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Learn about the syntax and semantics of Datalog, a rule-based language related to Prolog, for querying databases. Explore recursive queries and examples of Datalog queries.
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Database Design Dr. M.E. Fayad, Professor Computer Engineering Department, Room #283I College of Engineering San José State University One Washington Square San José, CA 95192-0180 http://www.engr.sjsu.edu/~fayad SJSU -- CmpE
Lesson 08: Datalog Queries 2 SJSU – CmpE --- M.E. Fayad
Lesson Objectives • Understand datalog langauge • Learn about: • Syntax of Datalog Rules • Datalog with Sets • Datalog with Abstract Data Types • Semantics • Recursive Datalog Queries 3 SJSU – CmpE --- M.E. Fayad
Datalog is a rule-based language that is related to Prolog Each rule is a statement has some points that belong to some relations and other points must belong to a defined relation. Each Datalog query contains a Datalog program and an input database. Datalog 4 SJSU – CmpE --- M.E. Fayad
Datalog query– a finite set of rules of the form: R0(x1,…,xk) :– R1(x1,1,…, x1,k1),..., Rn(xn,1,…, xn,kn) where each Ri is either an input or a defined relation name. including built-in relations such as +(x,y,z) which means x + y = z. (We normally use the latter syntax.) The preceding rule is read “R0 is true if R1 and .. and Rn are all true. head of the rule – R0 body of the rule– R1,…,Rn Datalog Queries: Syntax 5 SJSU – CmpE --- M.E. Fayad
[4.1.1] See Taxrecord and Taxtable (Page 8) Find the SSN and the tax. Tax_Due(s, t) :– Taxrecord(s, w, i, c), Taxtable(inc, t), w+i+c = inc. Requires one rule where Taxrecord and Taxtable are input database relations and Tax_Due is the only defined relation. Datalog Queries: Syntax – Example (1) 6 SJSU – CmpE --- M.E. Fayad
[4.1.2] Suppose that relation Street (n, x, y) contains all combinations of street name n and locations (x, y) such that a location belongs to the street. Find the streets that can be reached from (x0,y0). Reach(n) :– Street(n, x0, y0). -- Rule 1 This rule says that street n is reachable if it contains the initial point. Reach(n) :– Reach(m), Street(m, x, y), Street(n, x, y). – Rule 2 This rule says that if m is reachable and m and n intersect on some point, than n is also reachable. Datalog Queries: Syntax – Example (2) 7 SJSU – CmpE --- M.E. Fayad
[4.1.3] Find the time to travel from x to y. Travel(x, y, t) :– Go(x, 0, y, t). Travel(x, y, t) :– Travel(x, z, t2), Go(z, t2, y, t). The head defines the travel(x, y, t) relation, which is true if it is possible to travel from city x to city y in time t. Datalog Queries: Syntax – Example (3) 8 SJSU – CmpE --- M.E. Fayad
[4.1.8] Find town points covered by a radio station or find every place in town that can e reached by at least one broadcast station. A kind of “map overlay problem” In this kind of problems, the scales and the points of the maps to be overlayed are not the same. Suppose that a relation Parameters(ID, Scale, X0, Y0) records for each map it scale and point of origin. Datalog Queries: Syntax – Example (4) 9 SJSU – CmpE --- M.E. Fayad
Suppose a town map where each point corresponds to a half kilometer, and in the broadcast map each point corresponds to a kilometer and the points of origin are the same for both maps. Then (1, 1, 0, 0), (2, 1, 0, 0), (3, 1, 0, 0), and (San Jose, 0.5, 0, 0) would be parameters relation. Datalog Queries: Syntax – Example (4) 10 SJSU – CmpE --- M.E. Fayad
We can find the points in town that are covered using the following query Covered(x2, y2) :– Broadcast(n, x, y), Town(t, x2, y2), Parameters(n, s, blat, blong), Parameters(t, s2, tlat, tlong), x2 = s/ s2 x + (tlat – blat), y2 = s/ s2 y + (tlong – blong). This query at first scales up and shift every point (x, y) in the broadcast map n to match the scale and point of the town map. If it corresponds to a point (x2, y2) in the town map, then it is added to relation Covered. Datalog Queries: Syntax – Example (4) 11 SJSU – CmpE --- M.E. Fayad
Datalog Queries: Syntax – Example (4) 12 SJSU – CmpE --- M.E. Fayad
We think of the domain of each attribute is a set. We can represent an undirected graph in two relations: Vertices and Edge (X1, X2) that contains a pair of singleton sets of city names iff there is an edge between them. For example: Edge ({San Jose}, {San Francisco}) would be one tuple in the Edge relation. Datalog with Sets (1) 13 SJSU – CmpE --- M.E. Fayad
