1 / 50

difference between input voltages to op amp is very small because voltage gain a is very large input impedance ri i

ME 6405 Introduction to Mechatronics. Contents. IntroductionTheoryA. Definition and presentationB. Linear ModeC. Non Linear Mode Real Operational AmplificatorsUses ConclusionReferences. ME 6405 Introduction to Mechatronics. Definition and presentation. Theory. Operational Amplifier (Op Amp)Definition: a high gain electronic amplifying circuit element in a feedback amplifier, that accomplishes many functions or mathematical

jacob
Download Presentation

difference between input voltages to op amp is very small because voltage gain a is very large input impedance ri i

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

    1: ME 6405 INTRODUCTION TO MECHATRONICS:

    2: ME 6405 Introduction to Mechatronics

    3: ME 6405 Introduction to Mechatronics Definition and presentation

    4: ME 6405 Introduction to Mechatronics Definition and presentation

    5: ME 6405 Introduction to Mechatronics Definition and presentation

    6: ME 6405 Introduction to Mechatronics

    7: ME 6405 Introduction to Mechatronics Definition and presentation

    8: ME 6405 Introduction to Mechatronics Difference between input voltages to Op Amp is very small because voltage gain (A) is very large Input impedance (Ri) is large

    9: ME 6405 Introduction to Mechatronics Transfer Characteristic: Modes + saturation ( ) - saturation ( ) linear ( )

    10: ME 6405 Introduction to Mechatronics Op Amp transfer characteristic relation

    11: ME 6405 Introduction to Mechatronics Analysis We assume that the Op-Amp gain is very high, effectively infinity. It is assumed that the amplifier operates in its linear amplifying region. ( for e.g. -10V < eo < 10V )

    12: ME 6405 Introduction to Mechatronics Analysis The difference between input voltages to the op amp is very small, essentially 0. The input impedance to the op-amp is extremely large.

    13: ME 6405 Introduction to Mechatronics Analysis For e.g. if |eo | < 10V and K = 105 then |e+ - e’| =10/105 = 100 ?V For the inverting amplifier, e+ is grounded. Hence e+ 0 and e’ 0

    14: ME 6405 Introduction to Mechatronics The equation for this circuit can be obtained as follows:

    15: ME 6405 Introduction to Mechatronics Since K (0 - e’) = e0 and K >>>1, then e’ 0 since

    16: ME 6405 Introduction to Mechatronics Hence we have or

    17: ME 6405 Introduction to Mechatronics For the non-inverting amplifier the input is connected to the non-inverting input. The same assumptions have been made as in the case of the Inverting Op Amp

    18: ME 6405 Introduction to Mechatronics For this circuit we have , where K is the differential gain of the amplifier.

    19: ME 6405 Introduction to Mechatronics This leads to A particular form of this amplifier is when the feedback loop is a short circuit, I.e. R2 = 0. Then the voltage gain is 1, such an amplifier is called a Voltage Follower.

    20: ME 6405 Introduction to Mechatronics An inverting amplifier can accept two or more inputs and produce a weighted sum At X, I = IA + IB + IC and we can see that:

    21: ME 6405 Introduction to Mechatronics By utilizing the usual assumptions, we obtain:

    22: ME 6405 Introduction to Mechatronics A differential amplifier is one that amplifies the difference between two voltages

    23: ME 6405 Introduction to Mechatronics The current through the feedback resistance must be equal to that from V1 through R1

    24: ME 6405 Introduction to Mechatronics Hence which can be rearranged to give,

    25: ME 6405 Introduction to Mechatronics Potential Difference across capacitor = VX - Vout q = CV

    26: ME 6405 Introduction to Mechatronics Rearranging this gives Integrating both sides gives

    27: ME 6405 Introduction to Mechatronics Non Linear Mode

    28: ME 6405 Introduction to Mechatronics Non Linear Mode

    29: ME 6405 Introduction to Mechatronics Non Linear Mode

    30: ME 6405 Introduction to Mechatronics Non Linear Mode

    31: ME 6405 Introduction to Mechatronics Non Linear Mode

    32: ME 6405 Introduction to Mechatronics Non Linear Mode

    33: ME 6405 Introduction to Mechatronics Non Linear Mode

    34: ME 6405 Introduction to Mechatronics Non Linear Mode

    35: ME 6405 Introduction to Mechatronics Non Linear Mode

    36: ME 6405 Introduction to Mechatronics Internal electrical schema

    37: ME 6405 Introduction to Mechatronics Input Characteristics

    38: ME 6405 Introduction to Mechatronics Input Characteristics

    39: ME 6405 Introduction to Mechatronics Transfer Characteristics

    40: ME 6405 Introduction to Mechatronics Output Characteristics

    41: ME 6405 Introduction to Mechatronics Output Characteristics

    42: ME 6405 Introduction to Mechatronics Summary

    43: ME 6405 Introduction to Mechatronics Summary

    44: ME 6405 Introduction to Mechatronics Summary

    45: ME 6405 Introduction to Mechatronics Solutions

    46: ME 6405 Introduction to Mechatronics Solutions

    47: ME 6405 Introduction to Mechatronics Practical Applications

    48: ME 6405 Introduction to Mechatronics Characteristics / Numbers

    49: ME 6405 Introduction to Mechatronics CONCLUSION

    50: ME 6405 Introduction to Mechatronics REFERENCES

More Related