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AVL Trees II

AVL Trees II. Implementation. AVL Tree ADT. A binary search tree in which the balance factor of each node is 0, 1, of -1. Basic Operations Construction, empty, search, and traverse are the same as for a BST. Insert a new item in such a way that the height-balanced property is maintained.

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AVL Trees II

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  1. AVL Trees II Implementation

  2. AVL Tree ADT • A binary search tree in which the balance factor of each node is 0, 1, of -1. • Basic Operations • Construction, empty, search, and traverse are the same as for a BST. • Insert a new item in such a way that the height-balanced property is maintained. • Delete a item in such a way that the height-balanced property is maintained. • Left for advanced course! • Discussed in Brozdek.

  3. AVL Trees • Class to represent AVL tree nodes • Includes new data member for the balance factor

  4. What do we need to know? • When we look at a tree on paper, it is fairly easy to determine if the tree has become unbalanced. • Also what to do to fix the problem. • When implementing the ADT, we have to work with local information. • What do we have available as we descend the tree to add a node and return? • What do we need to know at each node?

  5. Observations • When we add a node to an AVL tree, the parent node will either be a leaf or have a single child. • If the parent node is a leaf, its balance factor prior to the addition is 0. • After the addition, the balance factor absolute value will be 1. • Ancestor nodes’ balance factor may increase, decrease, or remain the same. • Rebalancing may or may not be necessary. • If the parent node has a single child, its absolute balance factor prior to the addition will be 1. • After the addition, it will be 0. • Ancestor nodes’ balance factors will not change. • Rebalancing will not be necessary.

  6. Observations Given that the tree was an admissible AVL tree before we added a node: • Adding a node always changes the balance factor of the parent of the new node. • Absolute value 0 to 1 or 1 to 0. • The parent node will never become unbalanced due to an addition. • The grandparent is the first node (going up the tree) that can become unbalanced due to an addition. • An ancestor further up the tree could be the first node to become unbalanced. • See addition of MA in previous presentation.

  7. When does a node become unbalanced? • A node will become unbalanced due to an addition if the following conditions are true: • It already had an balance factor of +1 or -1. • In searching for the point to do the addition we descended into its subtree that already had the greater height. • Left subtree if balance factor was +1. • Right subtree is balance factor was -1. • Adding the node increased the height of that subtree. • We need to know if adding a node to a subtree increased the height of the subtree.

  8. Did the subtree height increase? • We need to know if adding a node to a subtree increased the height of the subtree. • The (recursive) insert function must report back to its caller whether adding a new node increased the height of the subtree to which it was added. • At each step we can then determine if the node has become unbalanced. • Whether or not we need to do a rotation.

  9. When does a node become unbalanced? • Adding a node increased the height of the subtree at a node along the path from the new node back to the root if: • The addition increased the height of the subtree rooted at the parent of the new node. • We added the node to a leaf. • The addition increased the height of the subtree rooted at each intermediate node. • Balance factor at each intermediate node was 0 • If a node previously had a nonzero balance factor and adding the new node increased the height of its higher subtree, the addition made that node unbalanced.

  10. Rebalancing the Tree • If adding a node increased the height of a subtree and any node became unbalanced because of the increase, we will do a rotation at the nearest ancestor that became unbalanced. • The rotation reduces the height of the subtree rooted at that position. • Will ensure that the subtree at that position does not increase in height. • No further rotations will be needed.

  11. Rebalancing the Tree • We will use a recursive search to find the node at which to attach the new node. • Previously we used a loop. • When we find the place to attach the new node, after attaching it, return values saying • Whether or not the subtree height increased. • On which side the new node was added. • Required in order to determine if a double rotation is needed.

  12. Rebalancing the Tree • At each step in the sequence of recursive calls, report back the same information: • Did the subtree rooted at this position increase in height? • Which direction did we descend to do the addition?

  13. Rebalancing the Tree • At each node as we descend from the root • If the balance factor is nonzero • If we descended in the direction of our higher subtree • If the next node down reports back that the height of its subtree increased • This node has become unbalanced. • We must do a rotation at this node.

  14. Rebalancing the Tree • If we have to do a rotation • If the next node down reports that it descended in the same direction • Do a single rotation. • Else • Do a double rotation.

  15. Implementation • Download: • http://www.cse.usf.edu/~turnerr/Data_Structures/Downloads/2011_03_28_AVL_Tree/ File AVL_Tree_Demo.zip • Project contains: • AVL_BST.h Our most recent BST template updated to implement an AVL tree. • main.cpp Uses the AVL BST to replicate the states example from last class. • Extract, build, and run

  16. Adding RI, PA, DE

  17. Adding GA, OH

  18. Adding GA, OH

  19. Adding MA

  20. Adding MA

  21. Adding MA

  22. Adding IL, MI, IN

  23. Adding IL, MI, IN

  24. Adding IL, MI, IN

  25. Adding NY

  26. Adding NY

  27. Adding NY

  28. Adding VT

  29. Adding VT

  30. Adding TX, WY

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