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1. 2. 2. 1. 1. 1. 1. …. 2. 2. 2. 2. …. K. …. …. …. …. x 1. K. K. K. K. x 2. x 3. x K. …. Hidden Markov Models. Variants of HMMs. Higher-order HMMs. How do we model “memory” larger than one time point? P( i+1 = l | i = k) a kl
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1 2 2 1 1 1 1 … 2 2 2 2 … K … … … … x1 K K K K x2 x3 xK … Hidden Markov Models
Higher-order HMMs • How do we model “memory” larger than one time point? • P(i+1 = l | i = k) akl • P(i+1 = l | i = k, i -1 = j) ajkl • … • A second order HMM with K states is equivalent to a first order HMM with K2 states aHHT state HH state HT aHT(prev = H) aHT(prev = T) aHTH state H state T aHTT aTHH aTHT state TH state TT aTH(prev = H) aTH(prev = T) aTTH
Similar Algorithms to 1st Order • P(i+1 = l | i = k, i -1 = j) • Vlk(i) = maxj{ Vkj(i – 1) + … } • Time? Space?
Modeling the Duration of States 1-p Length distribution of region X: E[lX] = 1/(1-p) • Geometric distribution, with mean 1/(1-p) This is a significant disadvantage of HMMs Several solutions exist for modeling different length distributions X Y p q 1-q
Solution 1: Chain several states p 1-p X Y X X q 1-q Disadvantage: Still very inflexible lX = C + geometric with mean 1/(1-p)
Solution 2: Negative binomial distribution Duration in X: m turns, where • During first m – 1 turns, exactly n – 1 arrows to next state are followed • During mth turn, an arrow to next state is followed m – 1 m – 1 P(lX = m) = n – 1 (1 – p)n-1+1p(m-1)-(n-1) = n – 1 (1 – p)npm-n p p p 1 – p 1 – p 1 – p Y X(n) X(1) X(2) ……
Example: genes in prokaryotes • EasyGene: Prokaryotic gene-finder Larsen TS, Krogh A • Negative binomial with n = 3
Solution 3: Duration modeling Upon entering a state: • Choose duration d, according to probability distribution • Generate d letters according to emission probs • Take a transition to next state according to transition probs Disadvantage: Increase in complexity of Viterbi: Time: O(D) Space: O(1) where D = maximum duration of state F d<Df xi…xi+d-1 Pf Warning, Rabiner’s tutorial claims O(D2) & O(D) increases
Viterbi with duration modeling emissions emissions Recall original iteration: Vl(i) = maxk Vk(i – 1) akl el(xi) New iteration: Vl(i) = maxk maxd=1…DlVk(i – d) Pl(d) akl j=i-d+1…iel(xj) F L d<Df d<Dl Pl Pf transitions xi…xi + d – 1 xj…xj + d – 1 Precompute cumulative values
A state model for alignment M (+1,+1) Alignments correspond 1-to-1 with sequences of states M, I, J I (+1, 0) J (0, +1) -AGGCTATCACCTGACCTCCAGGCCGA--TGCCC--- TAG-CTATCAC--GACCGC-GGTCGATTTGCCCGACC IMMJMMMMMMMJJMMMMMMJMMMMMMMIIMMMMMIII
Let’s score the transitions s(xi, yj) M (+1,+1) Alignments correspond 1-to-1 with sequences of states M, I, J s(xi, yj) s(xi, yj) -d -d I (+1, 0) J (0, +1) -e -e -AGGCTATCACCTGACCTCCAGGCCGA--TGCCC--- TAG-CTATCAC--GACCGC-GGTCGATTTGCCCGACC IMMJMMMMMMMJJMMMMMMJMMMMMMMIIMMMMMIII
Alignment with affine gaps – state version Dynamic Programming: M(i, j): Optimal alignment of x1…xi to y1…yjending in M I(i, j): Optimal alignment of x1…xi to y1…yj ending in I J(i, j): Optimal alignment of x1…xi to y1…yjending in J The score is additive, therefore we can apply DP recurrence formulas
Alignment with affine gaps – state version Initialization: M(0,0) = 0; M(i, 0) = M(0, j) = -, for i, j > 0 I(i,0) = d + ie; J(0, j) = d + je Iteration: M(i – 1, j – 1) M(i, j) = s(xi, yj) + max I(i – 1, j – 1) J(i – 1, j – 1) e + I(i – 1, j) I(i, j) = max d + M(i – 1, j) e + J(i, j – 1) J(i, j) = max d + M(i, j – 1) Termination: Optimal alignment given by max { M(m, n), I(m, n), J(m, n) }
Brief introduction to the evolution of proteins Protein sequence and structure Protein classification Phylogeny trees Substitution matrices
Actin sequence • Actin is ancient and abundant • Most abundant protein in cells • 1-2 actin genes in bacteria, yeasts, amoebas • Humans: 6 actin genes • -actin in muscles; -actin, -actin in non-muscle cells • ~4 amino acids different between each version MUSCLE ACTIN Amino Acid Sequence 1 EEEQTALVCD NGSGLVKAGF AGDDAPRAVF PSIVRPRHQG VMVGMGQKDS YVGDEAQSKR 61 GILTLKYPIE HGIITNWDDM EKIWHHTFYN ELRVAPEEHP VLLTEAPLNP KANREKMTQI 121 MFETFNVPAM YVAIQAVLSL YASGRTTGIV LDSGDGVSHN VPIYEGYALP HAIMRLDLAG 181 RDLTDYLMKI LTERGYSFVT TAEREIVRDI KEKLCYVALD FEQEMATAAS SSSLEKSYEL 241 PDGQVITIGN ERFRGPETMF QPSFIGMESS GVHETTYNSI MKCDIDIRKD LYANNVLSGG 301 TTMYPGIADR MQKEITALAP STMKIKIIAP PERKYSVWIG GSILASLSTF QQMWITKQEY 361 DESGPSIVHR KCF
