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KINETICS CH14 # 53A

KINETICS CH14 # 53A. GIVEN k 1 AT T 1 , FIND k 2 AT T 2. ln[k 1 /k 2 ] = (Ea/R) [1/T 2 – 1/T 1 ]. ln[ k 1 /k 2 ] = (Ea/R) [1/ T 2 – 1/ T 1 ]. ln[ k 1 /k 2 ] = (75.5 * 10 3 Jmol -1 /8.134Jmol -1 ) [1/ 333 – 1/ 293 ]. ln[ k 1 /k 2 ] = -3.7229. [ k 1 /k 2 ] = 0.0242.

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KINETICS CH14 # 53A

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  1. KINETICS CH14 # 53A GIVEN k1 AT T1, FIND k2 AT T2 ln[k1/k2] = (Ea/R) [1/T2 – 1/T1] ln[k1/k2] = (Ea/R) [1/T2 – 1/T1] ln[k1/k2] = (75.5 * 103 Jmol-1/8.134Jmol-1) [1/333 – 1/293] ln[k1/k2] = -3.7229 [k1/k2] = 0.0242 [k2] = 0.0275 s-1/0.0242 = 1.14 s-1

  2. KINETICS CH14 # 53B GIVEN k1 AT T1, FIND k2 AT T2 WHERE Ea=105*10-3 ln[k1/k2] = (Ea/R) [1/T2 – 1/T1] ln[k1/k2] = (Ea/R) [1/T2 – 1/T1] ln[k1/k2] = (105 * 103 Jmol-1/8.134Jmol-1) [1/333 – 1/293] ln[k1/k2] = -5.1776 [k1/k2] = 5.642*10-3 [k2] = 0.0275 s-1/5.642*10-3 = 4.88 s-1

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