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Math Journal 9-30. 2. 3. 4. Unit 3 Day 3: Solving Equations With Variables on Both Sides. Essential Questions: How do we solve equations with variables on both sides? When does an equation have no solution or many solutions?.
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Math Journal 9-30 • 2. • 3. 4.
Unit 3 Day 3: Solving Equations With Variables on Both Sides • Essential Questions: How do we solve equations with variables on both sides? When does an equation have no solution or many solutions?
Solving Equations With Variables on Both Sides 1) Simplify each side separately. 2) Use inverse operations to collect the variables on one side of the equation and the constants on the other side of the equation. 3) Continue to solve the equation.
9x • 3x • 9 • 3 • 3 • 9 • 9x • 3x • Example 1: Solve the equations. • a) 7x + 19 = -2x + 55 b) 6x + 22 = 3x + 31 • + 2x • + 2x • - 3x • - 3x • + 22 = 31 • + 19 = 55 • - 19 • -19 • - 22 • -22 • = 36 • = 9 • x = 4 • x = 3
80 • 16 • 15 • 15 • 6 • 6 • 6c • 80 • Example 2: Solve the equations. • a) 80 – 9y = 6y b) 10c = 24 + 4c • = y • = y • 15 • 3 • + 9y • + 9y • - 4c • - 4c • = 15y • = 24 • c = 4
4 + x • Example 3: Solve the equation. • 4(1 – x) + 3x = -2(x + 1) • x = -6 • 4 • - 4x • + 3x • = -2x • - 2 • 4 • - 1x • = - 2x - 2 • + 2x • + 2x • = - 2 • - 4 • - 4
13 • 13 • -36 • -26 • Example 4: Solve the equation. • 9(n – 4) – 7n = 5(3n – 2) • 9n • - 36 • - 7n • = 15n • - 10 • 2n • - 36 • = 15n - 10 • - 2n • - 2n • = 13n - 10 • + 10 • + 10 • = 13n • -2 = n
Equations With No Solution or Infinitely Many Solutions • Happens when the variable is eliminated and you are left with a true or false statement. • True Statement • Example: 5 = 5 • Infinitely Many Solutions • (any number substituted for the variable will work) • False Statement • Example: 5 = 2 • No Solution • (no number substituted for the variable will work)
24 • 3 • Example 5: Solve the equations. • a) x - 2x + 3 = 3 - x b) 5x + 24 = 5(x - 5) • -x + 3 = 3 - x • 5x + 24 • = 5x • - 25 • + x • + x • - 5x • - 5x • = 3 • = -25 • true statement • false statement • no solution • infinitely many solutions
.03 • .03 • .36 = .03x • Example 6: Phone Company A charges an activation fee of 36 cents and then 3 cents per minute. Phone Company B charges 6 cents per minute with no activation fee. How long is a call that costs the same amount no matter which company is used? • .36 + .03x = .06x • - .03x • - .03x • If you talk for more than ___minutes, Company __ has the better price. • 12 = x
150 + 3x = 195 • Example 7: Justin and Tyson are beginning an exercise program to train for football season. Justin weighs 150 pounds and hopes to gain 2 pounds per week. Tyson weighs 195 pounds and hopes to lose 1 pound per week. If the plan works, in how many weeks will the boys weigh the same amount? • 3x = 45 • Justin • Tyson • = 195 - 1x • 150 + 2x • + 1x • + 1x • In 15 weeks, Justin and Tyson will weigh the same amount. • - 150 • - 150 • x = 15
Essential Questions: How do we solve equations with variables on both sides? When does an equation have no solution or many solutions? • Take 1 minute to write 2 sentences answering the essential question. Summary