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Mrs.Volynskaya LITERAL EQUATIONS

Mrs.Volynskaya LITERAL EQUATIONS. A formula is a type of literal equation . A literal equation is an equation with two or more variables. To solve for one of the variables, use inverse operations. 1) Solve 2 x - 4y = 7 for x. 2 x - 4y = 7 + 4y + 4y 2 x = 7 + 4y

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Mrs.Volynskaya LITERAL EQUATIONS

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  1. Mrs.Volynskaya LITERAL EQUATIONS A formula is a type of literal equation. A literal equationis an equation with two or more variables. To solve for one of the variables, use inverse operations.

  2. 1) Solve 2x - 4y = 7 for x 2x - 4y = 7 + 4y + 4y 2x = 7 + 4y 2 2 • Add 4y to both sides • Simplify • Divide both sides by 2 • Does it simplify? This fraction cannot be simplified because both terms in the numerator are not divisible by 2.

  3. Answer Now 2) Solve 2x - 4y = 7 for yTo get y by itself, what is the first step? • Add 2x • Subtract 2x • Add 4y • Subtract 4y

  4. 3) Solve 2x - 4y = 7 for y 2x - 4y = 7 -2x - 2x -4y = 7 - 2x -4 -4 • Subtract 2x from both sides • Simplify • Divide both sides by -4 • Does it simplify? Nope!

  5. 4) Solve for y: 4x – 2y = 12 4x – 2y = 12 - 4x - 4x -2y = 12 – 4x -2 -2 y = -6 + 2x or y = 2x - 6 • Subtract 4x from both sides • Simplify • Divide both sides by -2 • Does it simplify? Yes!

  6. Answer Now 5) Solve for y: 4x – 2y = 12 • -4x + 12 • 4x - 12 • -2x + 6 • 2x - 6

  7. 9x – 7y = -7 1. Solve for x 2. Solve for y

  8. Lesson Quiz: Part I Solve for the indicated variable. 1. 2. 3. 2x + 7y = 14 for y 4. for h P = R – C for C C = R – P for m m = x(k – 6) 5. for C C = Rt + S

  9. Lesson Quiz: Part II Euler’s formula, V – E + F = 2, relates the number of vertices V, the number of edges E, and the number of faces F of a polyhedron. 6. Solve Euler’s formula for F. F = 2 – V + E 7. How many faces does a polyhedron with 8 vertices and 12 edges have? 6

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