 pt 15 pt 15 pt 15 pt 20 pt 20 pt 20 pt 20 pt 20 pt 25 pt 25 pt 25 pt 25 pt 25 pt
I 5 If a man with Huntington’s marries a normal female, what percentage of the offspring are likely to have Huntington's?
I 5a If a man with Huntington’s marries a normal female, what percentage of the offspring are likely to have Huntington's? 50%
I 10 The ability of one gene to control the expression of another gene is known as ____________.
I 10a The ability of one gene to control the expression of another gene is known as episatsis.
I 15 In the cross: RrTt x Rrtt, what is the probability of getting an offpring that is dominant for both traits?
I 15a In the cross: RrTt x Rrtt, what is the probability of getting an offpring that is dominant for both traits? ¾ x ½ = 3/8
I 20 What is the probability of flipping a tails three times in a row?
I 20a What is the probability of flipping a tails three times in a row? ½ x ½ x ½ = 1/8
I 25 An AABb individual is mated with another AABb individual. The possible number of genetically different kinds of offspring is _____.
I 25a An AABb individual is mated with another AABb individual. The possible number of genetically different kinds of offspring is3.
II 5 If one parent is blood type AB and the other is type O, what fraction of their offspring will be blood type A?
II 5a If one parent is blood type AB and the other is type O, what fraction of their offspring will be blood type A? ½
II 10 The result of the following cross indicates the orange eyes are _____ black eyes.
II 10a The result of the following cross indicates the orange eyes are recessive to black eyes.
II 15 If a parent is AaBBCcddEe, how many different types of gametes can it produce?
II 15a If a parent is AaBBCcddEe, how many different types of gametes can it produce? 2 x 1 x 2 x 1 x 2 = 8
II 20 • A woman is A+ and has B- child. A father with this blood type could NOT be the father: • A+ • B- • AB + • AB-
II 20a • A woman is A+ and has B- child. A father with this blood type could NOT be the father: • A+
II 25 An organism homozygous for red color was crossed with an organism homozygous for blue color. The offspring were green. Two of the green organisms were crossed. What is (are) the expected phenotypes in this second group of offspring?
II 25a An organism homozygous for red color was crossed with an organism homozygous for blue color. The offspring were green. Two of the green organisms were crossed. What is (are) the expected phenotypes in this second group of offspring? 1 Red: 2 green: 1 blue
III 5 If two genes are linked _____. a. they are on different chromosomes b. they assort independently c. they code for the same protein d. they are on the same chromosome
III 5a If two genes are linked _____. d. they are on the same chromosome
III 10 If a color-blind woman marries a man with normal vision, the female offspring will be __________, and the male offspring will be __________.
III 10a If a color-blind woman marries a man with normal vision, the female offspring will be normal, and the male offspring will be color-blind.
III 15 Four genes (A, B, C, and D) are on the same chromosome. The crossover frequencies below are obtained. What is the correct sequence of genes? A-B 19% A-D 21%B-C 14% C-D 16% A-C 5% B-D 2%
III 15a Four genes (A, B, C, and D) are on the same chromosome. The crossover frequencies below are obtained. Which is the correct sequence of genes? A-B 19% A-D 21%B-C 14% C-D 16% A-C 5% B-D 2% ACBD or DBCA
III 20 • A father (whose father was color-blind) and a normal woman can produce: • a color-blind son • a color-blind daughter • no color-blind children • sons that have a 50% chance of being color-blind.
III 20a • A father (whose father was color-blind) and a normal woman can produce: • C. no color-blind children
III 25 In a particular species of mammal,black hair (B) is dominant to green hair (b), and red eyes (R) are dominant to white eyes (r). When a BbRr individual is mated with a bbrr individual, the observed offspring are: black-red 1,070; black-white 177; green-red 180; green-white 1,072. How far apart are the B and R genes?
III 25a In a particular species of mammal,black hair (B) is dominant to green hair (b), and red eyes (R) are dominant to white eyes (r). When a BbRr individual is mated with a bbrr individual, the observed offspring are: black-red 1,070; black-white 177; green-red 180; green-white 1,072. How far apart are the B and R genes? 14.3 MU
IV 5 A chart of chromosomes in which they are arranged by number is called a _________________.
IV 5a A chart of chromosomes in which they are arranged by number is called a karyotype.
IV 10 A male with a Barr body has what disorder?
IV 10a A male with a Barr body has what disorder? Klinefelter’s Syndrome XXY
IV 15 The exchange of parts between nonhomologous chromosomes is called _____.
IV 15a The exchange of parts between nonhomologous chromosomes is called translocation.
IV 20 The only known viable human monosomy is:
IV 20a The only known viable human monosomy is Turner’s Syndrome.
IV 25 • If non-disjunction occurs in Meiosis I, what types of gametes will be produced? • n and n + 1 • n and n-1 • C. n + 1 and n – 1 • D. n, n + 1, and n - 1
IV 25a • If non-disjunction occurs in Meiosis I, what types of gametes will be produced? • C. n + 1 and n – 1
V 5 • Who am I? • Mendel b. Morgan • c. Kleinfelter d. Turner
V 5a Who am I? b. Thomas Hunt Morgan
V 10 • Ophioglossum reticulatum, a type of fern, has the most chromosomes of any organism. How many chromosomes does each cell have? • 110 b. 256 • c.1260 d. 2448
V 10a • Polyploidy is a common conduction in plants, but seemingly taken to its limits in the Ophioglossum reticulatum. This fern has roughly 630 pairs of chromosomes or 1260 chromosomes per cell
V 15 What is this condition called?
V 15a Polydactyly
V 20 • If you read 5 bases/second, how long would it take you to read the entire human genome (without stopping)? • 7 years b. 19 years • c. 48 years d. 87 years
V 20a It would take 19 years to read aloud without stopping, at 5 bases per second, the entire sequence of the genome within the nucleus of the human embryo
V 25 Why was Aberforth Dumbledore prosecuted?