Hamiltonian Cycle in An Undirected graph is a path that starts and ends with the same vertex and goes through each vertex exactly once. Assume Start (X) is an input relation where X is a singleton set containing the name of starting vertex of the cycle. Find a Hamiltonian Cycle where a set of vertices A not yet visited. Datalog with Sets (2) 14 SJSU – CmpE --- M.E. Fayad
Example: Hamiltonian Cycle Input: Vertices(S) where S is a set of vertices Edge ({c1}, {c2}) if there is an edge from c1 to c2 Start({c}) where c is start city name Output: Path ({c}, B) if there is a path from c that uses all vertices except those in B. Hamiltonian ({c}) if there is a Hamiltonian path. Datalog with Sets (3) 15 SJSU – CmpE --- M.E. Fayad
Base case – Path is a single vertex. All vertices except the start vertex is unvisited. Path(X1, B) :– Vertices(A), Start(X1), B = A \ X1. Recursion – a path to X1 with B unvisited exists if there is Path(X1, B) : – Path(X2, A), a path to X2 with A unvisited Edge(X2, X1), and an edge from X2 to X1, X1 A, which is unvisited, and B = A \ X1. B is A minus X1 Datalog with Sets (4) 16 SJSU – CmpE --- M.E. Fayad
If there is a path from start to X2 that visits all vertices and an edge from X2 to start, then there is a Hamiltonian cycle. Hamiltonian(X1) :– Path(X2, ), Edge(X2, X1), Start(X1). Datalog with Sets (5) 17 SJSU – CmpE --- M.E. Fayad
The domain of each abstract data type ranges over some set S. For example, in the Street example, the Extend attribute was an abstract data type that ranged over sets of points in the plane over R2 where R is the set of real numbers. With each abstract data type only certain operations are allowed and can be used with the query. Datalog with Abstract Data Types (1) 18 SJSU – CmpE --- M.E. Fayad
For an abstract data type that ranges over points in the plane, all the basic set operations can be allowed: equality (=) containment intersection union U Datalog with Abstract Data Types (2) 19 SJSU – CmpE --- M.E. Fayad
Example: Streets(Name, Extent) where extent is a set of 2D points. Let (x0, y0) be a start location. Express the reach relation: Reach(n) :– Street(n, Extent), {(x0,y0)} Extent. Reach(n) :– Reach(m), Street(m, S1), Street(n, S2), S1 S2 Datalog with Abstract Data Types (3) 20 SJSU – CmpE --- M.E. Fayad
Rule instantiation – substitution of variables by constants ⊢Q,I R(a1,…..ak)– R(a1,….ak) has a proof using query Q and input database I, iff R represents input relation r and (a1,….ak) r , or There is some rule and instantiation R(a1,…,ak):–R1(a1,1,…,a1,k1),…, Rn(an,1,…, an, kn). where ⊢Q,I Ri(ai,1,…,ai,ki) for each 1 i n . Semantics (1) 21 SJSU – CmpE --- M.E. Fayad
Reach(Vine) Reach(Vine) :– Street(Vine, 5, 2). -- from point (5, 2) Reach(Bear) Reach(Bear) :– Reach(Vine), Street(Vine, 5, 12), Street(Bear, 5, 12). -- (5, 12) is the intersection point Reach(Hare) Reach(Hare) :– Reach(Bear), Street(Bear, 8, 13), Street(Hare, 8, 13). Semantics: Example (1) 22 SJSU – CmpE --- M.E. Fayad
Example: By the input database (Figure 1.2): Go(Omaha, 0, Lincoln, 60) Go(Lincoln, 60, Kansas_City, 210) Go(Kansas_City, 210, Des_Moines, 390) Go(Des_Moines, 390, Chicago, 990) We also have: Travel(Omaha, Lincoln, 60) Travel(Omaha, Lincoln, 60):- Go(Omaha, 0, Lincoln, 60) Travel(Omaha, Kansas_City, 210) Travel(Omaha,Kansas_City,210):- Travel(Omaha,Lincoln,60), Go(Lincoln,60,Kansas_City,210). Semantics: Example (2) 23 SJSU – CmpE --- M.E. Fayad
Proof Trees (1) 24 SJSU – CmpE --- M.E. Fayad
Proof-based semantics – derived relations are the set of tuples that can be proven. Fixed point semantics – an interpretation of the derived relations such that nothing new can be proven. Least fixed point semantics – smallest possible FP semantics. Proof-based semantics = Least fixed point semantics Proof Trees (2) 25 SJSU – CmpE --- M.E. Fayad
T/F Datalog is an extension of SQL. Datalog is a rule-based language and it is related to Prolog. A fact is the same thing as a tuple in a relation or a row in an SQL table. A rule is a way to derive new facts, that is, a rule is (part of) a query. Datalog is more powerful than SQL3 since it permits a more general form of recursion. Discuss: Since we can do selection, projection, and join in Datalog just like in SQL and relational algebra, is there any difference among the three? Discussion Questions 26 SJSU – CmpE --- M.E. Fayad