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Explore the concept of projectile motion launched at an angle. Discover how the launch angle affects the maximum distance traveled in the x-direction. Consider air resistance and its impact on the motion.
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Projectile Motion Launched at an angle This will done qualitatively instead of quantitatively. So there will be no calculations.
What angle will get the maximum distance? (in the x direction) • Distance in the x direction depends on time and velocity in the x direction • Shooting it directly horizontally, will give you the fastest x velocity… • but it will also give you the shortest time in the air. You need to point it up to increase this. • Shooting it straight up will give you the maximum time in the air… • but it will also give you the slowest x velocity, actually zero x velocity. You need to tilt it down to increase this.
Diagrams horizontal vertical high angle low angle Maximum distance
An angle of 45o will give you the maximum distance in the x direction • If you consider air resistance you want it to be slightly less than 45o • If you are launching from some height above the ground, it will be less than 45o • The higher you go the smaller the angle will be approaching 0o but never getting there
Projectiles launched at an angle • vi in the y direction will no longer be 0 • Everything else stays the same from the calculation problems that we have been doing, this would only adding an extra step if we were to do the calculations.
Air resistance • Air resistance would decelerate motion in all directions. • The faster an object is moving, the more air resistance it will fell. • There is a point where the air resistance in the y direction will cancel out the acceleration due to gravity.
Does that mean it would stop falling? • NO!!!!!!! • It has to have a high velocity moving downward to reach the point where air resistance cancels out acceleration due to gravity. • This means it would no longer change its velocity. • This velocity is called terminal velocity.
