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7.1 Apply the Pythagorean Theorem

7.1 Apply the Pythagorean Theorem . Objectives. Use the Pythagorean Theorem Recognize Pythagorean Triples. The Pythagorean Theorem.

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7.1 Apply the Pythagorean Theorem

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  1. 7.1 Apply the Pythagorean Theorem

  2. Objectives Use the Pythagorean Theorem Recognize Pythagorean Triples

  3. The Pythagorean Theorem Theorem 7.1In a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.a2 + b2 = c2

  4. Proof of Pythagorean Theorem STATEMENTS • Perpendicular Postulate • Geometric Mean Theorem • Cross Product Property 1. c a c b = = a e b f 2. 3. ce = a2 and cf = b2 REASONS Draw a ┴ from C to AB and 4. ce + cf = a2 + b2 4. Addition Property 5. c(e + f) = a2 + b2 5. Distributive Property 6. Segment Add. Postulate 6. e + f = c 7. c2 = a2 + b2 7. Substitution Property

  5. Example 1: Find d.

  6. Example 1: Answer: Pythagorean Theorem Simplify. Subtract 9 from each side. Take the square root of each side. Use a calculator.

  7. Example 2: LONGITUDE AND LATITUDE Carson City, Nevada, is located at about 120 degrees longitude and 39 degrees latitude. NASA Ames is located about 122 degrees longitude and 37 degrees latitude. Use the lines of longitude and latitude to find the degree distance to the nearest tenth degree if you were to travel directly from NASA Ames to Carson City.

  8. The change in latitude is or 2 degrees latitude. Let this distance be b. Example 2: The change in longitude between NASA Ames and Carson City is or 2 degrees. Let this distance be a. Use the Pythagorean Theorem to find the distance in degrees from NASA Ames to Carson City, represented by c.

  9. Example 2: Pythagorean Theorem Simplify. Add. Take the square root of each side. Use a calculator. Answer: The degree distance between NASA Ames and Carson City is about 2.8 degrees.

  10. Your Turn: Answer: Find x.

  11. Example 3: Find the area of the isosceles triangle. 13 m 13 m h 5 m 5 m

  12. Example 3: Use Pythagorean Theorem to find the height of the . 132 = 52 + h2 Pythagorean Theorem 169 = 25 + h2 Simplify. 144 = h2 Subtract 25 from each side. 12 = h Take the square root of each side. Solve for Area of a  A = ½ (bh) = ½ (10)(12) Answer: 60 m2

  13. Pythagorean Triples A Pythagorean Triple is three whole numbers that satisfy the equation a2+ b2 = c2 , where the longest side is the hypotenuse, c, and aand b are the two legs. Some common Pythagorean Triples are: 3, 4, 5 5, 12, 13

  14. Example 4a: Determine whether 9, 12, and 15are the sides of a right triangle. Then state whether they form a Pythagorean triple. Since the measure of the longest side is 15, 15 must be c. Let a and b be 9 and 12. Pythagorean Theorem Simplify. Add.

  15. Example 4a: Answer: These segments form the sides of a right triangle since they satisfy the Pythagorean Theorem. The measures are whole numbers and form a Pythagorean triple.

  16. Example 4b: Answer: Since , segments with these measures cannot form a right triangle. Therefore, they do not form a Pythagorean triple. Determine whether 21, 42, and 54are the sides of a right triangle. Then state whether they form a Pythagorean triple. Pythagorean Theorem Simplify. Add.

  17. Example 4c: Determine whether 4, and 8 are the sides of a right triangle. Then state whether they form a Pythagorean triple. Answer: Since 64 = 64, segments with these measures form a right triangle. However, is not a whole number. Therefore, they do not form a Pythagorean triple. Pythagorean Theorem Simplify. Add.

  18. Your Turn: Determine whether each set of measures are the sides of a right triangle. Then state whether they form a Pythagorean triple. a. 6, 8, 10b. 5, 8, 9c. Answer: The segments form the sides of a right triangle and the measures form a Pythagorean triple. Answer: The segments do not form the sides of a right triangle,and the measuresdo not forma Pythagorean triple. Answer: The segments form the sides of a right triangle, but the measures do not form a Pythagorean triple.

  19. Assignment Geometry:Workbook Pgs. 124 – 126 #1 - 38

  20. 7.2 Use the Converse of the Pythagorean Theorem

  21. Objectives Use the Converse of the Pythagorean Theorem Classify triangles using Pythagorean Thereom

  22. Converse of the Pythagorean Theorem Theorem 7.2If the square of the length of the longest side of the triangle is equal to the sum of the squares of the lengths of the other two sides, then the triangle is a right triangle. If c2 = a2 + b2, then ∆ABC is a right triangle.

  23. Example 1: Tell whether a triangle with the given sides is a right triangle or not. a. 10, 11, 14 b. 14, 22, 26c. 4, 4 3, 8 a. No, not a right  b. No, not a right  c. Yes, it is a right 

  24. Example 2: COORDINATE GEOMETRY Verify that is a right triangle.

  25. Example 2: Use the Distance Formula to determine the lengths of the sides. Subtract. Simplify. Subtract. Simplify.

  26. Example 2: Subtract. Simplify. By the converse of the Pythagorean Theorem, if the sum of the squares of the measures of two sides of a triangle equals the square of the measure of the longest side, then the triangle is a right triangle.

  27. Example 2: Answer: Since the sum of the squares of two sides equals the square of the longest side, is a right triangle. Converse of the Pythagorean Theorem Simplify. Add.

  28. Your Turn: COORDINATE GEOMETRY Verify that is a right triangle. Answer: is a right triangle because

  29. Classifying s Using Pythagorean Theorem Theorem 7.3If the square of the length of the longest side of the triangle is less than the sum of the squares of the lengths of the other two sides, then the triangle is an ACUTE . If c2<a2 + b2, then ∆ABC is an acute triangle. Theorem 7.4If the square of the length of the longest side of the triangle is greater than the sum of the squares of the lengths of the other two sides, then the triangle is an OBTUSE . If c2>a2+ b2, then ∆ABC is an obtuse triangle.

  30. Example 1: Tell whether the following segment lengths form a ∆, and if so classify the ∆ as acute, right, or obtuse. a. 3, 4, 6 b. 4.3, 5.2, 6.1 c. 7, 9.1, 16.2 a. Yes, it is an obtuse  b. Yes, it is an acute  c. No, it is not a 

  31. Assignment Geometry:Workbook Pgs. 127 – 129 #1 – 25

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