1 / 16

AF1.1 Write and solve one-step linear equations in one variable.

California Standards. AF1.1 Write and solve one-step linear equations in one variable. The slowest time in a 40-yard dash was 3.84 seconds slower than the fastest time of 7.2 seconds. You can write an equation to represent this situation.

jlamberth
Download Presentation

AF1.1 Write and solve one-step linear equations in one variable.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. California Standards AF1.1 Write and solve one-step linear equations in one variable.

  2. The slowest time in a 40-yard dash was 3.84 seconds slower than the fastest time of 7.2 seconds. You can write an equation to represent this situation. The slowest time s minus 3.84 is equal to the fastest time of 7.2 seconds. s – 3.84 = 7.2

  3. Remember! You can solve an equation by performing the same operation on both sides of the equation to isolate the variable.

  4. Example 1: Solving Equations by Adding or Subtracting Solve. A. n – 2.75 = 8.3 n – 2.75 = 8.30 Since 2.75 is subtracted from n, add 2.75 to both sides. + 2.75 + 2.75 n = 11.05 B. a + 32.66 = 42 a + 32.66 = 42.00 Since 32.66 is added to a, subtract 32.66 from both sides. –32.66 –32.66 a 9.34 =

  5. Example 2A: Solving Equations by Multiplying and Dividing Solve. x = 5.4 4.8 x = 5.4 4.8 x Since x is divided by 4.8, multiply both sides by 4.8. 4.8  4.8 5.4 = 4.8 x = 25.92

  6. Example 2B: Solving Equations by Multiplying and Dividing Solve. 9 = 3.6d 9 = 3.6d 9 3.6d Since d is multiplied by 3.6, divide both sides by 3.6. = 3.6 3.6 9 d = Think: 9 ÷ 3.6 = 90 ÷ 36 3.6 2.5 = d

  7. 1 Understand the Problem Example 3: Problem Solving Application A board-game box is 2.5 inches tall.A toy store has shelving measuring 15 inches vertically in which to store the boxes. How many boxes can be stacked in the space? Rewrite the question as a statement. Find the number of boxes that can be placed on the shelf. List the important information: • Each board-game box is 2.5 inches tall. • The store has shelving space measuring 15 inches.

  8. Make a Plan 2 Example 3 Continued The total height of the boxes is equal to the height of one box times the number of boxes. Since you know how much vertical space the shelf has, you can write an equation with b being the number of boxes. 2.5b = 15

  9. 3 Solve Example 3 Continued 2.5b = 15 2.5b = 15 Since b is multiplied by 2.5, divide both sides by 2.5. 2.5 2.5 b = 6 6 boxes can be stacked in the space.

  10. 4 Additional Example 3 Continued Look Back You can round 2.5 to 3 and estimate how many boxes will fit on the shelf. 15 ÷ 3 = 5 So 6 boxes is a reasonable answer.

  11. Check It Out! Example 1 Solve. a + 27.51 = 36 a + 27.51 = 36.00 Since 27.51 is added to a, subtract 27.51 from both sides. –27.51 –27.51 a = 8.49

  12. Check It Out! Example 2 Solve. 9 = 2.5d 9 = 2.5d 9 2.5d Since d is multiplied by 2.5, divide both sides by 2.5. = 2.5 2.5 9 d = Think: 9 ÷ 2.5 = 90 ÷ 25 2.5 3.6 = d

  13. 1 Understand the Problem Check It Out! Example 3 A canned good is 4.5 inches tall.A grocery store has shelving measuring 18 inches vertically in which to store the cans. How many cans can be stacked in the space? Rewrite the question as a statement. Find the number of cans that can be placed on the shelf. List the important information: • Each can is 4.5 inches tall. • The store has shelving space measuring 18 inches.

  14. Make a Plan 2 Check It Out! Example 3 Continued The total height of the cans is equal to the height of one can times the number of cans. Since you know how much vertical space the shelf has, you can write an equation with c being the number of cans. 4.5c = 18

  15. 3 Solve Check It Out! Example 3 Continued 4.5c = 18 4.5c = 18 Since c is multiplied by 4.5, divide both sides by 4.5. 4.5 4.5 c = 4 4 cans can be stacked in the space.

  16. 4 Check It Out! Example 3 Continued Look Back You can round 4.5 to 5 and 18 to 20 estimate how many cans will fit on the shelf. 20 ÷ 5 = 4 So 4 cans is a reasonable answer.

More Related