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Lecture 30. To do :. Chapter 21 Examine two wave superposition (- w t and + w t) Examine two wave superposition (- w 1 t and - w 2 t) Review for final (Location: CHEM 1351, 7:45 am ) Tomorrow: Review session, 2103 CH at 12:05 PM. Last Assignment HW13, Due Friday, May 7 th , 11:59 PM.
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Lecture 30 To do : • Chapter 21 • Examine two wave superposition (-wt and +wt) • Examine two wave superposition (-w1t and -w2t) Review for final (Location: CHEM 1351, 7:45 am) Tomorrow: Review session, 2103 CH at 12:05 PM • Last Assignment • HW13, Due Friday, May 7th , 11:59 PM
Standing waves • Waves traveling in opposite direction “interfere” with each other. If the conditions are right, same k (2p/l) & w, the superposition generates a standing wave: DRight(x,t)= a sin( kx-wt ) DLeft(x,t)= a sin( kx+wt ) Energy flow in a standing wave is stationary, it “stands” in place. Standing waves have nodes and antinodes Anti-nodes D(x,t)= DL(x,t) + DR(x,t) D(x,t)= 2 a sin(kx) cos(wt) The outer curve is the amplitude function A(x) = ±2 a sin(kx) when wt = pn n = 0,1,2,… k = wave number = 2π/λ Nodes
Standing waves on a string • Longest wavelength allowed: ½ of the full wave Fundamental: l/2 = L l = 2 L Recall v = fl Overtones m > 1
Violin, viola, cello, string bass Guitars Ukuleles Mandolins Banjos Vibrating Strings- Superposition Principle D(x,0) Antinode D(0,t)
Standing waves in a pipe Open end: Mustbe a displacement antinode (pressure minimum) Closed end: Must be a displacement node (pressure maximum) Blue curves are displacement oscillations. Red curves, pressure. Fundamental: l/2l/2 l/4
Combining Waves Fourier Synthesis
DESTRUCTIVEINTERFERENCE CONSTRUCTIVEINTERFERENCE Superposition & Interference • Consider two harmonic waves A and B meet at t=0. • They have same amplitudes and phase, but 2 = 1.15 x 1. • The displacement versus time for each is shown below: A(1t) B(2t) C(t) =A(t)+B(t)
A(1t) B(2t) t Tbeat C(t)=A(t)+B(t) Superposition & Interference • Consider A + B,[Recall cos u + cos v = 2 cos((u-v)/2) cos((u+v)/2)] yA(x,t)=A cos(k1x–2p f1t)yB(x,t)=A cos(k2x–2p f2t) Let x=0, y=yA+yB = 2A cos[2p (f1 – f2) t/2] cos[2p (f1 + f2) t/2] and |f1 – f2| ≡ fbeat = = 1 / Tbeat f average≡ (f1 + f2)/2
Exercise Superposition • The traces below show beats that occur when two different pairs of waves are added (the time axes are the same). • For which of the two is the difference in frequency of the original waves greater? Pair 1 Pair 2 The frequency difference was the same for both pairs of waves. Need more information.
A(1t) B(2t) t Tbeat C(t)=A(t)+B(t) Superposition & Interference • Consider A + B,[Recall cos u + cos v = 2 cos((u-v)/2) cos((u+v)/2)] yA(x,t)=A cos(k1x–2p f1t)yB(x,t)=A cos(k2x–2p f2t) Let x=0, y = yA + yB = 2A cos[2p (f1 – f2)t/2] cos[2p (f1 + f2)t/2] and |f1 – f2| ≡ fbeat = = 1 / Tbeat f average≡ (f1 + f2)/2
Review • Final is “semi” cumulative • Early material, more qualitative (i.e., conceptual) • Later material, more quantitative (but will employ major results from early on). • 25-30% will be multiple choice • Remainder will be short answer with the focus on thermodynamics, heat engines, wave motion and wave superposition
Exercise Superposition • The traces below show beats that occur when two different pairs of waves are added (the time axes are the same). • For which of the two is the difference in frequency of the original waves greater? Pair 1 Pair 2 The frequency difference was the same for both pairs of waves. Need more information.
Organ Pipe Example A 0.9 m organ pipe (open at both ends) is measured to have it’s first harmonic (i.e., its fundamental) at a frequency of 382 Hz. What is the speed of sound (refers to energy transfer) in this pipe? L=0.9 m f = 382 Hzandf l = vwith l = 2 L / m(m = 1) v = 382 x 2(0.9) m v = 687 m/s
Standing Wave Question • What happens to the fundamental frequency of a pipe, if the air (v =300 m/s) is replaced by helium (v = 900 m/s)? Recall: f l = v (A) Increases (B) Same (C) Decreases
Chapter 6 Chapter 7
Chapter 9 Chapter 8
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Hooke’s Law Springs and a Restoring Force • Key fact: w = (k / m)½ is general result where k reflects a constant of the linear restoring force and m is the inertial response (e.g., the “physical pendulum” where w = (k / I)½
Simple Harmonic Motion Maximum potential energy Maximum kinetic energy
Resonance and damping • Energy transfer is optimal when the driving force varies at the resonant frequency. • Types of motion • Undamped • Underdamped • Critically damped • Overdamped
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T can change! Work, Pressure, Volume, Heat