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Learn how to write equations of lines in slope-intercept form using given points and slopes, and how to determine parallel and perpendicular lines.
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Write an equation of the line in slope- intercept form. STEP 1 Find the slope. Choose two points on the graph of the line, (0, 4) and (3, –2). m – 2 = = = Find the y-intercept. The line intersects the y-axis at the point (0, 4), so the y-intercept is 4. STEP 2 4 – (– 2) 6 0 – 3 – 3 EXAMPLE 1 Write an equation of a line from a graph SOLUTION
STEP 3 Write the equation. y mx + b = EXAMPLE 1 Write an equation of a line from a graph Use slope-intercept form. y = –2x + 4 Substitute – 2 for mand 4 for b.
STEP 1 Find the slope m. The slope of a line parallel to y = 2x –3 is the same as the given line, so the slope is 2. STEP 2 Find the y-intercept bby using m=2 and (x, y)=(– 1, 1). EXAMPLE 2 Write an equation of a parallel line Write an equation of the line passing through the point (– 1, 1) that is parallel to the line with the equation y= 2x–3. SOLUTION
y mx + b = EXAMPLE 2 Write an equation of a parallel line Use slope-intercept form. Substitute forx, y, and m. 1 = 2 (–1 ) + b 3 = b Solve for b. Because m = 2 and b = 3, an equation of the line is y = 2x+ 3.
STEP 1 Find the slope mof line j. Line khas a slope of – 2. – 2 m = – 1 The product of the slopes of lines is –1. m = 1 2 EXAMPLE 3 Write an equation of a perpendicular line Write an equation of the line jpassing through the point (2, 3) that is perpendicular to the line kwith the equation y = – 2x + 2. SOLUTION Divide each side by – 2.
mx + b y = ( 2 ) + b 3 = 1 1 2 2 EXAMPLE 3 Write an equation of a perpendicular line STEP 2 Find the y-intercept bby using m= and (x, y)=(2, 3). Use slope-intercept form. Substitute for x, y, and m. 2 = b Solve for b.
Because m = and b = 2, an equation of line j is y=x+ 2. You can check that the lines jand kare perpendicular by graphing, then using a protractor to measure one of the angles formed by the lines. 1 1 2 2 EXAMPLE 3 Write an equation of a perpendicular line
Write an equation of the line in the graph at the right. STEP 1 Find the slope of the line. 2 . m = = 3 1 – (– 1) Find the y-intercept. Since the line intersects the y-axis at the point (0, –1), so the y-intercept is –1. STEP 2 1 – 1 for Examples 1, 2 and 3 GUIDED PRACTICE SOLUTION
STEP 3 Write the equation. y mx + b = 2 x y = – 1 Substitute for mand –1 for b. 3 2 3 for Examples 1, 2, and 3 GUIDED PRACTICE Use slope-intercept form.
Write an equation of the line that passes through (– 2, 5) and (1, 2). STEP 1 Find the slope of the line. 5 – 2 3 m = = – 3 – 2 – 1 Find the y-intercept. Since the line intersects the y-axis at the point (– 2, 5) and (1, 2) , so the y-intercept is 3. STEP 2 for Examples 1, 2 and 3 GUIDED PRACTICE SOLUTION = –1
y mx + b = EXAMPLE 1 for Examples 1, 2 and 3 GUIDED PRACTICE STEP 3 Write the equation. Use slope-intercept form. y = –x + 3 Substitute –1 for mand 3 for b.
Write an equation of the line that passes through the point (1, 5) and is parallel to the line with the equation y=3x–5. Graph the lines to check that they are parallel. STEP 1 Find the slope of the line. The slope of the line parallel to y = 3x – 5 is the same as the given line. So , the slope is 3. Find the y-intercept b by using m= 3 and (x , y)= (1 , 5). STEP 2 for Examples 1, 2 and 3 GUIDED PRACTICE SOLUTION
y mx + b = for Examples 1, 2 and 3 GUIDED PRACTICE Use slope-intercept form. y = 3 x + 2 STEP 3 Graph the lines.
How do you know the lines x = 4 and y = 2 are perpendicular? x = 4 is a vertical line whiley = 2 is horizontal line. Hence x y. for Examples 1, 2 and 3 GUIDED PRACTICE SOLUTION