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Significant Figures. Significant Figure Rules . 1. All Nonzeros are significant. 523 g = 3 sig figs 4222 cm 3 = 4 sig figs. 2. All numbers between significant figures are significant. 4,404 g = 4 sig figs 9.005 mm = 4 sig figs 5,000,102 mg = 7 sig figs.
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1. All Nonzeros are significant. 523 g = 3 sig figs 4222 cm3= 4 sig figs
2. All numbers between significant figures are significant. 4,404 g = 4 sig figs 9.005 mm = 4 sig figs 5,000,102 mg = 7 sig figs
3. All final zeros past the decimal are significant. 9509.90 cm = 6 sig figs 52.000 km = 5 sig figs
4. Zeros used solely as placeholders are NOT significant. 42,000 L = 2 sig figs 42,000.00 L = 7 sig figs 0.000802 g = 3 sig figs
1. Find the part of the problem with the least number of sig figs. 142 m x 1552 m x 0.25 m = Which measurement has the least? 0.25 m only has 2 sig figs.
2. Round your answer so it has that number of sig figs. 142 m x 1552 m x 0.25 m = 55,096= 55,000
3. Units When multiplying, add the exponents. 142 m x 1552 m x 0.25 m = 55,000 m3 When dividing, subtract the exponents. 12 g3 ÷ 6 g = 2 g2 18 g ÷ 2 cm3 = 9 g/ cm3
1. Find the least accurate measurement in the problem. 14.3 g + 99 g + 40 g = 40 g is the least accurate measurement. It is rounded to the nearest 10
2. Make your answer match the least accurate measurement. 14.3 g + 99 g + 40 g = 153.3 g must be rounded to the nearest ten The answer is 150 g
More Examples 300 g - 193 g - 21.2 g = 85.8 Since 300g is the least accurate measurement, your answer must be rounded to the nearest 100. The answer is 100 g
Examples cont. 14.2 m + 12.36 m = 26.56 Since 14.2 is the least accurate measurement, the answer must be rounded to the nearest tenth. 26.6 m