560 likes | 807 Views
INFO 2950. Prof. Carla Gomes gomes@cs.cornell.edu Module Modeling Computation: Finite State Machines without Output Rosen, Chapter 12.2 and 12.3. Finite-State Machines with No Output. Definition: Concatenation of A and B.
E N D
INFO 2950 Prof. Carla Gomes gomes@cs.cornell.edu Module Modeling Computation: Finite State Machines without Output Rosen, Chapter 12.2 and 12.3
Definition:Concatenation of A and B • A and B are subsets of V*, where V is a vocabularyThe concatenation of A and B isAB={xy: x string in A and y string in B} • Example: A={0, 11} and B={1, 10, 110}AB={01,010,0110,111,1110,11110} • What is BA? • A0={λ}An+1=AnA for n=0,1,2,…
Definition:Concatenation of A and B • Example: A={1,00} An ? n=1, 2, 3,… • A0 • A0={λ} • A1=A0A1={λ} A ? • A1=A0A1={λ} A={1,00} • A2=A1A ={1,00} {1,00} • A2=A1A ={1,00} {1,00} = {11,100,001,0000} • A3=A2A ={11,100,001,0000}{1,00} • A3=A2A ={11,100,001,0000}{1,00} = {111,1100,1001,10000,001111,00100,00001,000000}
Kleene Closure Let A be any subset of V*. Kleene closure of A, denoted by A*, is The set consisting of concatenations of arbitrarily many strings from A If B={0,1}, B*=V*.
Kleene Closure What are the Kleen closures of the set A={0}; B={0,1}, and C={11}? A*={,0,00,000,…} ={0n |n=0,1,2,…} If B={0,1}, B*=V*. (The set of all strings over the alphabet V) C*={,11,1111,111111,…} ={(11)n |n=0,1,2,…} ={12n |n=0,1,2,…}
Finite State AutomataRepresentations • As with finite-state machines, finite-state automata have the following common representations • A state tableis used to represent a finite-state automaton by giving the values of the function f. • Just like for finite-state machines, except the second half of the columns are omitted, since there is no output. • A state diagramis a directed graph representation of a finite-state automaton. • Final states are usually denoted by double-circles. • Values separated by commas denote several possible inputs, not inputs and outputs as with finite state machines.
Finite State Automata • A finite state automation over an alphabet is illustrated by a state diagram: • a directed graph • edges are labeled with elements of alphabet, • some nodes (or states), marked as final of “accepting”. • one node marked as start state
Dealing with Input Strings • Let x=x1x2…xnÎI *(That is, x is a string over I) • Then we can extend the transition function fto all state-input string pairs (rather than simply state-input pairs) in the obvious way • Assume the machine is in state S0, • Compute f(S0, x1) = Si2 • Next compute f(Si2, x2) = Si3 • Continue until you get f(Sin, xn) = Sin+1 • We define f(S0, x) = Sin+1 • From now on, we will speak of the transition function fbeing applied to input strings, not just single inputs.
Finite Automaton Input String Output “Accept” or “Reject” Finite Automaton
Transition Graph initial state accepting state transition state
Initial Configuration Input String
Input finished accept
Input finished reject
Input finished accept
Input finished reject
Finite-State Automata • Definition: A finite-state automatonis a 5-tuple M=(S, I, f, S0, F) where • S is a finite set of states • I is a finite input alphabet • f:S´I®S is a transition functionfrom each state-input pair to a state • S0is the initial state • FÍSis a set of final states • Note: automaton is the singular of automata.
Finite Automata • ’ • If end of input • If in accepting state => accept • Otherwise => reject • If no transition possible (got stuck) => reject
Language Recognition • Definition: A finite-state automaton accepts (or recognizes) a string x if f(S0, x)ÎF. That is, the finite state automaton ends up in a final state. • Definition: The language accepted (or recognized) by a finite-state automaton M, denoted by L(M), is the set of all strings recognized by M. • Definition: Two finite-state automata are equivalentif they recognize the same language.
Example accept
Example accept accept accept
Example trap state accept
What is the Language? • Example: What language is recognized by the following finite-state automaton? Input 0 or 1 • Solution: Since the only final state is the start state, and only an input of 1 will leave the machine in the start state, it is easy to see that • L(M)={1n: n=0,1,2,…}
What is the Language? • Example: What language is recognized by the following finite-state automaton? • Solution: Notice that • Any input that does not start with 0 cannot go to a final state • The final state can only be arrived at if the last input is a 1 • Any string can occur in between the first 0 and last 1. • Thus, we can see that • L(M)={binary strings beginning with 0 and ending with 1}
S1 FSM Examples Example: What language is recognized by the following finite-state automaton? 0 1 1 S0 0 Accepts strings over alphabet {0,1} that end in 1
S0 S2 S1 a b a b b b a a 4 5 b a FSM Examples Example: What language is recognized by the following finite-state automaton? Accepts strings over alphabet {a,b} that begin and end with same symbol
S0 FSM Examples Example: What language is recognized by the following finite-state automaton? 0 Accepts strings over {0,1,2} such that sum of digits is a multiple of 3 S1 Start 2 1 S2 0 1 2 0 2 1
0 0 1 Odd Even 1 FSM Examples Accepts strings over {0,1} that have an odd number of ones
0,1 1 1 0 0 '001' '0' '00' 1 0 FSM Examples Accepts strings over {0,1} that contain the substring 001
Examples • Design a FSM to recognize strings with an equal number of ones and zeros. • Not possible • Design a FSM to recognize strings with an equal number of substrings "01" and "10". • Perhaps surprisingly, this is possible
FSM Examples 0 1 1 0 0 Accepts strings with an equal number of substrings "01" and "10" 1 0 1 0 1
Non-deterministic Finite Automaton (NDFA) • a non-deterministic finite state machine or non-deterministic finite automaton (NDFA) is a finite state machine where for each pair of state and input symbol it assigns a set of states i.e., from a pair of state and input symbol there are possibly two or more transitions to a next state. • Every NDFA can be converted to a DFA