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Lesson on using Theorem 23 to prove angles are right angles. Includes proofs with supplementary and congruent angles. Shows midpoint properties and rhombus proofs. Concepts like SSS, CPCTC, and reflexive property are applied.
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Right Angle Theorem Lesson 4.3
Theorem 23:If two angles are both supplementary and congruent, then they are right angles. 2 1 Given: 1 2 Prove: 1 and 2 are right angles.
Paragraph Proof: Since 1 and 2 form a straight angle, they are supplementary.Therefore, m1 + m2 = 180°. Since 1 and 2 are congruent, we can use substitution to get the equation: m1 + m2 = 180° or m1 = 90°. Thus, 1 is a right angle and so is 2.
Given: Circle P S is the midpoint of QR P Prove: PS QR Τ S Q R • Circle P • Draw PQ and PR • PQ PR • S mdpt QR • QS RS • PS PS • PSQ PSR • PSQ PSR • QSR is a straight • PSQ & PSR are supp. • PSQ and PSR are rt s • PS QR • Given • Two points determine a seg. • Radii of a circle are . • Given • A mdpt divides a segment into 2 segs. • Reflexive property. • SSS • CPCTC • Assumed from diagram. • 2 s that make a straight are supp. • If 2 s are both supp and , they are rt s. • If 2 lines intersect to form rt s, they are . Τ Τ
Given: ABCD is a rhombus AB BC CD AD Prove: AC BD A D 5 4 7 2 E 1 Τ 3 6 8 B C Hint: Draw and label shape! • Given • Reflexive Property • SSS • CPCTC • If then • ASA • CPCTC • Assumed from diagram. • 2 s that make a straight are supp. • If 2 s are both supp and they are rt s. • If 2 lines intersect and form rt s, they are . • AB BC CD AD • AC AC • BAC DAC • 7 5 • 3 4 • ABE ADE • 1 2 • BED is a straight • 1 & 2 are supp. • 1 and 2 are rt s • AC BD Τ Τ