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To Do

To Do. Finish reading Chapter 3. Text homework for Chapter 3. Quiz #2 on Friday, February 12 Lon- Capa assignments #1, #2 Start Chapter 4 for next week. N 2 ( g ) + 3H 2 ( g )  2NH 3 ( g ). Method 1: Have vs. Need. Compare what you HAVE with what you NEED.

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To Do

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  1. To Do • Finish reading Chapter 3. • Text homework for Chapter 3. • Quiz #2 on Friday, February 12 • Lon-Capa assignments #1, #2 • Start Chapter 4 for next week.

  2. N2(g) + 3H2(g)  2NH3(g)

  3. Method 1: Have vs. Need • Compare what you HAVE with what you NEED. • The limiting reactant determines the amount of product. • The amount of leftover reactant is the difference between what you HAVE and what you NEED.

  4. Method 2: Maximum Product • Determine the maximum amount of product from each reactant. • The reactant which produces the least amount of product is the limiting reactant. • The least amount of product is the amount of product formed.

  5. Method 3: ICE Table • Set up ICE Table [Initial, Change, End]. • Amounts must be in terms of number of moles. • At least one reactant is completely used up (goes to zero at End). • Change row: same ratio as the balanced equation.

  6. Clicker Question How much ammonia (NH3) can be produced by reacting 6.0 mol of nitrogen gas with 6.0 mol of hydrogen gas? a) 2.0 mol b) 4.0 mol c) 6.0 mol d) 12.0 mol e) I don’t know

  7. Determine Number of Moles • Use mass and molar masses. [Chapter 3] • Use volume and concentration for solutions. [Chapter 4] • Use pressure, volume, and temperature for gases. [Chapter 5]

  8. Solids, Solutions, and Gases NaHCO3(s) + HC2H3O2(aq) → NaC2H3O2 (aq) + H2O(l) + CO2(g) Use the data to explain the relative sizes of the balloons.

  9. Solids, Solutions, and Gases NaHCO3(s) + HC2H3O2(aq) → NaC2H3O2 (aq) + H2O(l) + CO2(g) Determine the mass of left-over sodium bicarbonate in Trial #5.

  10. Problem Solving Approach • What are we trying to solve? That is “where are we going?” • What does this mean? • What do we know? That is, “where have we been?” • What procedures do we know? That is, “how do we get there?” Requires knowledge and understanding!

  11. A Question for You… A 5.000 g sample of copper reacts with oxygen in the air to form 5.629 g of an oxide of copper. Determine the name of the product.

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