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Solubility-Product Constant

Solubility-Product Constant. Solubility-Product Constant. is an equilibrium expression for a chemical equation that represents the dissolving of an ionic compound K sp = The product of the concentration of a salt’s ions in a saturated solution, each raised to the appropriate power.

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Solubility-Product Constant

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  1. Solubility-Product Constant

  2. Solubility-Product Constant • is an equilibrium expression for a chemical equation that represents the dissolving of an ionic compound • Ksp = The product of the concentration of a salt’s ions in a saturated solution, each raised to the appropriate power. • A large Ksp means that the compound is very soluble (forward reaction is favored) • A small Ksp means the compound is not very soluble (reverse reaction is favored)

  3. Ksp Practice Problems

  4. Dissolving Problems • Ksp is a measure of solubility; it is not actual solubility (as in grams per liter). We can compute the how much will dissolve from the Ksp value. • Steps to determine how much will dissolve • Write the equation for the reaction • Write the Ksp expression • Get Ksp from the table • Take the appropriate root • Convert to grams/liter

  5. Practice Problems How many grams of MgCO3 can be dissolved in 1.00 L of water if at 50°C, the Ksp = 2.5x10-5? • Take the appropriate root • 2.5x10-5 = [Mg2+] [CO32-] • [Mg2+] = [CO32-] = 5.0x10-3M • Convert to grams/liter • (5.0x10-3mol/L)(84.32 g/mol) = • 0.42 g/L

  6. Practice Problems How many grams of FeS will dissolve per liter if at 44°, the Ksp = 3.7x10-19? • Take the appropriate root • 3.7x10-19 = [Fe3+] [S2-] • [Fe3+] = [S2-] = 6.1x10-10M • Convert to grams/liter • (6.1x10-10mol/L)(87.92 g/mol) = • 5.4x10-8 g/L

  7. Practice Problems • How many grams of AgBr can be dissolved in 2.00 L of water if at 20°C, the Ksp = 4.8x10-13? • How many grams of Ca(OH)2 will dissolve in one liter of water if at 15°C, the Ksp = 1.3x10-6?

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