Protein Phylogenies • Proteins evolve by both duplication and species divergence
Structure Determines Function The Protein Folding Problem • What determines structure? • Energy • Kinematics • How can we determine structure? • Experimental methods • Computational predictions
Primary Structure: Sequence • The primary structure of a protein is the amino acid sequence
Primary Structure: Sequence • Twenty different amino acids have distinct shapes and properties
Primary Structure: Sequence A useful mnemonic for the hydrophobic amino acids is "FAMILY VW"
Secondary Structure: , , & loops • helices and sheets are stabilized by hydrogen bonds between backbone oxygen and hydrogen atoms
PDB Growth New PDB structures
Protein classification • Number of protein sequences grows exponentially • Number of solved structures grows exponentially • Number of new folds identified very small (and close to constant) • Protein classification can • Generate overview of structure types • Detect similarities (evolutionary relationships) between protein sequences • Help predict 3D structure of new protein sequences Classification of 27,599 protein structures in PDB
Protein world Protein structure classification Protein fold Protein superfamily Protein family Morten Nielsen,CBS, BioCentrum, DTU
Structure Classification Databases • SCOP • Manual classification (A. Murzin) • scop.berkeley.edu • CATH • Semi manual classification (C. Orengo) • www.biochem.ucl.ac.uk/bsm/cath • FSSP • Automatic classification (L. Holm) • www.ebi.ac.uk/dali/fssp/fssp.html Morten Nielsen,CBS, BioCentrum, DTU
Major classes in SCOP • Classes • All a proteins • All b proteins • a and b proteins (a/b) • a and b proteins (a+b) • Multi-domain proteins • Membrane and cell surface proteins • Small proteins • Coiled coil proteins Morten Nielsen,CBS, BioCentrum, DTU
All a: Hemoglobin (1bab) Morten Nielsen,CBS, BioCentrum, DTU
All b: Immunoglobulin (8fab) Morten Nielsen,CBS, BioCentrum, DTU
a/b:Triosephosphate isomerase (1hti) Morten Nielsen,CBS, BioCentrum, DTU
a+b: Lysozyme (1jsf) Morten Nielsen,CBS, BioCentrum, DTU
Families • Proteins whose evolutionarily relationship is readily recognizable from the sequence (>~25% sequence identity) • Families are further subdivided into Proteins • Proteins are divided into Species • The same protein may be found in several species Fold Superfamily Family Proteins Morten Nielsen,CBS, BioCentrum, DTU
Superfamilies • Proteins which are (remotely) evolutionarily related • Sequence similarity low • Share function • Share special structural features • Relationships between members of a superfamily may not be readily recognizable from the sequence alone Fold Superfamily Family Proteins Morten Nielsen,CBS, BioCentrum, DTU
Folds • >~50% secondary structure elements arranged in the same order in sequence and in 3D • No evolutionary relation Fold Superfamily Family Proteins Morten Nielsen,CBS, BioCentrum, DTU
Substitutions of Amino Acids Mutation rates between amino acids have dramatic differences!
Substitution Matrices BLOSUM matrices: • Start from BLOCKS database (curated, gap-free alignments) • Cluster sequences according to > X% identity • Calculate Aab: # of aligned a-b in distinct clusters, correcting by 1/mn, where m, n are the two cluster sizes • Estimate P(a) = (b Aab)/(c≤d Acd); P(a, b) = Aab/(c≤d Acd)
Probabilistic interpretation of an alignment An alignment is a hypothesis that the two sequences are related by evolution Goal: Produce the most likely alignment Assert the likelihood that the sequences are indeed related
A Pair HMM for alignments Model M 1 – 2 This model generates two sequences simultaneously Match/Mismatch state M: P(x, y) reflects substitution frequencies between pairs of amino acids Insertion states I, J: P(x), P(y) reflect frequencies of each amino acid : set so that 1/2 is avg. length before next gap :set so that 1/(1 – ) is avg. length of a gap M P(xi, yj) 1 – 1 – I P(xi) J P(yj) optional
A Pair HMM for unaligned sequences Model R Two sequences are independently generated from one another P(x, y | R) = P(x1)…P(xm) P(y1)…P(yn) = i P(xi) j P(yj) 1 1 J P(yj) I P(xi)
To compare ALIGNMENT vs. RANDOM hypothesis 1 – 2 Every pair of letters contributes: M • (1 – 2) P(xi, yj) when matched • P(xi) P(yj) when gapped R • P(xi) P(yj) in random model Focus on comparison of P(xi, yj) vs. P(xi) P(yj) M P(xi, yj) 1 – 1 – I P(xi) J P(yj) 1 1 J P(yj) I P(xi)