1 / 10

Stoichiometry - House Method

Stoichiometry - House Method. 1. Start with a balanced chemical equation. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3. Stochiometry - House Method.

jemma
Download Presentation

Stoichiometry - House Method

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Stoichiometry - House Method 1. Start with a balanced chemical equation. Na2CO3 + Ca(OH)2 2 NaOH + CaCO3

  2. Stochiometry - House Method 2. Place the given information above the proper compounds in the equation; except for moles. Moles will be written below the proper compounds!! 120 g X g Na2CO3 + Ca(OH)2 2 NaOH + CaCO3

  3. Stochiometry - House Method 3. Draw a simple house around each compound used in the problem. Add moles to the downstairs of each house. 120 g X g Na2CO3 + Ca(OH)2 2 NaOH + CaCO3 mole mole

  4. Stochiometry - House Method 4. Draw arrows to show the path of the conversion from beginning to end. 120 g X g Na2CO3 + Ca(OH)2 2 NaOH + CaCO3 mole mole

  5. Stochiometry - House Method 5. Set up your factor label conversions in the direction of the arrows. 120 g X g Na2CO3 + Ca(OH)2 2 NaOH + CaCO3 mole mole 120 g Na2CO3X 1 mol Na2CO3X mol NaOHX 40.00 g NaOH= 1 105.99 g Na2CO3 mol Na2CO3 1 mol NaOH Notice that there are no numbers in front of the mol to mol conversion…YET !

  6. Stochiometry - House Method 6. The numbers in front of the mol to mol conversion are the addresses (coefficients) of the compounds. 120 g X g 1 Na2CO3 + Ca(OH)2 2 NaOH + CaCO3 1 mole mole 2 1 120 g Na2CO3X 1 mol Na2CO3X mol NaOHX 40.00 g NaOH= 1 105.99 g Na2CO3 mol Na2CO3 1 mol NaOH

  7. Stochiometry - House Method 7. Solve the math. 120 g X g Na2CO3 + Ca(OH)2 2 NaOH + CaCO3 mole mole 2 1 120 g Na2CO3X 1 mol Na2CO3X mol NaOHX 40.00 g NaOH= 1 105.99 g Na2CO3 mol Na2CO3 1 mol NaOH 91 g NaOH

  8. Stoichiometry- In Review….. -calc. of quantities in BALANCED chemical equations.

  9. Mole Ratio/ Mole Bridge - Must have balanced equation - Use coefficients from balanced equation - Used to get from one substance to another Set- Up: # mole of unknown substance #mole of given substance # of moles = Coeff. from balanced equation

  10. For Stoichiometry Problems (A Step-by-Step Guide!!!): 1. Balance the equation 2. Write given and unknowns with the houses. 3. If given is not in moles, convert to moles. 4. Do MOLE BRIDGE 5. If solving to moles, you're done!! 6. If solving to any other unit, do one more conversion to solve to the proper unit.

More Related